prog 24 first-order differential equations

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Worked examples and exercises are in the text STROUD PROGRAMME 24 FIRST-ORDER DIFFERENTIAL EQUATIONS

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Page 1: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

PROGRAMME 24

FIRST-ORDER DIFFERENTIAL

EQUATIONS

Page 2: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Introduction

Formation of differential equations

Solution of differential equations

Bernoulli’s equation

Page 3: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Introduction

Formation of differential equations

Solution of differential equations

Bernoulli’s equation

Page 4: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Introduction

A differential equation is a relationship between an independent variable x, a dependent variable y and one or more derivatives of y with respect to x.

The order of a differential equation is given by the highest derivative involved.

2

22

2

34

3

0 is an equation of the 1st order

sin 0 is an equation of the 2nd order

0 is an equation of the 3rd orderx

dyx ydx

d yxy y xdx

d y dyy edx dx

Page 5: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Introduction

Formation of differential equations

Solution of differential equations

Bernoulli’s equation

Page 6: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Formation of differential equations

Differential equations may be formed from a consideration of the physical problems to which they refer. Mathematically, they can occur when arbitrary constants are eliminated from a given function. For example, let:

2

2

2

2

sin cos so that cos sin therefore

sin cos

That is 0

dyy A x B x A x B xdx

d y A x B x ydx

d y ydx

Page 7: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Formation of differential equations

Here the given function had two arbitrary constants:

and the end result was a second order differential equation:

In general an nth order differential equation will result from consideration of a function with n arbitrary constants.

sin cosy A x B x

2

2 0d y ydx

Page 8: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Introduction

Formation of differential equations

Solution of differential equations

Bernoulli’s equation

Page 9: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Introduction

Direct integration

Separating the variables

Homogeneous equations – by substituting y = vx

Linear equations – use of integrating factor

Page 10: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Introduction

Solving a differential equation is the reverse process to the one just considered. To solve a differential equation a function has to be found for which the equation holds true.

The solution will contain a number of arbitrary constants – the number equalling the order of the differential equation.

In this Programme, first-order differential equations are considered.

Page 11: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Direct integration

If the differential equation to be solved can be arranged in the form:

the solution can be found by direct integration. That is:

( )dy f xdx

( )y f x dx

Page 12: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Direct integration

For example:

so that:

This is the general solution (or primitive) of the differential equation. If a value of y is given for a specific value of x then a value for C can be found. This would then be a particular solution of the differential equation.

23 6 5dy x xdx

2

3 2

(3 6 5)

3 5

y x x dx

x x x C

Page 13: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Separating the variables

If a differential equation is of the form:

Then, after some manipulation, the solution can be found by direct integration.

( )( )

dy f xdx F y

( ) ( ) so ( ) ( )F y dy f x dx F y dy f x dx

Page 14: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Separating the variables

For example:

so that:

That is:

Finally:

21

dy xdx y

( 1) 2 so ( 1) 2y dy xdx y dy xdx

2 21 2y y C x C

2 2y y x C

Page 15: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Homogeneous equations – by substituting y = vx

In a homogeneous differential equation the total degree in x and y for the terms involved is the same.

For example, in the differential equation:

the terms in x and y are both of degree 1.

To solve this equation requires a change of variable using the equation:

32

dy x ydx x

( )y v x x

Page 16: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Homogeneous equations – by substituting y = vx

To solve:

let

to yield:

That is:

which can now be solved using the separation of variables method.

32

dy x ydx x

( )y v x x

3 1 3 and 2 2

dy dv x y vv xdx dx x

12

dv vxdx

Page 17: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Linear equations – use of integrating factor

Consider the equation:

Multiply both sides by e5x to give:

then:

That is:

25 xdy y edx

5 5 5 2 5 75 that is x x x x x xdy de e y e e ye edx dx

5 7 5 7 so that x x x xd ye e dx ye e C

2 5x xy e Ce

Page 18: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Solution of differential equations

Linear equations – use of integrating factor

The multiplicative factor e5x that permits the equation to be solved is called the integrating factor and the method of solution applies to equations of the form:

The solution is then given as:

where is the integrating factorPdxdy Py Q e

dx

.IF .IF where IFPdx

y Q dx e

Page 19: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Introduction

Formation of differential equations

Solution of differential equations

Bernoulli’s equation

Page 20: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Bernoulli’s equation

A Bernoulli equation is a differential equation of the form:

This is solved by:

(a) Divide both sides by yn to give:

(b) Let z = y1−n so that:

ndy Py Qydx

1n ndyy Py Qdx

(1 ) ndz dyn ydx dx

Page 21: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Programme 24: First-order differential equations

Bernoulli’s equation

Substitution yields:

then:

becomes:

Which can be solved using the integrating factor method.

1(1 ) (1 )n ndyn y Py n Qdx

(1 ) ndz dyn ydx dx

1 1dz Pz Qdx

Page 22: Prog 24 First-Order Differential Equations

Worked examples and exercises are in the textSTROUD

Learning outcomes

Recognize the order of a differential equation

Appreciate that a differential equation of order n can be derived from a function containing n arbitrary constants

Solve certain first-order differential equations by direct integration

Solve certain first-order differential equations by separating the variables

Solve certain first-order homogeneous differential equations by an appropriate substitution

Solve certain first-order differential equations by using an integrating factor

Solve Bernoulli’s equation.

Programme 24: First-order differential equations