Report copyright - Mark Scheme 4766 June 2005 packs/MS_MEI_S1.pdf · Statistics 1 (4766) June 2005 Final Mark Scheme 3 (i) (ii) (iii) P(X = 4) = 40 1 (4)(5) = 2 1 (Answer given) E()X = (2+12+36+80)
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