problem #1: f=? m =3kga=5 m/s 2 up

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Ms. Bates, Uplift Community High School 1 Problem #1: F=? m=3kg a=5 m/s 2 up F=ma

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Problem #1: F=? m =3kga=5 m/s 2 up. F=ma. Problem #2: F=250 N down m =10 kga=?. F=ma. Problem #3: The net force acting on a 2 kg textbook is 6N to the left. What is its acceleration?. F=ma. - PowerPoint PPT Presentation

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Page 1: Problem #1: F=?     m =3kga=5 m/s 2  up

1 Ms. Bates, Uplift Community High School

Problem #1: F=? m=3kg a=5 m/s2 up

F=ma

Page 2: Problem #1: F=?     m =3kga=5 m/s 2  up

2 Ms. Bates, Uplift Community High School

Problem #2: F=250 N down m=10 kg a=?

F=ma

Page 3: Problem #1: F=?     m =3kga=5 m/s 2  up

3 Ms. Bates, Uplift Community High School

Problem #3: The net force acting on a 2 kg textbook is 6N to the left. What is its acceleration?

F=ma

Page 4: Problem #1: F=?     m =3kga=5 m/s 2  up

4 Ms. Bates, Uplift Community High School

Problem #4: Aaliyah’s downward force due to gravity is 700 N but she jumps upward with a force or 1000 N. What is her acceleration, given that she has a mass of 70 kg?

Page 5: Problem #1: F=?     m =3kga=5 m/s 2  up

5 Ms. Bates, Uplift Community High School

Problem #5: A 7 kg soccer ball has a downward force of gravity (weight) of 70 N and an upward normal force equal to 70 N. The soccer ball is kicked with a force of 110 N. Calculate acceleration.

**REMEMBER: to calculate the net force separately in the HORIZONTAL (x) direction and VERTICAL (y) direction