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Question If f is differentiable, find the limit Sol . ) ( ) 3 ( lim 2 2 0 h h x f h x f h ). ( ) ( 8 )] ( ) ( [ ) ( 4 )]} ( ) 3 ( [ ) ( ) 3 ( { lim ) ( ) 3 ( lim 0 2 2 0 x f x f x f x f x f h x f h x f h h x f h x f h h x f h x f h h

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Question. If f is differentiable, find the limit Sol. Question. Find the limit: (1) (2) Sol. (1) (2) . The Chain Rule. Theorem If u=g(x) is differentiable at x=a and y=f(u) is - PowerPoint PPT Presentation

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Page 1: Question

QuestionIf f is differentiable, find the limit

Sol

.)()3(lim22

0 hhxfhxf

h

).()(8)]()([)(4

)]}()3([)()3({lim

)()3(lim

0

22

0

xfxfxfxfxf

hxfhxfh

hxfhxfh

hxfhxf

h

h

Page 2: Question

Question Find the limit: (1) (2)

Sol. (1)

(2)

0

sin 4limsin 6x

xx 0

tan 6limsin 2x

xx

0 0

sin 4 sin 4 6 4 2 2lim lim 1 1sin 6 4 sin 6 6 3 3x x

x x xx x x

0 0

tan 6 sin 6 2 1 6lim lim 1 1 1 3 3sin 2 6 sin 2 cos6 2x x

x x xx x x x

Page 3: Question

The Chain RuleTheorem If u=g(x) is differentiable at x=a and y=f(u) isdifferentiable at u=g(a). Then y=f(g(x)) is differentiable atx=a, and

or,[ ( ( ))] ( ) ( ) ( ( )) ( ),f g x f u g x f g x g x

dy dy dudx du dx

Page 4: Question

Derivative of power functionsEx. Differentiate

Sol. Since can be written as the composition

by the chain rule, we have

.y x

ln xy e

ln 1( ) ( ) u a xy f u g x e e x xx x x

( ) , ( ) ln ,uf u e u g x x

Page 5: Question

Derivative of exponential functionsEx. Differentiate

Sol. Since can be written into

by the chain rule, we have

xy a

lnx x ay a e

ln( ) ( ) ln ln lnu x a xy f u g x e a e a a a

( ) , ( ) (ln ) ,uf u e u g x a x

Page 6: Question

ExampleEx. Differentiate

Sol. Let then By the chain rule, we have

2( ) 1F x x

2( ) , ( ) 1,f u u u g x x ( ) ( ( )).F x f g x

1/ 2

2

1( ) ( ) ( ) 22 1

x xF x f u g x u xu x

Page 7: Question

The power rule The power rule combined with the chain rule

Ex. Find the derivative of

Sol.

1[ ( )] ( ) ( )n nf x nf x f x 92( )

2 1tg tt

82 2( ) 92 1 2 1t tg tt t

8 8

2 10

2 (2 1) 1 ( 2) 2 45( 2)92 1 (2 1) (2 1)t t t tt t t

Page 8: Question

The chain ruleIf y=f(u), u=g(v) and v=h(x) are all differentiable, theny=f(g(h(x))) is differentiable and

or,

[ ( ( ( )))] ( ) ( ) ( ) ( ( ( ))) ( ( )) ( )f g h x f u g v h x f g h x g h x h x

dy dy du dvdx du dv dx

Page 9: Question

Example Ex. Differentiate

Sol.

( ) sin(cos(tan ))f x x

2( ) cos(cos(tan )) [ sin(tan )] secf x x x x

2cos(cos(tan )) sin(tan ) secx x x

Page 10: Question

Logarithmic differentiationEx. Find the derivative of Sol. Not a power function, not an exponential function

Since by product rule and chain rule,

The method used here is called logarithmic differentiation

2tan ln(1 ) 2 22

2 tan 2 22

2[sec ln(1 ) tan ]1

2 tan(1 ) [sec ln(1 ) ].1

x x

x

xy e x x xx

x xx x xx

2 tan(1 ) .xy x

2tan ln(1 ) ,x xy e

Page 11: Question

Logarithmic differentiationIn general, to differentiate we can take logarithmfirst to get then differentiating both sides

Question: Find the derivative of

Sol.

( ) .1

xxf xx

( )( ) ,g xy f xln ( ) ln ( ),y g x f x

( )( ) ( )( ) ln ( ) ( ) ( ) [ ( ) ln ( ) ( ) ].( ) ( )

g xy f x f xg x f x g x y f x g x f x g xy f x f x

1( ) ln .1 1 1

xx xf xx x x

Page 12: Question

Question Differentiate

Sol.

2 3

23

( 1) 3 2 .( 3)

x xyx

2

5 23

( 1)(15 74 31) .3 ( 3) (3 2)

x x xyx x

Page 13: Question

Implicit differentiation Materials in textbook: page 227-233

Outline Derivative of implicit functions Derivative of inverse trigonometric functions

Page 14: Question

Expressions of functions Explicit expression: y can be explicitly expressed in term

of x, for example,

Implicit expression: x and y related by an equation, and can not solve y in terms of x explicitly, for example,

3 1y x

4 3 arcsin .xyx y e x

Page 15: Question

Implicit differentiationEx. Find ifSol. Differentiating both sides with respect to x, regarding y as a function of x, and using the chain rule, we get

Solving the equation for we obtain

Ex. Find an equation of the tangent line to the curve at the origin.Sol. is the slope

y 3 3 6 .x y xy

2 23 3 6 6 .x y y y xy ,y

2

2

2 .2

y xyy x

4 3 2 3 x y x y4 2 3 3 23 4 2 3 (0)

3x y y x y y y

Page 16: Question

Example Suppose y=f(x) is defined implicitly by (1) Find (2) Let find

Sol. (1)

(2)

ln 1. xy y( )( ) (ln ) , f xg x f x e( )f x (1).g

21 ( )( ) ( ) ( ) 0 ( )( ) 1 ( )

f xf x xf x f x f xf x xf x

( ) ( )

(1) (1)

1( ) (ln ) (ln ) ( )

(1) (0) (0) (1).

f x f x

f f

g x e f x f x e f xx

g e f f e f2 1(0) , (1) 1, (0) , (1) .

2 f e f f e f

2 31(1) .2

g e e

Page 17: Question

Homework 5 Section 3.1: 45, 56, 57

Section 3.2: 10, 21, 42

Section 3.4: 11, 16, 38, 39, 42

Section 3.5: 20, 28, 40

Section 3.6: 10, 18

Page 18: Question

Derivative of arcsine function Ex. Find the derivative of Analysis. means differentiating will give Sol. Differentiating implicitly with respect to x, we obtain so

sinx yarcsiny x( )y x

arcsin .y x

2

1(arcsin )1

xx

sinx ysinx y

1 cos y y

2

1 1cos 1

yy x

Page 19: Question

Derivative of inverse functions If x=f(y) is differentiable and then the inverse function is differentiable and

or,

Proof.

1 1[ ( )] ,( )

f xf y

( ) 0,f y 1( )y f x

1 .dydxdxdy

1( ) 1 ( ) ( ) ( )( )

x f y f y y x y xf y

Page 20: Question

Example Similarly,

22

2

1 1(arccos ) , (arctan ) ,11

1( cot ) .1

x xxx

arc xx

Page 21: Question

Higher derivatives The derivative of is called the second derivative of

f and denoted by or

Recursively, we can define the third derivative and generally the nth derivative

Interpretation: for example, if s(t) is displacement, then is velocity, is acceleration and is jerk.

( )f x( ) , f f

22

2( ) , ( )d dy d y D f xdx dx dx

( ) , f f

( 1) ( )( ) ( ). n

n n nn

d yf f D f xdx

( )s t( )s t( )s t

Page 22: Question

ExampleIf

then

3 26 5 3y x x x

23 12 5y x x

6 12y x

6y( ) 0 ( 4)ny n

Page 23: Question

ExampleFind if

Sol.

At x=0, y=1, and

thus

. ye xy e(0)y

2

0

( ) (1 )( )

yy

y y

y

ye y y xy yx e

y x e y e yyx e

0

1(0) ,

y

x

yyx e e

2 20

( ) (1 ) 1(0) .( )

y y

yx

y x e y e yyx e e

Page 24: Question

ExampleIf find

Sol.

( ) ( )nf x1( ) ,f xx

11( )f x xx

2( )f x x

3 3( ) ( 1)( 2) 2f x x x

4 4( ) ( 1)( 2)( 3) 3!f x x x

( ) 1 1( ) ( 1)( 2)( 3) ( ) ( 1) !n n n nf x n x n x

Page 25: Question

Example Find if Sol. Using the trigonometry identity

Suppose then

Therefore

( )ny

cos sin( ),2

y x x

sin .y xcos sin( ),

2

cos( ) sin( 2 ).2 2

y x x

( ) sin( ),2

ky x k

( 1) cos( ) sin( ( 1) ).2 2

ky x k x k

( )(sin ) sin( ).2

n nx x

Page 26: Question

Question Find if

Hint:

Sol.

( )ny 2

1 .2

yx x

2

1 1 1 1( ).2 3 1 2

x x x x

( )1 1

( 1) ! 1 1[ ].3 ( 1) ( 2)

nn

n n

nyx x