quadratic techniques to solve polynomial equations ccss: f.if.4 ; a.apr.3
TRANSCRIPT
CCSS: F.IF.4
• For a function that models a relationship between two quantities, interpret key features of graphs and tables in terms of the quantities, and sketch graphs showing key features given a verbal description of the relationship. Key features include: intercepts; intervals where the function is increasing, decreasing, positive, or negative; relative maximums and minimums.
CCSS: A.APR.3
• Identify zeros of polynomials when suitable factorizations are available, and use the zeros to construct a rough graph of the function defined by the polynomial.
Standards for Mathematical Practice
• 1. Make sense of problems and persevere in solving them.
• 2. Reason abstractly and quantitatively.
• 3. Construct viable arguments and critique the reasoning of others.
• 4. Model with mathematics.
• 5. Use appropriate tools strategically.
• 6. Attend to precision.
• 7. Look for and make use of structure.
• 8. Look for and express regularity in repeated reasoning.
Objectives
• Solve third and fourth degree equations that contain quadratic factors, and
• Solve other non-quadratic equations that can be written in quadratic form.
Intro
• Some equations are not quadratic but can be written in a form that resembles a quadratic equation. For example, the equation x4 – 20x2 + 64 = 0 can be written as (x2)2 – 20x2 + 64 = 0. Equations that can be written this way are said to be equations in quadratic form.
Key Concept:
• An expression that is quadratic form can be written as:
• au² +bu + c for any numbers a, b, and c, a≠0, where u is some expression in x.
• The expression au² +bu + c is called quadratic form of the original expression.
Once an equation is written in quadratic form, it can be solved by the methods you have already learned to use for solving quadratic equations.
Ex. 1: Solve x4 – 13x2 + 36 = 0
03613 24 xx
0)4)(9( 22 xx
036)(13)( 222 xx
2
02
x
x
0)2)(2)(3)(3( xxxx
2
02
x
x
3
03
x
x
3
03
x
x
The solutions or roots are -3, 3, -2, and 2.
The graph of x4 – 13x2 + 36 = 0 looks like:
The graph of y = x4 – 13x2 + 36 crosses the x-axis 4 times. There will be 4 real solutions.
• Recall that (am)n = amn for any positive number a and any rational numbers n and m. This property of exponents that you learned in chapter 5 is often used when solving equations.
Ex. 2: Solve 086 4
1
2
1
xx
0)4)(2(
08)(6)(
086
4
1
4
1
4
124
1
4
1
2
1
xx
xx
xx
256
4)(
4
0)4(
444
1
4
1
4
1
x
x
x
x
16
)2()(
2
02
444
1
4
1
4
1
x
x
x
x
00
01212
?08124
?08)2(64
08)16(616
086
4
1
2
1
4
1
2
1
xx
check
00
?02424
?08)4(616
08)256(6256
086
4
1
2
1
4
1
2
1
xx
check
Ex. 3: Solve 163
2
t
644
)4(
416
)16()(
16
3
2
16
632
333
2
3
2
ort
t
ort
t
t
1616
?164
?16)64(
?1664
16
2
23
3
2
3
2
t
check
1616
?16)4(
?16)64(
?16)64(
16
2
23
3
2
3
2
t
check
Ex. 4: Solve 087 xx
12
2
2
97
82
16
2
972
817
)1(2
)8)(1(4)7(7(
2
4
08)(7)(
087
2
2
2
x
a
acbbx
xx
xx
64
8)(
822
x
x
x
Ex. 4: Solve 087 xx
00
085664
08)8(764
0864764
087
xx
check
There is no real number x such that is = -1.Since principal root of a number can not be negative, -1 is not a solution. The only solution would be 64.
1x
• Some cubic equations can be solved using the quadratic formula. First a binomial factor must be found.
Ex. 5: Solve 0273 x
3
03
)93)(3(
0272
3
x
x
xxx
x
2
333
2
273
2
3693
)1(2
)9)(1(433
2
4
093
2
2
2
i
a
acbb
xx
Quadratic form
ax2 + bx + c = 0 2x2 – 3x – 5 = 0
This also would be a quadratic form of an equation
0532
0532
0532
3
1
3
2
24
xx
or
xx
or
yy
How would you solve
Then Use Substitution
Let u = y2
u2 = y4
1;2
5 uu
iyy
yy
yy
;2
10
1;2
5
1;2
5 22
How would you solve
Then Use Substitution
Let
Do both answers
work?
1;2
5 uu
xu
xu
2
1;4
25
1;2
5
xx
xx
How would you solve
Then Use Substitution
Let
Do both answers
work?
1;2
5 uu
xu
xu
2
051312
02
10
2
15
2
25
52
53
2
25
54
253
4
252
0532
xx
How would you solve
Then Use Substitution
Let
1;2
5 uu
3
22
3
1
xu
xu
8
125
2
5
2
5
33
3
1
3
1
x
x
x
1
1
1
3
3
3
1
3
1
x
x
x