power semiconductor systems i author: ales havel e-mail: [email protected]@vsb.cz phone...
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POWER SEMICONDUCTOR SYSTEMS I
Author: Ales Havel
E-mail: [email protected]
Phone number: 4287
Headquarters: E227
Web page: http://homen.vsb.cz/~hav278/
Presentation contents
Main types of converters AC-DC converters
Single phase rectifiers Construction possibilities, wiring Load voltage and current waveforms Mathematics Neat examples
Three phase rectifiers Construction possibilities, wiring Load voltage and current waveforms Mathematics Neat examples
DC-DC converters DC-AC converters AC-AC converters
Power converters A power semiconductor converter is an
electrical device for converting electrical energy.
Division of AC/DC converters
Properties of rectifiers Number of input phases
Single phase rectifiers Three phase rectifiers n – phase rectifiers
Number of pulses P = 1, 2, 3, 6…
Possibilities of output voltage control Without control
Diode rectifiers Half-controlled rectifiers
Diodes + Thyristors Full-controlled rectifiers
Thyristors
Wiring Bridge rectifiers Node rectifiers
Half-wave single phase diode rectifiers
Voltage
Voltage
Current
Current
Resistive load
Inductive load
Important mathematical relations
Output to Input phase RMS voltage ratio
p[-] UL / U1 [-]
1 0.45
2 0.90
3 1.17
6 2.34
Limit of load current continuity for resistive loadp[-] α[°]
3 306 60
0 sinL m
pU U
p
0 cosL LU U
The output AVG voltage of diode rectifier or thyristor rectifier with control angle α = 0°:
The output AVG voltage of thyristor rectifier with control angle α.
Condition 1: The load current must be continuousCondition 2: No parallel bypass diode on the load
Example 1- submission
Calculate the output AVG voltage of the 2-pulse bridge controlled rectifier, if you know the following values:
α = 60°, U1 = 230V
Example 1- solution
1
22sin( ) sin( ) cos( )
2
24 1 1 230 2cos cos 103.5
3 3 2 2
m mL m
m m m
U UU U t d t t d t t
T
U U U UV
1 12 2 2 230 2sin cos sin cos 103.5
2 3L m
U UpU U V
p
1
0.9 2300.9 cos 103.5
3 2LU U V
a) General calculation approach:
b) Calculation utilizing the basic relation:
c) Calculation utilizing the table values:
Example 1- question?
1
22sin( ) sin( ) cos( )
2
3 3 21 3 230 2cos cos 1 155
3 2 2 2 2
m mL BD m
m m m
U UU U t d t t d t t
T
U U U UV
How will change the output AVG voltage value if we use the bypass diode parallel to the load?
Solution: