powerpoint presentation · pm m n=m/pm m=n×pm nh 3 17 125 7.352941 h 2 so 4 98 25 0.255102 (nh 4)...
TRANSCRIPT
![Page 1: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/1.jpg)
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![Page 2: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/2.jpg)
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![Page 3: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/3.jpg)
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![Page 4: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/4.jpg)
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![Page 5: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/5.jpg)
Z =13
ne = 13
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![Page 6: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/6.jpg)
S S
OO
X
![Page 7: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/7.jpg)
H — N — H
|
H
••
X
![Page 8: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/8.jpg)
S34
16X
![Page 9: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/9.jpg)
Legge di DALTON
PTOT =
P(N2)+P(O2)+P(NO)P(N2)=190 tor = 190/760 atm =0.25 atm
P(O2) =0.30 atm
P(NO) = PTOT - P(N2)-P(O2)
= 1 – 0.25 – 0.30 = 0.45 atm
PV =nRT
225.09.79
0.18
9730821.0
4045.0
RT
PVn
gr
pmnm
70.630225.0
)1614(225.0
X
![Page 10: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/10.jpg)
44.826621
2730821.000.4
PV
mRTpm
pm
m
RT
PVn
nRTPV
pm
mn
pm
NH3 17
CH4 16
SO2 64
CO2 44
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![Page 11: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/11.jpg)
DP = K m → DP = i K m
NaCl → Na+ + Cl– i = 2 DP = K×2.0×1.0 = 2.0K
Glucosio C6H12O6 i = 1 DP = K×1.0×1.5 =1.5K
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![Page 12: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/12.jpg)
p = MRT → p = i MRT
NaCl → Na+ + Cl– i = 2 p = 2.0×0.3×RT = 0.6RT
Na2CO3 → 2Na+ + CO32- i = 3 p = 3.0×0.2×RT =0.6RT
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![Page 13: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/13.jpg)
pa(Zn) = 65.41
0.07644141.65
00.5
pa
mn
1 mol Zn → 2 mol HCl
0.076441 mol Zn → 0.152882 mol HCl
M
nV
V
nM 305764.0
5.0
152882.0V
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![Page 14: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/14.jpg)
pm m n=m/pm m=n×pm
NH3 17 125 7.352941
H2SO4 98 25 0.255102
(NH4)2SO4 132 0.255102 33.67347
Per 7.35 mol di NH3 servono 3.675 mol di H2SO4
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![Page 15: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/15.jpg)
pm m n=m/pm m=n×pm
Na2O 62 25 0.403226
H3PO4 98 125 1.27551
Na3PO4 164 0.269 44.08
Per 1.275 mol di H3PO4 servono 1.913 mol di Na2O
X
Per 0.403 mol di Na2O servono 0.269 mol di H3PO4
)(
)(
3
2
2
43
2
43
ONan
POHn
ONamol
POHmol
![Page 16: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/16.jpg)
P è del V gruppo
Fosfato → Max n.o = 5 → P2O5
Orto → 3H2O P2O5 + 3H2O → H6P2O8→ 2 H3PO4
Mg è del II gruppo → Mg2+
3Mg2+ + 2PO43- → Mg3(PO4)2 formula bruta
P O
O
O
O(–)
O(–)
O(–)
3 Mg(2+) 2
![Page 17: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/17.jpg)
S elemento VI gruppo
ato S = max n.o. = +6Ossido SO3
Acido solforico SO3 + H2O = H2SO4
Acido tio-solforico S sostituisce O = H2S2O3
Acido tio-solforico + idrossido di ammonio = tiosolfato di ammonio + H2O
H2S2O3 + 2NH4OH = (NH4)2S2O3 + 2 H2O
N H
H(+)
H
H 2 S S
O(─)
O
O (─)
![Page 18: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/18.jpg)
![Page 19: PowerPoint Presentation · pm m n=m/pm m=n×pm NH 3 17 125 7.352941 H 2 SO 4 98 25 0.255102 (NH 4) 2 SO 4 132 0.255102 33.67347 Per 7.35 mol di NH 3 servono 3.675 mol di H 2 SO 4](https://reader033.vdocuments.us/reader033/viewer/2022060521/604fda9d995dd411b9105da6/html5/thumbnails/19.jpg)