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4/30/16, 7:16 AM Print Test Page 1 of 5 https://www.casa.uh.edu/CourseWare2008/Root/Pages/CW/Users/Student/Grades/PrintTest.htm PRINTABLE VERSION Quiz 25 You scored 0 out of 100 Question 1 You did not answer the question. Find the slope of the tangent line to the curve at the point where . a) b) c) d) e) Question 2 You did not answer the question. Find an equation in x and y for the line tangent to the curve at the point where . a) b) c) d) e) x(t)= (2 t), y(t)= (2 t) cos 3 sin 3 t = π 3 3 3 3 2 3 3 3 3 x(t)=3 t, y(t) = cos(π t) t =3 6 x =0 3 x 3=0 x = 1 y = 1 y =2

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Page 1: PRINTABLE VERSION - UHbekki/1432sp16/notes/1432_quiz25_help.… · Print Test 4/30/16, 7:16 AM  Page 2 of 5 Question 3 You did not answer the

4/30/16, 7:16 AMPrint Test

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PRINTABLE VERSIONQuiz 25

You scored 0 out of 100Question 1

You did not answer the question.

Find the slope of the tangent line to the curve at the point where .

a)

b)

c)

d)

e)

Question 2

You did not answer the question.Find an equation in x and y for the line tangent to the curve at the pointwhere .

a)

b)

c)

d)

e)

x(t) = (2 t), y(t) = (2 t)cos3 sin3

t =π3

−3 3‾‾√

3‾‾√

2 3‾‾√

3‾‾√3

− 3‾‾√

x(t) = 3 t, y(t) = cos(π t)t = 3

6 x = 0

3 x − 3 = 0

x = −1

y = −1

y = 2

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Question 3

You did not answer the question.Find an equation in x and y for the line tangent to the curve at the point .

a)

b)

c)

d)

e)

Question 4

You did not answer the question.

Find an equation in x and y for the line tangent to the curve at the point .

a)

b)

c)

d)

e)

Question 5

You did not answer the question.Find an equation in x and y for the line tangent to the polar curve at .

x(t) = t − 2, y(t) = t 4 (0, 16)

32 x − y + 16 = 0

32 x + y + 112 = 0

32 x + y + 16 = 0

−32 x + y + 16 = 0

8 x − y + 48 = 0

x(t) = , y(t) = + 22t t 2

(1, 6)

2x + = 052

4x − + y = 0112

14

2x − = 052

4x − 7 + y = 012

−4x + 3 = 0

r = 12 − 6 sin(θ) θ = 0

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a)

b)

c)

d)

e)

Question 6

You did not answer the question.

Find an equation in x and y for the line tangent to the polar curve at .

a)

b)

c)

d)

e)

Question 7

You did not answer the question.Parametrize the curve by a pair of differentiable functions with

then determine the tangent line at the orgin.

a) , ; tangent line:

b) , ; tangent line:

c) , ; tangent line:

d) , ; tangent line:

e) , ; tangent line:

y = 4 x + 24

y = −2 x + 24

y = 6 x − 1

y = −2 x − 12

y = −3 x + 6

r = 5 cos(2 θ) θ = π2

y = x + 5

y = −5

x = 5

y = 2 x − 5

y = −6

y = −3 x3 x = x(t), y = y(t)[ (t) + [ (t) ≠ 0x ′ ]2 y′ ]2

x(t) = t y(t) = −3 t 3 x = 0

x(t) = t 2 y(t) = −3 t 3 x = 0

x(t) = −3 t 3 y(t) = t y = −1

x(t) = −3 t 3 y(t) = t y = 0

x(t) = t y(t) = −3 t 3 y = 0

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Question 8

You did not answer the question.Find the points at which the curve has a vertical tangent.

a)

b)

c)

d)

e)

Question 9

You did not answer the question.Find the points at which the curve has a horizontal tangent.

a) , , , and

b) , , , and

c) , , , and

d) , , , and

e) , , , and

Question 10

You did not answer the question.Find the points at which the curve has a vertical tangent.

(x, y) x(t) = − 12 t, y(t) = − 12 tt 2 t 3

(−11, 1)

(12, 2)

(11, −3)

(−36, 144)(−12, 3)

(x, y) x(t) = 11 cos(t), y(t) = 11 sin(2 t)

( , 22)11 2‾‾√2 ( , 22)−11 2‾‾√

2 ( , −22)11 2‾‾√2 ( , −22)−11 2‾‾√

2

( , 11)11 2‾‾√4 ( , 11)−11 2‾‾√

4 ( , −11)11 2‾‾√4 ( , −11)−11 2‾‾√

4

( , )11 2‾‾√2

112 ( , )−11 2‾‾√

2112 ( , − )11 2‾‾√

2112 ( , − )−11 2‾‾√

2112

( , 11)11 2‾‾√2 ( , 11)−11 2‾‾√

2 ( , −11)11 2‾‾√2 ( , −11)−11 2‾‾√

2

(11 , 11)2‾‾√ (−11 , 11)2‾‾√ (11 , −11)2‾‾√ (−11 , −11)2‾‾√

(x, y) x(t) = 3 − sin(t), y(t) = 5 + 2 cos(t)

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a) and

b) and

c) and

d) and

e) and

(−2, 0) (3, 1)

(3, 2) (−1, −3)

(3, 1) (1, 3)

(2, 5) (4, 5)(2, −2) (2, 3)