Report copyright - Aula #07 · A Comparison of DH and DU DH 2Na (s) + 2H 2 O (l) 2NaOH (aq) + H2 (g) DH = -367.5 kJ/mol DU DH = DU + pDV DU = DH-pDV DU ≡DH-Dn(g) RT = -367.5 - 2.5 = -370.0 kJ/mol
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