prog 24 first-order differential equations
DESCRIPTION
Differential Equation MatchTRANSCRIPT
Worked examples and exercises are in the textSTROUD
PROGRAMME 24
FIRST-ORDER DIFFERENTIAL
EQUATIONS
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Introduction
Formation of differential equations
Solution of differential equations
Bernoulli’s equation
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Introduction
Formation of differential equations
Solution of differential equations
Bernoulli’s equation
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Introduction
A differential equation is a relationship between an independent variable x, a dependent variable y and one or more derivatives of y with respect to x.
The order of a differential equation is given by the highest derivative involved.
2
22
2
34
3
0 is an equation of the 1st order
sin 0 is an equation of the 2nd order
0 is an equation of the 3rd orderx
dyx ydx
d yxy y xdx
d y dyy edx dx
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Introduction
Formation of differential equations
Solution of differential equations
Bernoulli’s equation
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Formation of differential equations
Differential equations may be formed from a consideration of the physical problems to which they refer. Mathematically, they can occur when arbitrary constants are eliminated from a given function. For example, let:
2
2
2
2
sin cos so that cos sin therefore
sin cos
That is 0
dyy A x B x A x B xdx
d y A x B x ydx
d y ydx
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Formation of differential equations
Here the given function had two arbitrary constants:
and the end result was a second order differential equation:
In general an nth order differential equation will result from consideration of a function with n arbitrary constants.
sin cosy A x B x
2
2 0d y ydx
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Introduction
Formation of differential equations
Solution of differential equations
Bernoulli’s equation
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Introduction
Direct integration
Separating the variables
Homogeneous equations – by substituting y = vx
Linear equations – use of integrating factor
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Introduction
Solving a differential equation is the reverse process to the one just considered. To solve a differential equation a function has to be found for which the equation holds true.
The solution will contain a number of arbitrary constants – the number equalling the order of the differential equation.
In this Programme, first-order differential equations are considered.
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Direct integration
If the differential equation to be solved can be arranged in the form:
the solution can be found by direct integration. That is:
( )dy f xdx
( )y f x dx
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Direct integration
For example:
so that:
This is the general solution (or primitive) of the differential equation. If a value of y is given for a specific value of x then a value for C can be found. This would then be a particular solution of the differential equation.
23 6 5dy x xdx
2
3 2
(3 6 5)
3 5
y x x dx
x x x C
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Separating the variables
If a differential equation is of the form:
Then, after some manipulation, the solution can be found by direct integration.
( )( )
dy f xdx F y
( ) ( ) so ( ) ( )F y dy f x dx F y dy f x dx
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Separating the variables
For example:
so that:
That is:
Finally:
21
dy xdx y
( 1) 2 so ( 1) 2y dy xdx y dy xdx
2 21 2y y C x C
2 2y y x C
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Homogeneous equations – by substituting y = vx
In a homogeneous differential equation the total degree in x and y for the terms involved is the same.
For example, in the differential equation:
the terms in x and y are both of degree 1.
To solve this equation requires a change of variable using the equation:
32
dy x ydx x
( )y v x x
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Homogeneous equations – by substituting y = vx
To solve:
let
to yield:
That is:
which can now be solved using the separation of variables method.
32
dy x ydx x
( )y v x x
3 1 3 and 2 2
dy dv x y vv xdx dx x
12
dv vxdx
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Linear equations – use of integrating factor
Consider the equation:
Multiply both sides by e5x to give:
then:
That is:
25 xdy y edx
5 5 5 2 5 75 that is x x x x x xdy de e y e e ye edx dx
5 7 5 7 so that x x x xd ye e dx ye e C
2 5x xy e Ce
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Solution of differential equations
Linear equations – use of integrating factor
The multiplicative factor e5x that permits the equation to be solved is called the integrating factor and the method of solution applies to equations of the form:
The solution is then given as:
where is the integrating factorPdxdy Py Q e
dx
.IF .IF where IFPdx
y Q dx e
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Introduction
Formation of differential equations
Solution of differential equations
Bernoulli’s equation
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Bernoulli’s equation
A Bernoulli equation is a differential equation of the form:
This is solved by:
(a) Divide both sides by yn to give:
(b) Let z = y1−n so that:
ndy Py Qydx
1n ndyy Py Qdx
(1 ) ndz dyn ydx dx
Worked examples and exercises are in the textSTROUD
Programme 24: First-order differential equations
Bernoulli’s equation
Substitution yields:
then:
becomes:
Which can be solved using the integrating factor method.
1(1 ) (1 )n ndyn y Py n Qdx
(1 ) ndz dyn ydx dx
1 1dz Pz Qdx
Worked examples and exercises are in the textSTROUD
Learning outcomes
Recognize the order of a differential equation
Appreciate that a differential equation of order n can be derived from a function containing n arbitrary constants
Solve certain first-order differential equations by direct integration
Solve certain first-order differential equations by separating the variables
Solve certain first-order homogeneous differential equations by an appropriate substitution
Solve certain first-order differential equations by using an integrating factor
Solve Bernoulli’s equation.
Programme 24: First-order differential equations