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PLINTH ANALYSIS

Design Loading

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Tank Size= 12 x 8 x 4

Equivalent to = 3.6576m x 2.4384m x 1.2192m

Full tank a!ait" o# $ate% in volume& m3 = 1'.8737m3

(en)it" o# $ate% = 1'''k*+m3

,ei*-t o# $ate% in k* = 1'873.7k*

,ei*-t o# $ate% in = 1'667'.7 / 1'6.67'7k

0%o)) Setional %ea o# t-e tank = 8.9187m2

oain* !e% a%ea = 11.96'4k+m2

%ea o# Ea- lint- = 13 x 1'

= 3.9624m x '.254m

= 1.''64m2

ni#o%ml" (i)t%iute oa o# Ea- lint- = oain* !e% %ea+no. o# lint- x

en*t- o# lint-

= 11.96'4k+m2 +3 x 3.9624m

= 15.7973k+m

a! et$een Ea- lint- = 4 / 1.2192m

Shear Force Diagram (Force Exerted on Each Plinth Exclusive Sel!"eight

o "ater Tan#$

15.7973k+m

3.9624m

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Shear Force Diagram (Force Exerted on Each Plinth Inclusive Sel!"eight

o "ater Tan#$

))umin* Sel# ,ei*-t o# Tank i) equivalent to 25'k* :oain* !e% a%ea =

'.275k+m2;

ni#o%ml" (i)t%iute oa o# Ea- lint- :%e)i)tin* t-e loa o# t-e $ate% tank )el# ? T-ikne))&T-k @m!o)eiveoa&@@m!o)e(eaoa&@( 5''' mm 5''' mm 2'' mm 2.5' k+mA2 2.'' k+mA2

Total(eaoa = Sel#,ei*-t B @m!o)e(eaoa= T-kC0on%ete(en)it"+1''' B @( = 2''C 24+1''' B 2.'' = 6.8'

Total #ato%e loa& ,u =1.4'C 6.8' B1.6'C 2.5' = 13.52 k+mA2

Fato%e )!an moment D ea% oment& %ea %equi%e D ea% oment

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Fato%e Su!!o%t e*e moment

E*e no. oment %ea %equi%e a% !%ovie

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De>ection governs the design? consider o@tion to increase de@th

ection chec# PASSED