physics 2 f09: practice final

8/10/2019 Physics 2 F09: Practice Final

1/8

~ t

A

.-

P2 Sample Final (30 minutes)

VECTOR PROBLEMS

1. What is the vector sum of a vector with magnitude 4 at -60 degrees d magnitude 4

at +60 degrees?

a) Magnitude 4, +90 deg b)Magnitude 8, 0 deg


2/8

f

KJNEMATIC PROBLEMS, Ignore Air resistance

8 You wish to throw a basketball straight up to a rim at a height of 3 meters from the

ground. Suppose

you

try to do this from your knees so the ball leaves your hands at a

height

of

1m.

What

spee

do you need to throw the basketball

Ignore

the

fact that the

basketball has finite size.

You

simply want the center

ofthe

basketball to reach the rim.

(Use

I

=10

mls

2

c 60)lJ2

rnls d)60

mls

e)none

of

the previous

9)A ski jumper leaves the ramp at an angle of 30 deg up from horizontal with a speed of

10 mls. What is the direction of the jumper 2 seconds after leaving the ramp? Use Igl=lO

m/s

2

a erfectly horizontal b) 60 deg up from horizontal c) 60 deg down from

horizont d) 30 deg

up

from horizontal e)30 deg down

om

.

10 if

the ski jumper in the previous problem barely clears a wall that extends 1.24 meters

above the level of the ramp,

how

far from the ramp is the wall?

a) 2m ) 0.5 m d) it must be below the ramp

e) none

of

the preVIOUS answers


3/8

1) Cars A and B approach each other at a four way intersection. Car

A s

velocity

is

given

by

(40,0) meters/second. Car

B s

Velocity is given by (0,30) meters per second. What is Car

B s

velocity (and speed) relative to

A?

And car A s velocity (and speed) relative to

b?

A

B

2) Joe is in a helicopter with velocity 20

i

0

j

He throws an orange out

of

the helicopter

with velocity 10m/s i Omls j. The helicopter

is

100 meters from the ground Where (in

meters, x and y coordinates) does the orange land with respect to where the helicopter

was

when Joe threw the orange? Where does the orange land with respect to where the

helicopter

ctu lly

is at

the

time

it

hits

the

ground?

3) (2D projectile motion) During a tennis match, a player serves at a speed

V

o

with the ball

leaving the racquet at 5.0

0

below the horizontal. The release point of the ball is 2.4 m above the

court surface. The ball barely clears the net that

is

2

m away and 0.90 m high. (a) What is value

ofvo? (b) In what direction (with respect to the vertical) is the ball moving as it clears the net and

how fast is it moving?

4) A pulley wheel

of8.0

cm in diameter has an 18.0 m long cord wrapped around its periphery.

Starting from rest, the wheel is given a constant angular acceleration of2.0 rad/s

2

Assume that

the rotation is CCW direction. (a) How many revolutions must the wheel turn when the cord is

completely unwound? (b) How long does it take to unwind the cord completely? (c) What are the

tangential velocity and the centripetal acceleration

of

the end-piece

of

the cord just before it

leaves the wheel?


4/8

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m m 1


5/8

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6/8

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=

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t S ~ ~ m ~ Q 1 t _ M . ~ .

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7/8

_ t ~ m ~

......

- - - - - ~ - - ~ - - - - - - - - - - - - - - -

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_ =

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-

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8/8

3.

(2D projectile

motion) During

a

tennis

rnatch

a

player

seFes

at

a sped v" with the ball

leaving the

racqut at 5.0" below the horizonlal.

The rlease

point

ofthe

ball is 2.4 m above the courl surfac.

Thc

ball barely clears the

net

that

is

12 m away and

0 90-m

high

(a)

w1lat

rs

value ofvo?

0)

What

is the

tp?d

.r

and thc angle ol the ball.

wlth

rcspecl to the

h#i. as

,t

clears t],e

net'

-

-

-

{' Y'-

l

rl

+=

i

+4

r-+)*gd"txf

f^lt

Xri

Y

a"to-.t'. xotkat'o trg

xz tr.,n\= xli

tl

casf b

+*(zt)"

->

&--

i6:

&41

(b)

ar=e;f il.i1e'L)+:x(At)a

;

sL--+e-

L.

-a=

-&j

t=t.s^ls.

N'niat--o

|

+l/'=x7

+

\

a*"r'4>,

tu^

"

=

#+

*

e@,*

ystt-@47--Y:

,..5

rlt

a

tred

4.

(Rotational

Kinematics)

A

pulley

wheel

of8-0 cm

in

diameter

has

an

18.0 m long cord

$rappql

around

':-

, :.^ .,,..*^

r

'lf

:

('.eo-)=(2''--)-

(.'l.o

oAlt'

4"

*+t

k

(wwr:'ltP'

ttrP

V\+

rldv

&

^e=

lzr*)"

+

(+so

"r)

=

;1'o )

(,,t)'.

1c)

y'=

C,Jr

,

a-"6-n9a

=

tu'.

=$

=u)r

,

Q\'n+ntu =b

f

=+-

-

oo

U""+r*

",^l-gilifrr.e

a,J ds

4,,r*"1,

a=r4

:

ai

=*tA.xt'a)=

z(=o,d)(qs

@t=i\+d/s

)

\/=

ht4

)

b.,tu;'

44lw

'a

ra;

I

x,

(oo

:

45O d

Ii""

prl

C^l

-

5f

=t

l.zpa

4*hla.{

=

(c'.tq)i

er,;'^

I

=@iA

physics 2 f09: practice final

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