reinisch_asd_85.5151 vorticity in terms of horizontal circulation
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Reinisch_ASD_85.515 1
Vorticity in terms of horizontal circulation
0 0
. If then
d d × d (Stokes' theorem)
d × dA
dlim lim 4.8A A
w d dx dy
dA A
C
A A
C
A
U V k l i j
V l U l U A
V l U k
V l
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Reinisch_ASD_85.515 2
4.2.1 Vorticity in Natural Coordinates
0
It is convenient to express the vertical component of the
relative vorticity in natural cooridinates. Consider the
circulation around the tiny loop shown in Fig. 4.5. Then
lim . Now:C
C V s d sn s
,
the two segments along the n direction cancel.
and
where is the radius of curvature of the streamline.
and
ss
s
s s
VV n
n
VC V d s n
nn s
d s n R s d sR
R
V V VC n s
R n R
4.9V
n
Rs
V
n
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Shear and curvature vorticity
The vorticity has two terms, shear vorticity ,
and curvature vorticity . See examples in Fig. 4.6 .s
V
nV
R
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4.3 Potential Vorticity
1
Assume adiabatic flow on a surface of
. The density as
function of p is given by the Poisson equation:
1
constant potential
temperature (isentropic surface)
p p
p
R c R c
s
s
R c
pp pTp R p
pR
1.
Therefore 0 and from 4.3
0 (Kelvin's circulation theorem), or from 4.3
. But for horizontal relative circulation:
4.11
p v p pR c c c R cs s
a
a
p p p pR
dp
DC
DtC C f A const
CC A f A const
A
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Ertel’s Potential Vorticity EquationAssume an air parcel extending from to + moves along
an isentropic surface =const. The mass of the parcel is
is conserved following
the motion, therefore A
pM V z A A
g
Mg Mg
p p
for constant . Substitute into 4.11 :
4.12
P is Ertel's potential vorticity in isentropic coordinates.
When using 4.11 , we assumed that the parcel moves
approximatel
const gp
P f g constp
y horizontally. The -sign makes P positive in NH.
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Applications of Kelvin’s TheoremThe large-scale motion of the atmosphere is, to first order, adiabatic.
Conservation of the potential vorticity is a very useful constraint
discribing air movements. For example, flow over a large mountain
barrier when is large. p
0 0
0 0 0 0 0
0 0
But first consider for simple zonal flow at x , andp
, 0. Then . Since is constant, the value
downstream , . ., . For the flow to curve northward
downstream,
const y
x y f f
f f i e f f
must be < 0 (since 2 sin ) to assure conservation of .
This is the case for easterly flow (see Fig. 4.8 for NH).
Southward curvature requires >0. Again this is the case for easterly flow.
Westerly
f
flow must be purely zonal!
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Westerly and easterly flows are discusssed in Figures 4.9 and 4.10.
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Flow over mountain barrier
Now consider the case where changes following the motion. In this
case the potential vorticity P is conserved. To study adiabatic flow over a
mountain barrier we consider a homogeneous incompress
p
ible fluid.
For such fluid 4.5 becomes
1, since 0.
With .
From
4.13
dpC f A const dp
C A f A const
M constM A z A z
z
f z const
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East/West Flow Asymmetry
0
0
Consider a vertical air column between the potential surfaces (ground)
and . Westerly adiabatic flow over a ridge will produce a decrease
in z Fig. 4.9 . To satisfy 4.13 , must decrease. Upstr
eam, before the
barrier, z streaches, so must increase from its value further upstream.
If the initial circulation upstream is = 0 (steady westerly flow), the flow
turns northward (cyclonic flow) b
efore reaching the barrier creating a ridge,
then southward over the barrier forming a trough, then northward on the
east side of the barrier (Fig. 9).
Very different behavior for eastward flow, see Fig. 4.10. Discuss.
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East/West Flow Asymmetry
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East/West Flow Over Large Mountain Summary
• Steady westerly flow results in cyclonic flow immediately east of the barrier, followed by ridges and troughs downstream
• Steady easterly flow creates one trough at the location of the barrier, followed by straight easterly flow downstream
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4.4 Vorticity Equation
DIn general 0, i.e., the flow is adiabatic. How does the absolute
DtD
vorticity change when moving with the flow? ?Dt
To find out we start with the approximate horizontal momentum equations,
2.
f
Vnot
24 and 2.24 :
1 1, or
14.14
14.15
Du p u pfv fv
Dt x t x
u u u u pu v w fv
t x y z x
v v v v pu v w fu
t x y z y
U u
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2 2 2
2
2
2
Differentiate 4.14 and 4.15 :
1
1
1 11
y x
u u u u pu v w fv
t x y z x
v v v v pu v w fu
t x y z y
uu u u u u v u w u v fy
u v w f vt x y y z y y x y y y z y y
p p
x y y x
v
2 2 2
2
2
2
1 12
v v v v v v v w v u fx u v w f ut x x y x z x x x y x z x x
p p
x y x y
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Total derivative of absolute vorticity
2
2 1 and considering that = :
14.16
Considering that 0, and 0 gives the
v u
x y
u v w v w u dfu v w f v
t x y z x y x z y z dy
p p
x y y x
f Df f fu f vx Dt t y
U
2
vorticity eq
:
1
uation
D u v w v w u p pf f
Dt x y x z y z x y y x
divergence tilt solenoid
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4.4.3 Scale Analysis of the Vorticity Equation
2
1D u v w v w u p pf f
Dt x y x z y z x y y x