physics 314 unit 10 warmups: 2015- 2016. warmup: thur jan. 21 what is the total charge in coulombs...
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Warmup: Thur Jan. 21 What is the total charge in Coulombs for a sample of 25 sulfate ions (SO 4 has a charge of -2) Q = Ne Q = (25)(-2)(1.6 x C) -8.0 x CTRANSCRIPT
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Physics 314 Unit 10 Warmups: 2015-2016
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Warmup: Thur Jan. 21What is the total charge in
Coulombs for a sample of 25 sulfate ions?
(SO4 has a charge of -2)
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Warmup: Thur Jan. 21What is the total charge in Coulombs for a sample of 25 sulfate
ions (SO4 has a charge of -2)
Q = NeQ = (25)(-2)(1.6 x 10-19 C)
-8.0 x 10-18 C
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Warmup: Friday, January 22:
•What is the number of electrons required to create a net charge of -45 nC?
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What is the number of electrons required to create a net charge of -45 nC?
q = Neq/e = Nq = 45 nC = 4.5 x 101 nC = 4.5 x 10-8 C
4.5 x 10-8 C / 1.6 x 10-19 C = N2.81 x 1011 electrons required!
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Monday, February 1st
Warmup: Draw Electric Field Lines for the following:
Checklist:
• No Lines crossed• Diamond between
two +3 charges•Watermelon
between each +3 and the -2• 3:3:2 ratio between
lines• Arrows away from
+, toward – charges and towards - charge
+3
-2+3
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Tuesday, February 2nd
What is the net force on the middle charge?
d12 = 12 cm d23 = 3 cm
Q1 3 μC
Q2
4 μCQ3
2μC
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Tuesday, February 2nd
What is the net force on the middle charge?
d12 = 12 cm d23 = 3 cm
F32 F12
Q1 3 μC
Q2
4 μCQ3
2μC
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Wednesday, Feb. 3rd: What is the magnitude and direction of the electric field acting upon the charge shown below if it feels a force of 8.0 x 10-6 N?:
FE-4.0 μC
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What is the magnitude and direction of the electric field acting upon the charge shown below if it feels a force of 8.0 x 10-6 N?:
FE-4.0 μC
Direction: for negative charges, electric field is in reverse direction as electric force, so electric field is to the LEFT.Magnitude:E = FE/q2
= (8.0 x 10-6 N / 4.0 x 10-6 C= 2.0 N/C
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What is the electric field at the top of the ball as a result of the orange charge (-6 μC)? The orange charge is in the exact middle of the 80 cm ball.
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What is the electric field at the top of the ball as a result of the orange charge (-6 μC)? The orange charge is in the exact middle of the 80 cm ball.
Magnitude: E = kq1/r2
E = (9 x 109 Nm2/C2) (-6 x 10-6C) / (0.40 m)2
E = 3.38 x 105 N/C
Direction: Electric field lines go inward toward negative charges. Therefore, E field lines will go DOWNWARD through the top of the ball to get to the charge