powerpoint templates page 1 logarithmic functions f(x)= alog c b(x-h) + k
TRANSCRIPT
![Page 1: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/1.jpg)
Powerpoint Templates Page 1
Logarithmic Functions
f(x)= alogcb(x-h) + k
![Page 2: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/2.jpg)
If c > 1
b > 0
a < 0a > 0
b < 0
![Page 3: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/3.jpg)
If 0 < c < 1
b > 0
a < 0a > 0
b < 0
![Page 4: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/4.jpg)
Powerpoint Templates Page 4
Logarithmic Functions
The rule f(x)= alogcb(x-h) + k can be re-written in the form:
f(x)= logcb(x-h)
where the function passes through the point
and has x = h as its asymptote
x-intercept
![Page 5: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/5.jpg)
Powerpoint Templates Page 5
Graphing Logarithmic Graphing Logarithmic FunctionsFunctions
![Page 6: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/6.jpg)
Example 1 y = 2log3(x-1) + 2
Step 1 – Draw the vertical asymptote x = h
x = 1
![Page 7: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/7.jpg)
Step 2 – Locate two points using the rule
Let x=2
y = 2(0) + 2
y = 2
A(2,2)
y = 2log3(x-1) + 2
![Page 8: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/8.jpg)
Step 2 – Locate two points using the rule
Let x=4
y = 2(1) + 2
y = 4
A(4,4)
y = 2log3(x-1) + 2
![Page 9: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/9.jpg)
y = 2log3(x-1) + 2Step 3 – Sketch the curve
![Page 10: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/10.jpg)
Example 2 y = 3log0.5(x+4) - 3
![Page 11: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/11.jpg)
Example 3 y = -log1/3(-0.5x+2) + 1
y = -log1/3-0.5(x-4) + 1
![Page 12: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/12.jpg)
Powerpoint Templates Page 12
Finding the rule of Finding the rule of Logarithmic FunctionsLogarithmic Functions
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x intercept,1 point and an asymptote
Step 1: Find the x intercept and determine parameter b using
Step 2: Substitute the point (x,y) and asymptote (h)Step 3: Solve for “c”
f(x)=logcb(x-h)
![Page 14: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/14.jpg)
Example 1
(0,4)
(4,-2)
f(x)=logcb(x-h)1 +h = 2.5b
b = 0.5
f(x)=logcb(x-h)
2 = logc0.5(1-0.5)
2 = logc(0.25)
y = 2
c2 = 0.25
c = +/- 0.5
1 +0.5 = 2.5b1 = 2b
f(x)=log0.50.5(x-0.5)
x = 0.5
![Page 15: Powerpoint Templates Page 1 Logarithmic Functions f(x)= alog c b(x-h) + k](https://reader034.vdocuments.us/reader034/viewer/2022050909/56649e9e5503460f94b9f653/html5/thumbnails/15.jpg)
Example 2 f(x)=logcb(x-h)1 +h = -2b
b = 25
f(x)=logcb(x-h)
3.23 = logc25(5.24+2) 3.23 = logc(181)
y = 2
c3.23 = 181
c = +/- 5
1 -2 = -1.96b1 = 0.04b
f(x)=log525(x+2)
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Powerpoint Templates Page 16
Inverse of a Logarithm
x =3log24(y-1) - 6
Example 3: Find the inverse of y = 3log24(x-1) - 6
x+6 =3log24(y-1)x+6 =log24(y-1)
3
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Powerpoint Templates Page 17
Inverse of a Logarithm
x =5ln3(y-1) - 10
Example 3: Find the inverse of y = 5ln3(x-1) - 10
x+10 =5ln3(y-1)x+10 =ln3(y-1)
5
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Powerpoint Templates Page 18
Inverse of an ExponentialExample 4: Find the inverse of