sample estimate

CHAPTER II

MATERIAL QUANTITY AND COSTCOMPUTATION

E. BEAMS

Forms

Lateral Perimeter = 2d + b + 0.10 = 2(0.30) + 0.20 + 0.10 = 0.90

For RB1: length = (4 18 beams) + (1.5 1 beam) + (3 1 beam) = 76.5

For RB2: length = (5 3 beams) + (4.5 1 beam) = 19.5 For CB: length = (1 2 beams) = 2.0

Total length: 76.5 + 19.5 + 2.0 = 98.0

Area = Perimeter Length = 0.90 98.0 = 88.20

# of Plywood:

Order: say 31 pcs. 1/4” 4’ 8’ plywood

Refer to Table 5-2 by FajardoWood frame using 2” 2” Lumber

Order: 31pcs. 25.06 = 767.46 bd.ft

Nails

For beam forms:Refer to Table 8-10 by Fajardo

Area = 88.20 Using 2d CWN Nails @ 30cm o.c.

Order: 88.20 0.033 = 2.91 , say 3 2d Nails

For wood frame (Velasco)

Order: say 10.5 8d Nails

For beam scaffolding:

Total length = 98.0Refer to Table 8-10 by Fajardo

Using 20d CWN Nails @ 30cm o.c.Order: 98.0 0.73 = 71.54 , say 72 20d Nails

ScaffoldingsTotal length = 98.0Refer to Table 5-3 by FajardoOrder: Vertical Support (2” 2” Lumber)= 98 4.0 = 392.0 bd.ft

Horizontal Support (2” 2” Lumber) = 98 4.7 = 460.60 bd.ft

Steel Requirements

Main Reinforcement

For RB1: L = 474.92For RB2: L = 140.4

For CB: L = 14

Total length: 474.92 + 140.4 + 14 = 629.32

Using 6m long steel bars

Order: say 105 pcs. 12mm F steel bars @ 6

long

Stirrups

Spacing: based from the specificationLength per stirrup: 0.85

For RB1:# of stirrups: for 4 length beam:32 per beam

for 3 length beam:26 per beamfor 1.5 length beam:14 per beam

Total # of stirrups: (18 x 33) + (1x 26) + (1x14) = 634 stirrups

For RB2:# of stirrups: for 5 length beam:42 per beam

for 4.5 length beam:22 per beam Total # of stirrups: (3 x 42) + (1x 22) = 148 stirrups

For CB:# of stirrups: for 1 length beam:11 per beamTotal # of stirrups: (2 x 11) = 22 stirrups

Total # of stirrups for all beams: 634 + 148 + 22 = 804 stirrups Using 6m long steel bars

Order: 804 stirrups x 0.85 = , say 114pcs. 10mm F

steel bars @ 6 long

Tie Wire

For RB1:# of intersection = 634 stirrups 6 bars = 3,804 ties

For RB2:# of intersection = 148 stirrups 7 bars = 1,036ties

For CB:# of intersection = 22 stirrups 8 = 176 ties

Total # of intersection: 3,804 + 1,036 + 176 = 5,016 ties

Using 30cm long ties5,016 ties 0.3 = 1,504.8

Converting to

Order: say 29 #16 G.I. tie wire

Concrete Mix

For RB1:Length = 76.5Volume = 76.5 0.30 0.20 = 4.59

For RB2:

Length = 19.5Volume = 19.5 0.30 0.20 = 1.17

For CB:

Length = 2.0Volume = 2.0 0.30 0.20 = 0.12

Total Volume = 4.59 1.17 0.12 = 5.91

Refer to Table 1-2 by FajardoUsing 40 cement Class A Mixture

Order: Cement: 5.88 9.0 = 52.92, say 53 bagsSand: 5.88 0.5 = 2.94, say 3Gravel: 5.88 1.0 = 5.88, say 6

Summary: Material Cost and Quantity

MATERIALS QUANTITYUNIT PRICE

(Php)COST(Php)

Premium Cement 53 bags 225/bags 11,925.00 Washed Sand 3m3 800/ m3 2,400.00Washed Gravel, ¾’’ 6 m3 1,200/m3 7,200.0012mm x 6.00m DRB 105 pcs 185/pc 19,425.0010mm x 6.00m DRB 114 pcs 125/pc 14,250.00# 16 G.I. tie wire 29 kg 80/kg 2,320.00CWN # 1’’ 3 kg 80/kg 240.00CWN # 2½’’ 10.5 kg 60/kg 630.00CWN # 4’’ 72 kg 55/kg 3,960.00¼’’ x 4’ x 8’ ordinary plywood 31 pcs 260/pc 8,060.002’’x 2’’x10’ red lauan 852.60 bd.ft. 12/bd.ft. 10,231.20

TOTAL MATERIAL COST FOR BEAM = 80,641.20

CHAPTER III

MAN POWER, DURATION AND LABOR COSTCOMPUTATION

E. Beam Works

Reinforcements

rate = 0.09 MH/kgs

reinforcements: 105 pcs 12 mm Ø bars ,factor 5.33114 pcs 10 mm Ø bars ,factor 3.7

weight of reinforcements = factor x number of reinforcementsweight of reinforcements = (105pcs x 5.33) +(114pcs x 3.70) =

981.45 MH = 981.45 x 0.09 MH/kgs = 88.3305MH

MD = 11.04 MD

ConcretingTotal Volume = 5.91rate = 0.25 m³/MD

MD = 23.64 MD

Forms and Scaffoldings

Formsarea = 88.20 m²rate = 3.12 MH/m²

carpenter: 1.90 MH/m²laborer: 1.22 MH/m²

MH = 88.20 m² x 3.12 MH/kgs = 275.184MH

MD = 34.4 MD

Scaffoldingsections: say 37 sectionsrate = 0.7MH/section

MH = 37 sections x 0.7 MH/section = 25.90 MH

MD = 3.49 MD

Erecting forms and scaffoldings

rate = 1.86m2/MH

MH = MH

MD = 5.92 MD

Total M-D for forms and scaffolding: 34.4 + 3.49 + 5.92 = 43.81 MD

Total MD for beam works: 11.04 + 23.64 + 43.81 = 78.49, say 79 MD

Manpower : 8 men(2 steel fixers, 2 masons,2 carpenters, 2 laborers)

Duration = 9.81, say 10 days

Labor costSteel fixers: 2 x 10 days x 256/day = 5,120.00 masons: 2 x 10 days x 300/day = 6,000.00 carpenters: 2 x 10 days x 300/day = 6,000.00 laborers: 2 x 10 days x 200/day = 4,000.00

Total labor cost = 21,120.00 Php

DIRECT COST FOR BEAM:

MATERIAL COST = 80,641.20 PhpLABOR COST = 21,120.00 PhpTotal direct cost = 101,761.20 Ph

J. REMOVAL OF BEAM FORMS AND SCAFFOLDING

rate = 1.86m2/MH

MH = MH

MD = 5.92, say 6 MD

Manpower : 2 men(1 carpenters, 1 laborer)

Duration = 3 days

Labor cost

carpenters: 1 x 3 days x 300/day = 900.00 laborers: 1 x 3 days x 200/day = 600.00

Total labor cost = 1,500.00 Php

MATERIAL QUANTITY AND COSTCOMPUTATION

V. FLOORING

Reinforcement BarRefer to FajardoSpacing .60m O.C.

1. Bed Room14m + 1 = 7.67 pcs x 2 = 15.34 pcs0.6

say 16 pcs 10mm F steel bar, 4 long cut bars.

2. Bed Room2 4m + 1 = 7.67 pcs x 2 = 15.34 pcs0.6


3. Mr. Bed Room4m + 1 = 7.67 pcs x 2 = 15.34 pcs0.6


4. Living AreaShort direction:

4m + 1 = 7.67 pcs 0.6

say 8 pcs 10mm F steel bar, 5 long cut bars. Long direction:

5m + 1 = 7.67 pcs 0.6


5. Dining AreaShort direction:

4m + 1 = 7.67 pcs 0.6


5m + 1 = 7.67 pcs 0.6


6. Kitchen Short direction:

4m + 1 = 7.67 pcs 0.6


Long direction:5m + 1 = 7.67 pcs 0.6


7. Laundry AreaShort direction:

4m + 1 = 7.67 pcs 0.6


5m + 1 = 7.67 pcs 0.6


8. Living Area Short direction:

4m + 1 = 7.67 pcs 0.6


6m + 1 = 11 pcs 0.6


9. GarageShort direction:

3m + 1 = 6 pcs 0.6


5m + 1 = 9.33 pcs 0.6


10. 2-C.R.Short direction:

2m + 1 = 4.30 pcs 0.6


3m + 1 = 6 pcs 0.6


ORDER:

Total length = 638m, 10mm F steel bar

638m = 106.33 pcs 6m

say 107 pcs, 10mm F steel bar, 6m long

Tie WireRefer to FajardoSpacing = 60cm O.CUsing 30cm tie wireTotal number of junction = 710

710x0.30m = 210m x 1kg = 3.96kg, say 4kg 53m

FLOOR SLABThickness of slab = 0.10

Area ( ) VolumeBed Room1 16.60 1.66Bed Room2 16.00 1.6Mr. Bed Room 16.60 1.66Living Area 23.20 2.32Dining Area 19.30 1.93CR1 5.75 0.575CR2 5.75 0.575Kitchen 20.00 2.00Garage 15.00 1.5Laundry Area 20.00 2.00Porch 3.24 0.324

= 161.44 = 16.144

Concrete MixtureRefer to Table 1-3 by FajardoUsing 40 cement Class A Mixture

Cement: 16.144 9 = 145.296, say 146bagsSand: 16.144 0.5 = 8.072, say 8.5Gravel: 16.144 1 = 16.144, say 16.5



(Php)COST(Php)

Premium Cement 146 bags 225/bags 32,850.00 Washed Sand 8.5m3 800/ m3 6,800.00Washed Gravel, ¾’’ 6 m3 1,200/m3 19,800.006m-10mm F steel bar 107 pcs 125/pcs 13,375.00#16 GI Wire 4kg 80/kg 320.00

TOTAL MATERIAL COST FOR FLOORING = 73,145.00


V. FLOORING

STEEL WORKS107pcs, 6m- 10mm F temp. Bar

107pcs = 395.9KgsRate: 9man Hour/100Kgs

MD = 395.9 Kgs x (9mHour/100Kgs) = 4.454 MDays

Duration: 2 men (1 mason, 1labor) 3 Days

CONCRETINGTotal Volume = 16.144rate = 2 men pour 0.84m³/Day

MD = 16.144 = 38.44 MDays (0.84 m³/2mD)

Duration: 6 men (2 mason, 3labor) 7Days

Labor costSteel fixers: 2 x 9 days x 256/day = 5,400.00 masons: 2 x 9 days x 300/day = 4,608.00 Laborers: 1 x 9 days x 256/day = 1,800.00

______________ TOTAL LABOR COST = 11,808.00 Php.

DIRECT COST FOR SLAB:

MATERIAL COST = 73,145.00 PhpLABOR COST = 11,808.00 Php

Total direct cost = 84,953.00 Php

X. Tile Works

Refer to table 7-1 (ESTEMATE BY FAJARDO)

Using 25cmx25cm ceramic floor tiles

( Area m2 )Bed Room1 16.6 Bed Room2 16 Mr. Bed Room 16.6 Living Area 22.50 Dining Area 19.30 Kitchen 20 Porch 3

= 114

ORDER :

NO. OF PCS = x 16 pcs/ m2 = 114 m2 x 16 pcs/ m2

= 1824 pcs

ADDING 5% DUE TO BREAKAGE

TOTAL NO. OF PCS. = 1824 + 5%( 1824 ) = 1915.2 PCS.Say 1916 pcs, 25cmx25cm ceramic floor tiles

QUANTITY OF CEMENT AND FILLER PASTE

CEMENT = 114 (0.086) = 9.084 BagsWHITE CEMENT = 114 (0.50) = 57KgsTILE ADHESIVE = 114 (0.11) = 12.54 Bags

FLOOR AREA OF 2 C.R

Using 20cmx20cm ceramic floor tiles

TOTAL AREA = 11.50 m2

NO. OF PCS = x 25pcs/m2

= 11.50 m2 x25pcs/m2

= 287.75 pcs

ADDING 5% DUE TO BREAKAGE

TOTAL NO. OF PCS. = 287.75 + 5%( 287.75 ) = 302. 14 pcs

Say 303 pcs, 20cmx20cm ceramic floor tiles

QUANTITY OF CEMENT AND FILLER PASTE

CEMENT = 11.50 (0.086) = 1 BagsWHITE CEMENT = 11.50 (0.50) = 5.76KgsTILE ADHESIVE = 11.50 (0.11) = 1.265 Bags

FLOOR AREA OF LAUNDRY

Using Crazy-cut stone TOTAL AREA = 20 m2 NO. OF PCS = x pcs/m2

= 20 m2 x1pcs/m2

= 20 pcs/m2


MATERIALS QUANTITYUNIT

PRICE(Php)

COST(Php)

Premium Cement 17Bags 225/bags 3,825.00 Washed Sand 0.5m3 800/ m3 400.00White Cement 32 (2kg/bag) 90/Bag 2,880.00

Tile adhesive17

(25Kg/Bag)245/Bag 3,430.00

25cmx25cm ceramic floor tiles

1916 pcs 16/pcs 30,656.00

20cmx20cm ceramic floor tiles

303 pcs 12/pcs 3,636.00

2.4 Tile trim 2 80/pcs 160.00Cut stone 20 145/ m2 2,900.00

TOTAL MATERIAL COST FOR TILE WORKS = 47,887.00

X. TILE WORKS

Total NO. of tiles = 2219 pcsRate: 2 men lay 72 pcs/Day

MD= 2219 pcs = 61.64 MDays (72pcs/2men)

Crazy-cut stone= 20m2

Rate: o.1905 mDay/ m2

20 m2 x 0.1905 mDay/m2 = 3.81 MDays

Duration: 6 men (4 Mason, 2 Labor) 11 Days

Labor costMasons: 4 x 11days x 300/day = 13,200.00 Laborers: 2 x 10 days x 256/ = 4,400.00 ___________________

TOTAL LABOR COST = 17,600.00 Php.

DIRECT COST FOR TILES:

MATERIAL COST = 47,887.00 Php.LABOR COST = 17,600.00 Php.Total direct cost = 65,487.00 Php.

L. WALLINGThickness = 0.10m

Total length =80.50m Interior wall: 28.50m Exterior wall: 52.0m

Total height of wall = 4.0m3.5m + 0.40m + 0.10m

Total wall area = 332 m2

4.0 x 80.50m

Total window area = 26.52m2

O6- T&B = (0.60x0.50)2 = 0.60m2

O3- kitchen = (1.6x0.90) =1.44m2

04- kitchen = (2.40 x0.90) = 2.16 m2

O5- kitchen = (0.80x0.90) = 0.72 m2 01- Living = (2.0x1.2)2 =4.80 m2

02- Living = (0.50x1.6) = 2.40 m2

01-BR = (2x1.2)6 =14.4 m2

Total door area = 13.65m2

01-02 (0.90x2.10)3 = 5.67m2

03 (0.80x2.10)3 = 5.04m2

04 (0.70x2.10)2 = 2.94m2

Net wall area = 281.83 m2

Total wall area = 322 m2

Window area = 26.52 m2

Door area = 13.65 m2

________ = 281.83 m2

MASONRY CHB = 3,525 piecesNet area x 12.50281.83 m2 x 12.5 = 3,523.875 pcs,

Say 3,525 pieces SAND CEMENT (FOR mortar and plaster)By Area Method Refer to table 2-2, Fajardo.

281.83 m2 x 0.522 (Class B)=147.12 bags

Say 148 bags, cement

281.83 m2 x 0.0435 = 12.26 cu.m.

Say 13 cu.m.

Rebars Vertical bars spacing = 0.6m Horizontal bars = every 3 layersRefer to table 3-6(Fajardo)

Vertical bars = 370Kg Area x 2.13 281.83 m2 x 2.13 = 600.3m

Say 601m 601m x 0.616kg/m = 370.22kg

Say 370kg

Horizontal bars = 374kg Area x 2.15 281.83 m2 x 2.15 =605.93 m 605.93 x 0.616kg/m = 373.36kg, say 374 kg Tie wires = 9.0Kg Use 30cm tie wire, gauge #16

(Refer to table 3-6, Fajardo) Area x 0.032 281.83 m2 x 0.032 = 9.02kg.


MATERIALS QUANTITYUNIT

PRICE(Php)

COST(Php)

CHB 3,525pcs 9/pcs 31,725.00 Washed Sand 13m3 800/ m3 10,400.00Cement 148bags 225/Bag 33,300.006m-10mm F steel bar

202pcs 125/pcs 25,250.00

#16 GI Wire 9kg 80/kg 720.00 TOTAL MATERIAL COST FOR WALLING = 101,395.00


L. WALLING:Laying of CHB

Total CHB: 3,523 blacksRate : 2 men lay 100 pcs/day

Hence; 3,523 pcs/(50pcs/mday) =70.46 mDay Say 71 mDay

Reinforcement :Total steel bars = 744kgRate: 0.09 MH/kg

Hence; 744kg x 0.09MH/kg =66.96MH, or 8.37mDaySay 9 mDay

Total MDay : 80mDay

Duration = 14 days Man power = 6 men (3 maso, 1 steel fixer, 2 labor)

Labor cost:Steel fixers: 1 x 14 days x 256/day = 3,584.00 mason: 3 x 14 days x 300/day = 12,600.00 Laborers: 2 x 14 days x 256/day = 5,600.00

______________ TOTAL LABOR COST = 21,784.00 Php

DIRECT COST FOR WALLING:

MATERIAL COST = 101,395.00 Php.LABOR COST = 21,784.00 Php.Total direct cost = 123,179.00 Php

U. FINISHING WORKS

MoldingW = 0.08403W = 0.06004W = 0.03608W = 0.11301____________ = 0.293

Using class B mixtureCement : 0.293 x 7.5 = 2.2 bags

Say 3 bags Sand : 0.293 x 0.5 = 0.146cu.m

Say 0.15cu.m

Mactan stone = 1,936 pcs (2” x6” ) Area = 0.30mx 48.5m = 14.55 ( Refer to table 2-11; velasco ) Area x 133 14.55 x133 =1,9135.15pcs.

Say 1,936pcs

Order: 2”x6” Mactan stone - 1,936 pcs

Cement = 5 bags (class B)14.55 x 0.30 = 4.365 bags

Say 5 bagsSand = 0.5 cu.m.14.55 x 0.025 = 0.365 cu.m.

Say 0.50cu.m.Pebble wash-out = 0.6902Area = 0.9x(52m-(3x0.90)) = 44.3720mm thick pebble finishes (white)

44.37 x 0.02 = 0.8874cu.m.

Cement 9 bags 0.6902 x 12 = 8.28 bags

Say 9 bagsPebbles = 0.70cu.m.0.8879cu.m. x 1.0 = 0.8874cu.m.

Say 1 cu.m.Stucco/ anay FinishArea = (2.5m x 52m) – window area – door area = 130 - 26.52 - 13.65Area = 96.33Use 15mm thick any finishing (Refer to table 2-1, FAJARDO) CEMENT = 18bags 96.33 x 0.015 x12 = 17.34bags Say 18 bags Sand = 1.5cu.m. 96.33x0.15x1.0 = 1.44 cu.m.

Say 1.5cu.m.



(Php)COST(Php)

Cement 61bags 225/kg 13,725.00Sand 3.5cu.m. 800/cu.m 2,800.00

Mactan stone 1940pcs 18/pcs 39,920.00Pebbles 1cu.m 1000/cu.m. 1000.00

TOTAL MATERIAL COST FOR FINISHING = 52,445.00 Php

.U. FINISHING WORKS

Man power rate: 0.40MH/Man power: 281.75x0.40MH/ = 15MD Duration: 3 DaysMan power : 5 men (2 mason, 3 labor)

Labor cost:

mason: 2 x 3 days x 300/day = 1,800.00 Laborers: 3 x 3 days x 256/day = 1,800.00

______________ TOTAL LABOR COST = 3,600.00 Php

DIRECT COST FOR WALL:

MATERIAL COST = 52,445php.00 Php.LABOR COST = 3,600.00 Php.Total direct cost = 56,045.00 Php.

sample estimate

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