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Previously in Chem 104: Solutions: macroscopic & microscopic • Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution— they can be exo- and endothermic TODAY QUIZ answer key out - send self- check by Tuesday midnight • Another BIG IDEA- Equilibrium • Effects on Dissolution by: P T • Effects of Dissolution on: • vapor pressure

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Previously in Chem 104: Solutions: macroscopic & microscopic Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be exo- and endothermic. TODAY QUIZ answer key out - send self-check by Tuesday midnight Another BIG IDEA- Equilibrium - PowerPoint PPT Presentation

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Page 1: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Previously in Chem 104:

• Solutions: macroscopic & microscopic

• Deducing Enthalpies of Solution

• Energetics (Enthalpies) of Dissolution—they can be exo- and endothermic

TODAY• QUIZ answer key out - send self-check by Tuesday midnight

• Another BIG IDEA- Equilibrium

• Effects on Dissolution by:

• P• T

• Effects of Dissolution on:

• vapor pressure• boiling• freezing

Page 2: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

A really BIG IDEA in chemistry

Page 3: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

A really BIG IDEA in chemistry

Closely followed by

Page 4: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

We need another word to pair with

Dynamic

As applied to a solid in equilibrium with a solvent in solution:

Page 5: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Combined with

Example 1.This explains phase changes in phase diagrams

“ a system at equilibrium when disturbed will adjust to remove or minimize the effect of the disturbance”

Page 6: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

H2O Phase Diagram

Temperature, deg C

Pres

sure

, atm

solid liquid

gas

0deg

1 atm

ice water

Page 7: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

H2O Phase Diagram

Temperature, deg C

Pres

sure

, atm

solid liquid

gas

0 deg

1 atm

ice

makemorewater

5 atm

meltslower T

Page 8: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Combined with

This explains almost all Solution behaviorsExample 2. How gas pressure affects solubility

Sg = kh PgGas solubility depends on gas partial pressure Sg = kh Pg

Henry’s Law Constant

Page 9: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

A related example: How temperature affects gas solubility

Increase T and:

Combined with

Explains almost all Solution behaviors

Gas + solvent Gas solution + energy (exothermic)

Gas + solvent Gas solution + energy

Page 10: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Another related example: How temperature affects solid solubility

Increase T and:

Combined with

Explains almost all Solution behaviors

Case A. MX + water M-(aq) + X-(aq) + energy

MX + water M-(aq) + X-(aq) + energy

Less dissolves

Increase T and:Case B. MX + water + energy M-(aq) + X-(aq)

MX + water + energy M-(aq) + X-(aq)

More dissolves

Page 11: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Combined with

Explains almost all Solution behaviors

Example 3. How a solute affects solvent vapor pressure

Psolvent = Xsolvent Posolvent

Page 12: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Combined with

Explains almost all Solution behaviors

Example 3. How a solute affects gas pressure

Psolvent = - Xsolute Posolvent

Page 13: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Combined with

Explains almost all Solution behaviors

Example 4. How a solute affects solvent boiling point

Tbp = Kbp msolute

When does a liquid boil?

Lower vapor pressure, requires more energy,higher T, to get to atmospheric pressure: Boiling Point Elevation

What changes if we add a solute?

Ebullioscopic constant

Tbp = Kbp msolute

Page 14: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Combined with

Explains almost all Solution behaviors

By extension: How a solute affects solvent freezing point

Tfp = Kfp msolute

Page 15: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Combined with

Explains almost all Solution behaviors

Three examples of Colligative Properties:colligative – depends only on the number of particles

Tfp = Kfp msolute

Tbp = Kbp msolute

Psolv = Xsolvent Posolvent

Tfp = Kfp msolute

Tbp = Kbp msolute

Psolv = Xsolvent Posolvent

Page 16: Previously in  Chem 104:   Solutions: macroscopic & microscopic   Deducing Enthalpies of Solution Energetics (Enthalpies) of Dissolution—they can be

Calculations based on Colligative Properties:requires different concentration units

M, molarity = #moles solute / liter solvent

m, molality = #moles solute / kg solvent

Weight % = (mass A/ total mass) x 100%

Mole fraction= #moles A / total # moles

We need to deal with concentration expressed as mole fraction, molality because collogative propertiesdeal only with number of particles in solution, not identities.