pr5216 tutorial lifeng
TRANSCRIPT
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7/30/2019 PR5216 tutorial Lifeng
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CA test1. Time 1800-1850 on January 28, 2013.
2. Close-book assessment.
3. Format: short questions.
Youtube video showed for lecture
Skin anatomy and biology:http://www.youtube.com/watch?v=yKAzVC0WcmI
Transdermal electroporation
http://www.youtube.com/watch?v=SElfH3e0fQ0
Transdermal laserhttp://www.youtube.com/watch?v=YInx_7w8Oqg
Transderal ultrasonic
http://www.youtube.com/watch?v=E-34gU_7jDY&feature=related
Microneedle, drug coated;http://www.youtube.com/watch?v=2Pp4CE4F3jI
Microneedle pretreatment; Then normal patches.
http://www.youtube.com/watch?v=RVbY5nHPpnw&feature=related
Microneedle hollow, for injectionhttp://www.youtube.com/watch?v=6noG3gQBOyg
Microneedle roller
http://www.youtube.com/watch?v=Asj9q6jTBpo&feature=related
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Short Questions
1. Describe the structure of epidermis and its relevance to the
selection of drug candidates for transdermal and topical drug
delivery.
Epidermis consists of stratum corneum and the rest viable
layers. The stratum corneum intercellular lipids are the major
penetration pathway. Drugs need to partition from carrier to
stratum corneum. Then drugs need to partition from stratum
corneum to the hydrophilic regions of the viable epidermis.
Drugs with high partition coefficients can easily partition into
stratum corneum (lipid in nature) but have difficult partition
into the hydrophilic regions of the viable epidermis. Therefore,
a medium polarity (log P 1-3) is preferred for transdermal
drug delivery. On the other hand, drugs of high lipophilicity
can be good candidates for topical dosage forms as their
targeting sites are skin.
2. Describe the sandwich model for transdermal drug delivery.
The skin barrier is located in the outermost layer of the skin,
the stratum corneum. This layer consists of keratin enriched
cells embedded in lipid lamellae. These lamellae form the
main passages for diffusion of substances through the skin.
Drug can diffuse through the tortuous lipid regions where
lipids are more loosely packed (liquid crystalline phase) than
the densely packed (crystalline phase).The liquid crystalline
phase consists of cholesterol and free fatty acids while the
crystalline phase consists mainly of ceramides.
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3. To deliver a hydrophilic drug through skin to treat bone
cancer, what are potential semisolid dosage forms?
To treat bone cancer, drug needs to be delivered into the
blood circulation. So a transdermal dosage form is needed todeliver drug through skin into blood circulation. For a
hydrophilic drug, hydrogel, emulsion and liposome can be
potential dosage forms.
4. What are the functions of each ingredient in the following
transdermal gel?Methyl Salicylate 5 g (drug)
Carbomer 0.1g (polymeric thickener)
Farnesol 1g (enhancer)
Methyl paraben 0.2g (preservative)
Ethanol water to 100ml (solvents)
5. The oral dose of a drug is 10 mg per day. Its flux in atransdermal patch was determined to be 100 g/(hcm
2).
What should be the patch size?
Assume the bioavailability of this drug is 100% for both oral
and transdermal drug delivery. So 10 mg need to be
delivered in 24 hours. In 24 hours, 2400 g of drug can be
delivered per cm2. To deliver 10 mg, or 10000 g, the patch
size needs to be 10000/2400 = 4.17 cm2
. (You can alsoassume the bioavailability to be 40%, 70%...and calculate
accordingly)
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Long Question
6. A protein molecule (5k Dalton) shows therapeutic effect
when its plasma concentration reaches 1 ng / ml. An in vitro
skin permeation study needs to be carried out to test the
drug permeation rate through skin.
1) Hand-draw a schematic diagram of a flow-through cell forinvitro skin permeation study.
2) Describe a method to prepare the epidermal membranefrom a piece of human skin sample.
Dermatome; hot water at 60 C for 2 minutes; or extract
skin cells to engineer skin if the skin is still viable.
3) If the size of a transdermal patch is 10 cm2
and the plasmaclearance of the drug is 1 litre/hour, calculate thepermeation rate needed for the drug to reach its effectiveplasma concentration.J = Clp*Css/A = (1000 ml/hour) * (10
-3g/ml) / 10 cm
2
= 0.1 g/hour/cm2