Practice Test 1 2009

Practice Series 1 2009ADDITIONAL MATHEMATICS 2

TIME: 1 HourAnswer all questions :

Section A

1.Solve the simultaneous equations

[ 5 marks ]

2.A curve with gradient function passes through through the

point (3, 10)

a) Find the equation of the curve.

[ 3 marks ]

b) Find the turning points and determine whether it is a maximum or minimum point.

[ 5 marks ]

3.Sketch the curve for.

[3 marks]Using the same axis, sketch the curve and hence state the number of solutions for the equation for.

[ 2 marks ]

4. ABCD is a trapezium. Given,. M is a mid point of BD and. Find:

i)

ii)

iii)

iv)

Section B

5.Table below shows the values of variables x and y obtained from an experimentx13579

y1.822.072.312.652.72

It is known that x and y are related by the equation with h and k are constants. It is given that one of the values of y is wrongly stated.

a)Plot a graph of against x using a scale of 2cm to 1 unit on both axes . Hence, draw the line of best fit [4 marks]

c) Use your graph to findi) Value of hii) Value of kiii) State the value of y that is incorrectly stated and state its actual value. [6 marks]

Section C

6.Table below shows the cost for four items in the year 2002 and 2003 and their weightages and the corresponding price indices for the year 2003 using the year 2002 as the base year.ItemCostYear 2002CostYear 2003Price indicesYear 2003Weightage

A12x1501

BY241203

C3042z2

D1013130m

a) Findi) x

ii) y

iii) z [3 marks]b) Given the composite index for year 2003 based on 2002 is 131, find m [2 marks]c) The weekly expenditure for the items in the year 2003 is RM300. Calculate the corresponding expenditure in year 2002. [2 marks]d) If the cost of item A increases by 20% from year 2003 to 2004 whereas the cost of other items remain unchanged, using the same weightage , calculate the composite index for 2004 based on 2002. [3 marks]

1.

Eliminate y

Solving quadratic equationX = (2, (3

y = 0, 4

2.a)

b) Using

X= 0, 2

(0, 10),

Differentiate

And find

Max

Min

3. Shape of

Max = 1 and Min

2 rounds y = x /

4.

x13579

3.314.285.347.027.40

N1Plot (correct axis and scale uniform)

5 points ploted correctly

Best fit line

k = y-intercept

h = gradient

k=2.8

=0.5

y = 2.53

5. a) Using

x = 18

y = 20

z =140

b)

= 131

m = 4

c)

d)

=134

K1

P1

K1

N1

N1

Substitute (3, 10)

N1

K1

K1

K1

N1

K1

K1

N1

1

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

EMBED Equation.3

N1

K1

Sketch line EMBED Equation.3

No of solution = 3

P1

P1

P1

N1

K1

N1

N1

K1

N1

K1

N1

P1

K1

N1

N1

N1

K1

N1

K1

N1

N1

K1

A

D

B

C

ANSWER SCHEME Practice Series 1 2009

ADDITIONAL MATHEMATICS 2

PAGE 3

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