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Lecture 2
Newton’s Laws
Acceleration due to gravity
Forces
We have worked out mathematical
relationships arising from the definitions
of velocity and acceleration.
Free Falling Objects
Probably the most familiar system where
we observe acceleration is that due to
gravity.
0v v at
2 2
0 2v v as
2
0
1
2s v t at
Hammer and a paper tissue
Dropped from same height,
Hammer will hit the ground first
Air resistance will slow the tissue down.
However if we neglect air resistance both
objects will hit the ground at the same time
Free Fall Definition:
Freely falling object is one moving freely
under the influence of gravity alone,
The “free fall condition” considers gravity only:
•neglects other effects such as air resistance
Objects considered to be freely falling
propelled upwards
propelled downwards
released from rest
The acceleration due to gravity near the
earths surface is known as g. This has
been measured to be g = 9.80 ms-2.
A time delay image of
two spheres of very
different mass
falling in a vacuum. .
Free Falling Objects
It can be seen that, in
the absence of air
resistance both
accelerate at the
same rate,
independent of mass.
If we assume objects falling near the
earths surface are affected only by
gravity (air resistance is negligible)
two basic facts govern their motion:
1. Objects accelerate at the same rate,
independent of their
mass,
size
composition.
Free Falling Objects
2 . This gravitational acceleration is
constant and so does not change as
the object falls.
Ignoring air resistance, an object in free fall
experiences an acceleration of magnitude
9.8 ms-2.
In other words the downward directed velocity
increases by 9.8 ms-1 each second.
So if released from rest an object has a velocity
downwards
after 1 second of 9.8m/s.
Acceleration due to gravity
Since by convention displacement upwards is
positive, but gravity acts downwards, then
g = -9.8 ms-2.
after 2 seconds of 19.6m/s
after 3 seconds of 29.4m/s
0v v at
Example:
A ball is dropped from a window 10m above
ground. What will be its velocity just before it
hits the ground?
2
0
2 2
1
2
0 (2) ( 9.8 )( 10 )
14
v v as
v ms m
v ms
Since acceleration due to gravity is constant,
motion under the action of gravity is
uniformly accelerated motion,
so we can use the equations relating position,
displacement, velocity and acceleration
already derived
Acceleration due to gravity
2 2
0 2v v as
114v ms
Up to now we have discussed kinematics i.e.
methods for describing motion (without
reference to the causes).
We will now study motion and the causes of
motion – dynamics.
The basic physical quantities used in dynamics
are
Force, Acceleration &
Newton’s Laws
force, mass and acceleration.
Force: push or a pull
•Strength or magnitude
•Direction
Force is a vector quantity
Characteristics:
A force resulting from direct contact with
another object is called a contact force.
For example when you push or pull an
object you exert a force on it.
Force
There are also non-contact forces.
Gravitational, electrical and magnetic forces
act through empty space.
You don’t have to be standing on the
surface of the earth to experience the
effects of gravity.
Orthodontics:
contact force applied
Force is a vector quantity:
magnitude and direction
Force pushes or pulls
teeth in a particular direction
Application of force
break the periodontal ligaments
Extends width of the socket
http://www.dentistrytoday.com/oral-
medicine/oral-surgery/1536
this web site concerns the mechanics of
extraction including the Physics forceps
Force
Tooth extraction
The force due to gravity exerted on an
object is known as its weight.
Force
The SI unit of force is the Newton, N.
Force can be measured with a spring balance.
When a force pulls on the spring, the spring
extends. A pointer attached to the end of the
spring can indicate the force on a scale.
Answers are contained in
NEWTON’S three LAWS.
Force causes Acceleration
1/ What happens to an object when there
is no net force exerted on it.?
Questions:
2/ What links force and acceleration?
3/ What happens to an object that
exerts a force on another object?
Isaac Newton ( 1643-1727)
Credited with establishing a mathematical
basis for the laws of motion
Earlier Galileo Galilei (1564 –1642) established
theories concerning moving (falling) objects
1. When the vector sum of forces on an
object is zero then the acceleration of that
object is zero.
Force must be applied to an object to change
its velocity.
All dynamics is based on Newton’s Laws.
These are three empirical laws which cannot
be derived from anything more fundamental.
2. When the vector sum of forces is NOT zero
force is related to acceleration.
Force = mass x acceleration.
3.The third law describes the pairs of forces
that interacting objects exert on each other.
If we push an object it pushes back with an
equal force but in the opposite direction.
Newton’s Laws
“Any object will remain at rest or in motion
in a straight line with constant velocity
unless acted upon by an outside force”
} v = 0
v = const. No net
Force
Constant velocity means both constant
magnitude (speed) and constant direction.
NEWTON’S FIRST LAW
There is no distinction between an object at
rest and an object moving with constant
velocity.
This is not as self evident as it may seem.
It actually seems counter intuitive because it
means that:
once an object is set in motion with
uniform velocity, no force is needed to
keep it moving.
This seems contrary to everyday
experience.
Newton’s First Law
“Any object will remain at rest or in motion in
a straight line with constant velocity unless
acted upon by an outside force”
For example,
If you push a book across a table, the book
does not keep moving indefinitely after it has
left your hand. It slows down.
BUT as we will see later, this is due to
frictional forces slowing it down.
Both teams pull on the rope with equal strength
they each exert the same magnitude of force
on it, but in opposite directions.
Imagine a tug of war match with each team
equally matched.
In this case the knot in the middle of the
rope does not move. It does not
accelerate. The rope is in equilibrium.
Equilibrium and Newton’s First Law
We can write - Fleft = Fright
Σ F = 0
This means Fleft + Fright = 0
In equilibrium
Fright Fleft
Greek letter “S” represents the sum
Acceleration produced by forces acting on
an object is
directly proportional to and in the same
direction as the net external force
inversely proportional to the mass of the
object
m = mass of the object
F
a=F/m
Newtons (N) (kg) (ms-2)
extnetF
ma
Newton’s Second Law
extnetF ma
The greater the mass of a body, the less effect
a given force has.
The unit of force, the Newton, is defined as
follows:
Equation F=ma means that mass, in addition
to being a measure of the amount of matter
in an object, is a measure of how difficult it is
to move an object or its inertia.
Newton’s Second Law
A force of 1N acting on a mass of 1kg
produces an acceleration of 1ms-2.
F = ma so (1N) = (1kg)(1ms-2) = 1kgms-2
Inertia is the tendency
of an object at rest to remain at rest
of an object in motion to remain in motion
with its original velocity.
If a number of forces act on an object at
the same time,
Newton’s second law applies to the sum
of the forces and is written.
Thus when working out problems involving
a number of forces, it is best to calculate
the resultant force and then set that
equal to ma.
Newton’s Second Law
F maS
Mass and Weight
Weight however is the force exerted by
gravity on a body.
Thus a heavy truck is
difficult to push because of its mass
difficult to lift due to its weight.
When an object falls under the influence of
gravity it accelerates downwards at the rate:
a = g = 9.80 m/s2
Force produces an acceleration given by
F = ma
Mass is a measure both of
how much matter an object contains
how difficult it is to move.
This equation gives the gravitational force
on an object whether it is in freefall or not.
Any object with mass “near” the surface of
the earth feels a gravitational force (weight),
w = mg.
But if the force on an object due to gravity
is weight, w, and it accelerates at
g = 9.8 ms-2 then, we can write,
Mass and Weight
w mg
1 2
2
m mF G
r
Newtonian Gravity
29.81g ms
G = 6.67 10-11 N m2 kg-2
2
EM mF G ma mg
r
2
EMg G
r
2E
EMg G
R
Mass of a person is 65kg. What is his weight?
Example
On the surface of the moon the force of
gravity is approximately 1/6 of that on earth.
What is the weight of the same person on
the moon.
Mass of a person on Earth is 65kg
Weight of this person on the moon is
w = mgm
weight (w) = 65kg * {(1/6) 9.8m/s2}
w =106.2kg.m/s2 = 106.2N
Example
His weight is given by w =mg
w = 65kg * 9.8m/s2
= 637kg m/s2 = 637N
A tennis ball and a golf ball are simultaneously
dropped from a tall building of height 120m.
Neglecting air resistance, determine
(a) the speed with which each ball hits the
ground.
(b) The time taken for each to reach the
ground (g = 9.8 ms-2)
a = -g and s = -120m
Acceleration and displacement
are in the direction such that
2 2
0 2v v as v0 = 0
Example.
all objects regardless of their mass or size
fall freely with an acceleration g = 9.8ms-2
(b) The time taken for each to reach the ground
v = v0+ at
-48.5m/s = 0 + (-9.8m/s2)t
t = (-48.5m/s )/ (-9.8m/s2) = 5s
v2 = 2*(-g)(-120)
v = ±√2*(-9.8m/s2)(-120m)
= ±48.5m/s
(a) the speed with which each ball hits
the ground. 2 2
0 2v v as
But since the direction is downwards
v = - 48.5m/s
And since speed is the magnitude of velocity
Speed = 48.5m/s
A car has a maximum acceleration of 4 ms-2.
What will its maximum acceleration be while
towing a second car of the same mass.
F=ma
F=MaN
where M is the combined mass of the cars
a = 4ms-2
2N
F Fa
M m
2 2N
ma aa
m
224
22
N
msa ms
Example
EXAMPLE
A ball is thrown upward at 20m/s from a
window 60m above the ground.
(a) How high does it go?
(b) When does it reach its highest point?
(c) When does it hit the ground?
Here we will take the upward direction as the
positive direction. This means any vector
quantities pointing upward (initial velocity) are
positive while vector quantities pointing down
(acceleration due to gravity) are negative.
or t = (v-v0)/a
t = (0-20m/s)/(-9.80m/s2) = 2.04 s
It reaches its highest point after 2.04s
2 2
0( )
2
v vs
a
or
(a) To find the highest point. We note at this
point the velocity is zero. We use
v=0 so
s = [0-(20m/s)2]/[2(-9.80m/s2)] = 20.4 m
Highest point is 20.4m above the window
(c) The ball hits the ground when s = -60m.
t ?
2 2
0 2v v as
0v v at
(b) When does it reach its highest point
(-60m) = (20m/s) t+(1/2)(-9.8m/s2) (t)2
Rearranging gives
(4.9m/s2) (t)2 - (20m/s) (t) – (60m) = 0
This is a quadratic equation whose solution is.
The roots of this equation are then
t = -2s or 6.1s
As the ball could not hit the ground before it is
thrown, The correct answer must be the positive
one t = 6.1s
2 2
2
(20 / ) ( 20 / ) 4(4.9 / )( 60 )
2(4.9 / )
m s m s m s mt
m s
2
(20 / ) (40 / )
(9.8 / )
m s m st
m s
Reducing to
2
0
1
2s v t at