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Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office: Life Sciences Building, Room # 5206. Office Hour: T, W, F – 11:30 AM – 12:30 PM or by appointment. Email ID: [email protected] Tel. #: 304-293-6181

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Probability Frequentist Approach Determine how often you expect event A to occur given a LONG series of trials Bayesian Approach Determine the plausibility of event A given what you already know (prior).

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Page 1: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Population Genetics Lab

Lab Instructor: Hari Chhetri PhD student

Department of Biology

Area of Research: Association genetics (Populus)

Office: Life Sciences Building, Room # 5206.

Office Hour: T, W, F – 11:30 AM – 12:30 PM or by appointment.

Email ID: [email protected]

Tel. #: 304-293-6181

Page 2: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Probability and Population Genetics

Population genetics is a study of probabilitySampling alleles from population each

generation

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A

A

aa a

a

A

Page 3: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Probability

Frequentist Approach• Determine how often you

expect event A to occur given a LONG series of trials

Bayesian Approach• Determine the plausibility

of event A given what you already know (prior).

Page 4: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

ProbabilityMeasure of chance.

P(E) = # of favorable outcome / Total # of possible outcome

It lies between 0 (impossible event) and 1 (certain event). Ex. What is the probability of getting a head in one toss of a balanced coin.

Total possible outcomes = 2 ( H, T) # of Heads = 1 (H) P(H) = 1/ 2 = 0.5 = 50 %

Page 5: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Sample- point method :1.Define sample space (S): Collection of all possible outcomes of a random expt.

Ex. S (Coin tossed twice)

2. Assign probabilities to all sample points

Ex. P(HH) = ¼ ; P(HT) = ¼ ; P(TH) = ¼ ; P(TT) = ¼

Outcome 1 2 3 4

First Toss H H T T

Second Toss H T H T

Shorthand HH HT TH TT

Page 6: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Sample- point method :3.Determine event of interest and add their probabilities.

Ex. Find the probability of getting exactly one head in two tosses of a balanced coin.

i. S (Coin tossed twice) { HH, HT, TH, TT}. ii. P(HT) = ¼ ; P(TH) = ¼

iii. P(HT) + P (TH) = ¼ + ¼ = 2/4 = ½ .

If all sample points have equal probabilities then –

P(A) = na / N

where, na = # of points constituting event A and N= Total # of sample points.

Page 7: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Sample- point method :

Example: Use the Sample Point Method to find the probability of getting exactly two heads in three tosses of a balanced coin.

1. The sample space of this experiment is:

2. Assuming that the coin is fair, each of these 8 outcomes has a probability of 1/8.

3. The probability of getting two heads is the sum of the probabilities of outcomes 2, 3, and 4 (HHT, HTH, and THH), or 1/8 + 1/8 + 1/8 = 3/8 = 0.375.

In above example, find the probability of getting at least two heads.Solution: 1/8 + 1/8 + 1/8+ 1/8 = 1/2

Outcome Toss 1 Toss 2 Toss 3 Shorthand Probabilities1 Head Head Head HHH 1/82 Head Head Tail HHT 1/83 Head Tail Head HTH 1/84 Tail Head Head THH 1/85 Tail Tail Head TTH 1/86 Tail Head Tail THT 1/87 Head Tail Tail HTT 1/88 Tail Tail Tail TTT 1/8

Page 8: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Problem 1: The game of “craps” consists of rolling a pair of balanced dice (i.e., for each die getting 1, 2, 3, 4, 5, and 6 all have equal probabilities) and adding up the resulting numbers. A roll of “2” is commonly called “snake eyes” and causes an instant loss when rolled in the opening round. Using the Sample-Point Method, find the exact probability of a roll of snaked eyes. (Time : 10 minutes)

Probability

Page 9: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

For large sample space: Use fundamental counting methods.

1.mn rule : If there are “m” elements from one group and “n” elements from another group, then we can have “mn” possible pairs, with one element from each group.

mn= 6*6= 36 .

Page 10: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

For large sample space : Use fundamental counting methods.

2. Permutation: Ordered set of “r” elements, chosen without replacement, from “n” available elements.

Remember: 0! = 1 (By definition)n! = n*(n-1)*(n-2)*…………*2*1.

Example: How many trinucleotide sequences can be formed without repeating a nucleotide , where ATC is different from CAT?

Solution: n = 4 ( A, T, C and G) r = 3

= 24.

)!(!rnnPnr

)!34(!4

n

rP

Page 11: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

For large sample space : Use fundamental counting principle.

3. Combination: Unordered set of “r” elements, chosen without replacement, from “n” available elements.

Example: How many trinucleotide sequences, can be formed without repeating a nucleotide , where ATC is same as CAT.

Solution: n = 4 ( A, T, C and G) r = 3

= 4.

)!(!!rnr

nC nr

)!34(!3!4

nrC

Page 12: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

For large sample space : Use fundamental counting principle.

Problem 2: There are 36 computer workstations in this lab. If there are 18 students in the class, how many distinct ways could students be arranged, with one student per workstation? ( 10 minutes).

Problem 3: A local fraternity is organizing a raffle in which 30 tickets are to be sold one per customer. (10 minutes).

a. What is the total number of distinct ways in which winners can be chosen if prizes are awarded as follows:

b. If holders of the first four tickets drawn each receive a $30 prize?

Order of Drawing Prize

First $100

Second $50

Third $25

Fourth 10$

Page 13: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Laws of Probability1. Additive law of probability:

B)P(A - P(B) P(A) B)(A P

P(B) P(A) B)P(A then 0, B)P(A events, exclusivemutually For usly.simaltaneo B andA event of occurrence ofy ProbabilitB)P(A

B.or A event of occurrence ofy ProbabilitB)P(AWhere,

B)(A Pfor diagramVenn B)(A Pfor diagramVenn

A B

A and B are Mutually Exclusive

Page 14: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Laws of Probability1. Additive law of probability:

Example: From a pack of 52 cards, one card is drawn at random. Find the probability that the card is “Heart” or “Ace”.

Four suits are : Spades, Diamonds, Clubs and Hearts. Each suit has 13 cards: Ace,2,3,4,5,6,7,8,9,10,Jack, Queen and King.There are four of each type, like 4 Aces,4 Jacks, 4 Queens, 4 Kings etc.

Solution:

5216

521

524

5213 A)P(H

521 A)P(H ;

524 P(A) ;

5213 P(H)

A)P(H - P(A) P(H) A)(H P

Page 15: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Laws of Probability2. Multiplicative law of probability:

P(B) P(A) B)(A P (If A and B are independent events)

B)|P(A P(B) A)|P(B P(A) B)(A P (If A and B are dependent events)

\

Example: A pond consists of 50 salmon and 25 trout. Two fish are drawn one by one. Find the probability that both fish are Salmon. a.)with replacement andb.)without replacement

Page 16: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

11149

22298

7449

7550

A)|P(B P(A) B)P(A :treplacemen Without :(b) Case

94

7550

7550

P(B) P(A) B)P(A :treplacemen With :(a) Case

Salmon. isdrawn fish second that Prob. : P(B) Salmon. isdrawn fish first that Prob. :P(A) Let,

:Solution

Page 17: Population Genetics Lab Lab Instructor: Hari Chhetri PhD student Department of Biology Area of Research: Association genetics (Populus) Office:Life Sciences

Problem 4. An inexperienced spelunker is preparing for the exploration of a big cave in a rural area of Mexico. He is planning to use two independent light sources and from reading their technical specifications, he has concluded that each source is expected to malfunction with probability of 0.01. What is the probability that:

a) At least one of his light sources malfunctions?b) Neither of his light sources malfunction?(Time : 15 minutes)

Problem 5. GRADUATE STUDENTS ONLY: In street craps, the opening toss wins if a 7 or 11 is rolled, and the “pass” bets will pay off. Meanwhile if 2, 3, or 12 is rolled, only “don’t pass” bets will win. a) Is it safest to bet “pass” or “don’t pass” on the opening roll? Show the exact probability of each outcome. b) If the shooter rolls 7 three times in a row, is it safest to bet “pass” or “don’t pass” on the next roll? Defend your answer. (Time: 5 minutes)