pneumatic conveying - uniudcalliope.dem.uniud.it/class/des-ind-pla/pneumatic-transport.pdf ·...
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M.Campolo
Design of Industrial Plants 2018
Pneumatic Conveying
Università degli Studi di UdineDip. Politecnico Ingegneria & Architettura
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Problem
Trasfer particulate solids from one point to another
Krupp coal stacker (RTCA Kestrel Mine, Queensland)
A boat being loaded at Pier 86 Grain Terminal (Seattle)
Belts conveyor to load/unload suphur
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Objective
Transfer the solid phase continuously using a flux of air (carrier gas)
System initially used to load/unload grains, sands, seeds
System presently used to load chemicals, wood fibers, powders
Under which condition the solids can be transported as suspended matter in the flow? How large is the pressure drop?
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Transport system: suction mode
Like in a vacum cleaner…
Pressure in the line < environmental pressure
no risk of leakage, limited loading capacity/transport lenght
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Transport system: pressure mode
Pressure in the line > environmental pressure
Leakage possible, enhanced loading capacity/transport lenght
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Transport system: suction-pressure mode
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Pipeline characteristics
Pipe diameter: 10 mm – 800 mm
Solid flowrate: 1 kg/h – 1000 t/h
Pipe length: 10 m – 1000 m
Air velocity: 10 m/s – 30 m/s
Suction mode: product introduced at a number of points and delivered to a central locations
Pressure mode: product introduced at a single point and delivered to multiple locations (largerthroughput)
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Flow regimes (vertical pipe)
G: gravity force
S: drag force
A: lift force
I: inertial force
Fp-p: particle-particle drag
Fp-w: particle-wall drag
Z
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Flow regimes (horizontal pipe)
G: gravity force
S: drag force
A: lift force
I: inertial force
Fp-p: particle-particle drag
Fp-w: particle-wall drag
Z
S
G GA
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Suspension speed: experimental evaluation
Is a function of:
• Shape
• Size
• Surface roughness (smooth/rough)
Fines
Smooth/spherical grains
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Flow regimes (horizontal pipe)
Dilute regime
Z=5
Mass loading (Z)= Solid Mass flow rate/Air mass flow rate
Dense suspension
Z=20
Z= 𝑚𝑝
𝑚𝑔
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Pressure loss
• Gas friction ΔPL~w2
• Solid acceleration ΔPR~ 𝑚𝑝 w
• Blocking forces ΔPF~1/w
ΔPTOT depends on
P=Q • ΔPTOT ~ w3
dilutedense
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Flow regimes (horizontal)
Saltation velocity
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Pressure loss: horizontal pipe
G= 𝑚𝑝=Solid mass flow rate
Usalt= mimimum velocity to prevent deposition
Gas only
Gas + solids
Usalt(G)
Saltation velocity
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Pressure loss: vertical pipe
G=solid mass flow rate
Uch= choking velocity
Gas only
Gas + solidsN.B. Ug,salt>Uch!!!
Choking velocity
Uch(G)
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Pressure drop calculation
P1, 𝑚𝑔, 𝑚𝑝 P2, 𝑚𝑔, 𝑚𝑝
L,D
sfrictiongasfrictionsaccgasacc PPPPPP ,,,,21
gasgravsgrav PP ,,
Ug,sup, gas superficial velocity
Up,sup, solid phase superficial velocity
in vertical flow
θ
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Evaluation of pressure drop
• Gas properties (MM, P, T, µ, ρ)• Particle properties (ρp, Dp)• Pipeline (L, D)• Gas and solid flow rates ( 𝑚𝑝, 𝑚𝑔)
𝑍 = 𝑚𝑝
𝑚𝑠=
1
10𝛿𝐹𝑟𝑥
𝛿 = 1.44 𝐷𝑝 + 1.96 𝐷𝑝 in mm
x= 1.1 𝐷𝑝 + 2.5
Fr=𝑈𝑔,𝑠𝑎𝑙𝑡
𝑔𝐷 0.5 𝑈𝑔,𝑠𝑎𝑙𝑡 𝑠𝑒𝑙𝑒𝑐𝑡 𝑈𝑔 > 𝑈𝑔,𝑠𝑎𝑙𝑡!!!!
1. Problem data
2. Evaluation of saltation velocity
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Evaluation of pressure drop
3. Evaluation of surface velocity
4. Evaluation of volumetric fraction
5. Evaluation of effective velocity
Gas velocity (if only phase in pipe)
Particle velocity (if only phase in pipe)
Gas volumetric flowrate & volume fraction
Particle volumetric flowrate & volume fraction
Actual velocity of gas
Actual velocity of particles
𝑈𝑔,𝑠𝑢𝑝 = 𝑚𝑔
𝐴
𝑈𝑝,𝑠𝑢𝑝 = 𝑚𝑝
𝐴
𝑄𝑔 = 𝑚𝑔
𝜌𝑔
𝑄𝑝 = 𝑚𝑝
𝜌𝑝
휀𝑔 =𝑄𝑔
𝑄𝑔 + 𝑄𝑝
휀𝑝 = 1 − 휀𝑔
𝑈𝑔,𝑒𝑓𝑓 =𝑈𝑔,𝑠𝑢𝑝
휀𝑔
𝑈𝑝,𝑒𝑓𝑓 =𝑈𝑝,𝑠𝑢𝑝(1 − 휀𝑔)
Gas velocity (if only phase in pipe)
Particle velocity (if only phase in pipe)
Actual velocity of gas
Actual velocity of particles
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Evaluation of pressure drop
particle settling velocity
6. Pressure drop for gas and solid acceleration
Wall friction
Gas wall friction
∆𝑃𝑎𝑐𝑐,𝑔=0.5 휀𝑔𝜌𝑔𝑈𝑔,𝑒𝑓𝑓2 ∆𝑃𝑎𝑐𝑐,𝑝=0.5 𝜌𝑝𝑈𝑝,𝑒𝑓𝑓
2
∆𝑃𝑓𝑟𝑖𝑐𝑡𝑖𝑜𝑛,𝑔=2𝑓𝐿
𝐷𝜌𝑔𝑈𝑔,𝑒𝑓𝑓
2
𝑓 = 0.079 𝑅𝑒−0.25
𝑅𝑒 = 𝑈𝑔,𝑒𝑓𝑓𝜌𝑔𝐷/𝜇
∆𝑃𝑓𝑟𝑖𝑐𝑡𝑖𝑜𝑛,𝑝=𝑓𝑠𝑍𝐿
2𝐷𝜌𝑔𝑈𝑔,𝑒𝑓𝑓
2
𝑓𝑠 = 0.082 𝑍−0.3𝐹𝑟−0.86𝐹𝑟𝑠0.25 (
𝐷
𝐷𝑝)0.1
Fr = 𝑈𝑔,𝑒𝑓𝑓/(𝑔𝐷)0.5
𝐹𝑟𝑠 = 𝑈𝑝,𝑠𝑒𝑡𝑡/(𝑔𝐷)0.5
𝑈𝑝,𝑠𝑒𝑡𝑡 = 𝑔𝜌𝑝𝐷𝑝2/(18𝜇)
Particle-wall and particle-particlefriction
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Evaluation of pressure drop
7. Extra terms for changes in pipe elevation
∆𝑃𝑔𝑟𝑎𝑣,𝑔=휀𝑔𝜌𝑔𝐿 sin 𝜗
∆𝑃𝑔𝑟𝑎𝑣,𝑝=(1 − 휀𝑔)𝜌𝑝𝐿 sin 𝜗
Pressure loss to lift the gas
Pressure loss to lift the particles
8. Final considerations
Since
is enough to produce stable dilute flow
K=1.5÷2 is large enough to account for errors in the evaluation of 𝑈𝑠𝑎𝑙𝑡 due to the empirical correlation used
Any larger velocity would be produce dilute flow BUT the pumping powerscales with 𝑈𝑔,𝑠𝑢𝑝
3 !!!!
𝑈𝑐ℎ < 𝑈𝑠𝑎𝑙𝑡 𝑈𝑔,𝑠𝑢𝑝 = 𝑘𝑈𝑠𝑎𝑙𝑡 > 𝑈𝑠𝑎𝑙𝑡 𝑤ℎ𝑒𝑟𝑒 𝑘 > 1
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Additional pressure loss at bends
At each bend: due to centrifugal forces particlesaccumulate on one side of the pipe section, decellerating and loosingenergy
Severe erosion may be produces by hard particles
Minimise the N° of bends
Use large curvature radius
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Additional pressure drop due to bends
Equivalent length of pipe
ΔPBend = 2 f Lsk/D ρ w2
R: curvature
D: pipe diameter
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References
http://www.erpt.org/retiredsite/014Q/rhoe-00.html
Introduction to the Theoretical and Practical Principles ofPneumatic ConveyingSCOTT NEIDIGH, Neuero Corporation, West Chicago, IL, USA
Theory and design of dilute phase particle conveying systemsA.T. AGARWALD, Power handling processing
Coulson & Richardson, Chemical Engineering