physics 214

37
Physics 214 5: Quantum Physics Photons and Electromagnetic Waves The Particle Properties of Waves The Heisenberg Uncertainty Principle The Wave Properties of Particles A Particle in a Box The Schroedinger Equation The Simple Harmonic Oscillator

Upload: holmes-king

Post on 13-Mar-2016

39 views

Category:

Documents


2 download

DESCRIPTION

Physics 214. 5: Quantum Physics. Photons and Electromagnetic Waves The Particle Properties of Waves The Heisenberg Uncertainty Principle The Wave Properties of Particles A Particle in a Box The Schroedinger Equation The Simple Harmonic Oscillator. Photons and Electromagnetic Waves. - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Physics 214

Physics 214

5: Quantum Physics

•Photons and Electromagnetic Waves•The Particle Properties of Waves•The Heisenberg Uncertainty Principle•The Wave Properties of Particles•A Particle in a Box•The Schroedinger Equation•The Simple Harmonic Oscillator

Page 2: Physics 214

•Long wavelength electromagnetic radiation acts as “waves”

•consider a radio wave with = 2.5 Hz•E = ~10-8 eV too small be detected as a single photon......

a detectable single would require ~1010 such photons, which on the average act as a continuous wave

•Short wavelength electromagnetic radiation acts as “particles”

•consider a X ray wave with = 1018 Hz•E = ~103 eV, which can easily be detected as a single photon

Photons and Electromagnetic Waves

Page 3: Physics 214

How should we think of

light?

Page 4: Physics 214

Remember Beats

Page 5: Physics 214

•particle•localized•finite size

•wave•delocalized

Photon

A solitary pulse can be produced by mixing together waves of infinitely many different harmonic waves of

different frequencies, such pulses are

called wave-packets. These pulses

exhibit properties of both particles and

waves

Page 7: Physics 214

The wavepacket as whole moves with a velocity vG

---the group velocityThe waves in the wavepacket

move with a velocity vp----the phase velocity

Page 8: Physics 214

Beats

BEATSytotal x,t y1 x,t y2 x,t

ytotal x,t A1 sin k1x 1t 1 A2 sin k2 x 2t 2 let A1A2 A; 1 20

ytotal 2Acosk

2 k

1 2

x

2

1

2t

sin

k1k

2 2

x

1

2

2t

2Acos kbx

bt

modulated amplitude beat

sin ksx

st

interference wave

b

2

1

2

2; k

b k

2

Page 9: Physics 214

Dispersion

v

in a vacuum

in an another medium

vac

med

ckn k

k kc

kckn k

Page 10: Physics 214

Different Phase and Group Velocities

v

v

phase

group

kd

k dk

Page 11: Physics 214

Intensity

of Particle Streams

and

Probability

Page 12: Physics 214

The instantaneous energy density of a light wave u r,t 12

0 E r,t 2

If the frequency of the light is Eh, (E is energy) this must

correspond to u r,t E

photons per unit volume at that point and time

Thus the photon density at r,t is proportional to the square

of the amplitude of the electromagnetic wave amplitude at r,t

Page 13: Physics 214

x

If there is only one photon, the wave packet model implies that the photon density at r,t has to be interpreted as the probability that a photon is at

the position r at the time t. This interpretation also workseven if there are many photons

Page 14: Physics 214

A wave-packet has an average position, which corresponds to the average position of

the photon

x = x Prob(x) dxThe width of the wave-packet corresponds to the dispersion of

the positions of the photons

x x x 2= x x 2 Prob(x ) dx

but has no exact position that can be measured

Page 15: Physics 214

Prob

Noting that

x,t E(x,t) 2

and the normalization condition for probability distributionsProb

x ,t dx 1

we can define

Prob x,t = E(x, t) 2

E(x,t) 2 dx

Page 16: Physics 214

The Heisenberg Uncertainty Principle

A wave-packet has width x It is made up with a range of

wavelength waves

max - min =range of wavelengths of harmonic oscillators making up wave-packet proportional to the dispersion of the EXPECTED

observed value of a wavelength in the wave-packet UNCERTAINTY in the observed value of

i.e 2

Page 17: Physics 214

x xmax

xmin

range of spatial positions covered by wave-packet proportional to the dispersion of

the EXPECTED observed value of the position of the wave-packet UNCERTAINTY in the observed value of x

x x x2

The difference of the wavelengths, , of the waves contained in the wave-packet cannot be greater than the width of the

wave-packet, otherwise waves with wavelengths larger than that of the wave-packet would be in the wave-packet hence

x

Page 18: Physics 214

h p

xhp

x p hHeisenberg's Uncertainty PrincipleA more accurate analysis shows that

x p 2

= h4

m xp

p p

m

2 x

v

E

2 t E

2

E p 2

2 m E pp

m & v x

t

i. e. t E 2

Page 19: Physics 214

Complex Number Representation of WavesComplex number definitionii 2

z x iy

z1z

2 x

1 iy

1 x2 iy

2 x1x

2i y

1x

2 x

1y

2 y1y

2

x1x2 y1y2

x3

i y1x2 x1y2

iy3

complex conjugate z x iymagnitude squared z 2 z z x2 y2

-1

-1

Page 20: Physics 214

e i cos i sin

1

2 ie i e i sin

1

2e i e i cos

Thus

E k ,t Emax

sin kx t Emax

2 ie i kx t e i kx t

Page 21: Physics 214

The wave-packet is a linear combination (integral) of infinitely many waves, thus has a wave-function

E , x , t Emax

sin2

x ( ) t

in general is a complex valued functionand its magnitude squared at the point x at time t

x , t 2 x, t x , t Prob x , t

when K is chosen so that

x , t 2

dx 1

complex ;,,,max

min

cdtxEcKtx

tx,

Page 22: Physics 214

For massless particles using The Special Theory of Relativity

E pc p Ec

and Plancks Hypothesis

E h hc

Ec

h

p h

hp

& p hk2

k

de Broglie hypothesized that this was valid for particles with mass also

hp h

m vg & p k

The Wave Properties of Particles

Page 23: Physics 214

Eh

vp = Emvg

for a free particle E p 2

2m

=12

mvg2

m vg

vg

2

vp vg

2

comparison of group velocity to phase velocity for a free particle with mass

Page 24: Physics 214

de Broglies explanation of the Bohr modelusing matter waves

Electrons are waves, but they are restricted to the one dimensional Bohr orbits

They only way they can exist in such a restricted region of space is as standing wave patterns

In order to fit into orbits without destructive interference one has to have an integer number of standing

wave patterns in one orbit

2r n n hmv

mvr nh

2 n

Page 25: Physics 214

This condition is exactlyBohrs Angular Momentum Quantization!!!!

Localization of waves

Standing waves

Quantized energies

Electron diffraction from Nickel crystals

confirmed de Broglies ideas

Page 26: Physics 214

The diffraction pattern produced by electrons passing through 2 slits can be viewed as the probability distribution of

the electrons hitting the screen

•If << distance between slits then •Slits act as single slits

•If << slit width then •Electrons act as particles

•If ~ slit width or > slit width electron acts as WAVE !!!!

photons display the same behavior

Page 27: Physics 214

A Particle in a Box

U U=0

U

Page 28: Physics 214

L 12 1 2 3

2 3 2 4

Ln2 n n

2 Ln

Stationary States for Electron in Box

n x , t A sin kn x cos t A sin nL

x

cos t

as kn 2 n

nL

Boundary Conditions 0, t 0 L , t

Page 29: Physics 214

Prob x , t x , t 2 A2 sin 2 n L

x

cos 2 t

pn h

n

h2L

n nh

2L, n 1 , ,

i .e. Momentum is Quantized

Kn p 2

2m

n 2 h 2

4 L2

2m h 2

8 mL2

n 2 E

n

Kinetic energy = Total energy as electric potential is zero inside box

Kinetic & Total energy are QuantizedEn n2 E 1

E1 h2

8 mL2

0Zero Point Energy

If electron drops from energy level b to energy level a the frequency of light emitted is

ba h

8 mL2

b2 a2 Hz

Page 30: Physics 214

The Schrödinger Equation

Schrödinger first guessed that the matter wave x, t would satisfy the

linear wave equation2t2 2

k22x2 v2

2x2

just as string waves do, however this did not give the correct non relativistic

energy for a free (traveling) electron

i.e. E p2

2 m= K

nor did it give the correct spectrum for the hydrogen spectrum (bound localized electron)

Page 31: Physics 214

The Equation for matter (in particular electrons) that does give the correct energy is

i x, t

t=- 2

2m2 x, t

x2 U( x) x, t

which is called Schrödinger's Time Dependent Wave Equation

U (x) is the P.E. of the particle

For free particles U(x)=0 this equation has solutions of the form

x,t e ikx it ei px Et

E; p= k

Page 32: Physics 214

substituting x , t e ikx i t ei px Et

into

i x, t

t= - 2

2m 2 x,t

x 2 gives

iiE

e

i px Et

= - 2

2m

ip

2

ei px Et

Eei px Et

p2

2 me

i px Et

E p 2

2m

the non relativistic K.E. for a free particle

Page 33: Physics 214

Notice that x , t e ikx i t = x t

plugging this product into

i x , t

t= - 2

2m

2 x, t x2

+ U(x) x , t gives

x d t

dt - 2

2 m

2 x x2

+ U(x) x

t

1

t d t

dt

1

x - 2

2m

2 x x2

+ U(x) x

This equation can only have a solution if both sides are constant

1

t d t

dt

E

& 1

x - 2

2m

2 x x 2

+ U(x) x

E

i

i

i

Page 34: Physics 214

1 t

d t dt

E

d t dt

E t

t Ce iEt ; C is a constant

1 x

-2

2m2 x x2

+ U(x ) x

E

-2

2m2

x2+ U(x )

x E x

Time Independent Schrödinger Equation

i

i

Page 35: Physics 214

Solutions of differential equations arenot completely characterized by the equation

alone. The functions must also satisfy some boundary conditions, such as having a specified

value at t 0. For the Schrödinger Equation the boundary conditions are

(1) x, t 2

-

dx =1

(2) x, t is a continuous function in x

(3) d x, t dx is a continuous function in x

(4) x, t 0 where U(x)=

Page 36: Physics 214

Particle in a Box -- Again

The potential energy of a particle in a box is

U (x) = for x 00 for x 0 , L for x L

This gives the Time Independent Schroedinger Equation

- h2

2m 2

x2 U ( x )

x E x

Which has solutions when En h2

8mL2

n2 ; n 1, 2 ,

For n 1 one can then solve the equation

- h2

2 m2

x 2 U ( x )

1 x h2

8mL 2

1 x

1 x A sinnx

L

; A is a constant that can be chosen to

normalize 1 x

Page 37: Physics 214

The Simple Harmonic Oscillator

The potential energy of a particle that moves in SHM is

U (x) = 12

kx 2 12

m 2x 2

where = km

& k is the force constant

This gives the Time Independent Schroedinger Equation

- 2

2 m2

x 2+ 1

2m2 x 2

x E x

Which has solutions when En n 12

; n 0 ,1, 2 ,

For n 0 one can then solve the equation

- 2

2 m 2

x 2+ 1

2 m 2 x 2

x

2 x

x Be m

x 2

; B is a constant that can be chosen to normalize x

2