principles of semiconductor devices-l5
TRANSCRIPT
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www.nanohub.org
NCN
Lecture5:EnergyBands
MuhammadAshraful [email protected]
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Outline
1) SchrodingerequationinperiodicU(x)
2) Blochtheorem
4) Propertiesof
electronic
bands
5) Conclusions
Alam ECE606S09 2
. , .
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GettingBacktoCrystals
Original
Problem
PeriodicStructure
Electronsinperiodic
wewanttosolve
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Finallyan(almost)RealProblem
=
E
n n n+ + +
x x
n n nC e D e = +
U(x)
a b
But N atoms have two 2N unknown constants to find .
p=a+
Alam ECE606S09 4
For large N, isnt there a better way ?
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Outline
1) Schrodinger
equation
in
periodic
U(x)
2) Blochtheorem
3) Bandstructure
4) Propertiesofelectronicbands
5) Conclusions
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FourStepsofFindingEnergyLevelsin Crystals
d2 2 =1 Det coefficient matix =0
( ) 0x = =
dx2
2) Set2N2 equationsfor
B B x x x x
+= =
=3)
B B x x x xdx dx += =
=
Nisverylargeforcrystal,butchanging steps2and3
alittlebitwecanstillsolvethe robleminafewminutes!
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PeriodicU(x)andBlochsTheorem
notourold(k)
2 2( x ) ( x p ) = + ( ) ( ) eikp x p x + =
E U(x)=U(x+a+b)=U(x+p)
U(x)
a b
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PhasefactorforNcells
( )x ( )x p +
E U(x)
N
ikp
= 2
ikpx x e+=+
2( )
ikpx e
=
8] ( )[
ikpN
Np xx e =+
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Step2:PeriodicBoundaryCondition
E U(x)
N-1
[ ] ( ) ikpN x Np x e + =
1 2 3
21
ikpN i ne e
= 1
23
N-1 2 ..... 1,0,1,....2 2
n N Nk nNp
= =
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max min,k k
p p
= =
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Step3: BoundaryConditions
2 2
02 2 ( )mE i m U E
0 0x x += ==
sina a
A x =sinb bA x =
0 0x x
d ddx dx
+= ==
acosbB x+
a b
a b
B B
A A
=
=
ik p=sin cos
a a A a B a + =
ax a x b
ik pa b
x a x b
d de
dx dx
= =
= =
=
( )[ sin cos ]
sin cos
ik a b b b
a a
e A b B b
A a B a
+ +
=
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( )[ sin cos ]
ik a b
b be A b B b + +
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Step4: Det(matrix)=0forEnergylevels
sina aA x =sinb bA x =a b
B B=
acosbB x+
a b
A A =
( )
sin cos
[ sin cos ]
a a
ik a b
b b
A a B a
e A b B b
+
+ =
+ 0 1 0 01 aA 4)
( )
sin cos
[ sin cos ]
a a
ik a b
A a B a
e A b B b
+
=
+* *
*
0
0
a
bA
B
=
021 2 mUE
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0 2
0
............2 1 U
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Outline
1) Solution
of
Schrodinger
Equation
in
Periodic
U(x)
2) BlochTheorem
3) Bandstructure
ropert eso e ectron c an s
5) Conclusions
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GraphicalsolutiontoEnergyLevels
1 2 2 n N N............
2 1
..... , , ,....2 2
nNp
= =
k=0
k=2/Np
=E/U
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EnergyBandDiagram
k=0
= p
=E/U
0 k
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Brillouin ZoneandNumberofStates
E
2..... 1,0,1,....
n N Nk n
= =
2m mx ina
2
tates pN
band k Np
= = =
k
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p
p2
k
Np
=
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Outline
1) SolutionofSchrodingerEquationinPeriodicU(x)
2) BlochTheorem
3) Bandstructure
roper eso e ec ron c an s
5) Conclusions
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WavePacketandGroupVelocity
( )E E
i k k x iEikx i t t
Ae Aex t
+ +
= +
( )1
EE i k x i t i tikx
Ae e
= +
t1
t
Alam ECE606S09 17
k
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GroupVelocityforaGivenBand
( )x,t
( )
1
Ei k x iikx t t
Ei
Ae e
= +
1
t21ikx i t
i const . Ae e
= +
x E
t k
E
= =
cons an .x =
1 1 d kd E d E F
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2a
t dt k dk k dt m*= = = =
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EffectiveMassforaGivenBand
1/m*vE
kk
1 E
k
=
2
2 2
1 1 d E
m* dk =
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mass or eac an
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EffectiveMassisnotEssential
1/m*vE ??
kk
1 E
k
=
2
2 2
1 1 d E
*=
kF
t
=
0
t
x x dt = + 00
t Fk k dt = +
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Conclusion
1 SolutionofSchrodin ere uationisrelativel eas fors stems
with
well
defined
periodicity.
.
andbandgapssummarizeinformationaboutpossibleelectronic
states.
3) Effectivemassisnotafundamentalconcept.Therearesystems
forwhicheffectivemasscannotbedefined.
4) KPmodelisanalyticallysolvable.Realbandstructuresaresolvedoncomputer.Suchsolutionsarerelativelyeasy wewilldoHW
Alam ECE606S09 21
. .