phy 3.1.notebook - wisconsin lutheran high schoolgreschner.wiscoscience.com/worksheets/physics/chpt...

phy 3.1.notebook

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September 19, 2017

Everything Moves

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Diagrams:

1) Motion (picture)

Motion

timelapsed photo

\

Type Motion?

no reference!

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September 19, 2017

Diagrams:

1) Motion (picture) diagram

Motion

by inserting lines on thewall in the backgroundyou have a "referencepoint" to comparethe motion of the runner

timelapsed photo

origin re

ference pt.

reference!

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September 19, 2017

Diagrams:

1) Motion (picture) diagram

Motion

by inserting lines on thewall in the backgroundyou have a "referencepoint" to comparethe motion of the runner

timelapsed photo

origin reference pt.

A = 1 cm B = .9 cm C = .4 cm D = +.2 cm E = +.5 cm

displacement A B C D E

reference values

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September 19, 2017

2) Particle Model sometimes easier to see what's happening because it reduces the object to a point source and eliminates outside distractions

a

c

What are thefour types ofmotion?

Particle/Point model: when the size of the object is much less than the dist. it moves! when you can ignore the internal motions

How would a graph look?????

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September 19, 2017

0 1 2 3 4 5 6 7 8 9 10

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x

y

Distance

Time

.

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0 1 2 3 4 5 6 7 8 9 10

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8

9

10

x

yDistance

Time

. ...

a)

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0 1 2 3 4 5 6 7 8 9 10

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9

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x

y

Distance

Time

. .. .

b)

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0 1 2 3 4 5 6 7 8 9 10

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2

3

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x

y

Distance

Time

. ...

c)

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0 1 2 3 4 5 6 7 8 9 10

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2

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x

y

Distance

Time

.

.. ..

d)

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September 19, 2017

Little Andy rolls a ball along the ground

Andy has arm problem

s!

origin

1) motion along the "x" axis

origin

vector tellssize and direction

scalar tellsize only

distance: 1 m 1 m

displacement: 1 m,+ 1 m

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September 19, 2017

origin

1) motion along the "x" axis

origin

Andy has arm problem

s!

Little Andy rolls a ball along the ground

dv v

a

using vectors to represent motion !

4.0 m

1 cm = 0.5 mscale

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September 19, 2017

little Andy drops a rock

Andy still has arm problems!

1) motion along the "y" axis

a) what will the particle diagram look like?

b) what will the vectors look like?


." "

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v

v

v

v

a

d

a

.

" v " stands for average velocity





why average velocity in this situation?

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September 19, 2017

Andy makes the m

ost

of his arm problem

s!

using vectors to represent motion !see Andy putt!

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September 19, 2017

Andy makes the m

ost

of his arm problem

s! .a a a

v v v vv vv

using vectors to represent motion !see Andy putt!

d

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September 19, 2017


Andy doesn't care anymore!

d = 1.88 m

t = 0.63 s

2) Type motion?rest/constant velocity, acceleration

(varying vel,)

3) Formulas that apply?

1) Data/diagrams?given and understoodparticle and/or vector diagram

Here's where we're going!

THE STEPS!!!!!

to come later!

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September 19, 2017

Motion:

rest Constant velocity varying velocityacceleration

v = Δd/t v = Δdt/t_

v = (v1 + v2)/2_

a = Δv/tthe " " is critical!!!!!!!!!!!!!

_ΔvNote the difference between and v

_ a = (v2 v1)/t

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September 19, 2017

d = 1.88 m t = 0.63 s

2) Type motion?


1) Data?origin



v

v

v

v

a

d

a

.

v2 = ?

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September 19, 2017

d = 1.88 m t = 0.63 s

2) Type motion?


1) Data?origin



v

v

v

v

a

d

a

. d = 1.88 m

t = 0.63 s

a (g) = 9.8 m/s2

v1 = 0

v2 = ?

v or, a_

v =

a = Δv/t

v1 + v22

_

v = Δdt/t_

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September 19, 2017

v

a

_

Δd = 1.88 mΔt = 0.63 s

vv

v1 = 0

v2 = ?v = dt/tt = 1.88 m/0.63 s v = 3.0 m/s_

_

v = (v1 + v2)

v2 = 2v v1v2 = 2(3.0 m/s) 0v2 = 6.0 m/s

_

_

a = Δv/t = (v2 v1)/ta = (6.0 m/s 0)/0.63 sa = 9.5 m/s2

m/ss s

11s

m/ss1

m/s

( ( 1s

s1

m/s

( ( ( ( 1s m/s2= = = =

v1 = 0, v2 = ?

2

where is that?

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September 19, 2017

v = dt/tt

v = (v1 + v2)/2

a = Δv/t = (v2 v1)/t

_

_

dt = v t t = d/v_ _

v2 = 2v v1_

v1= 2v v2_

v2 = v1 + at

v1 = v2 at

t = (v2 v1)/a

formulas for varying velocity

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September 19, 2017

0.0998 m

1.175 m

t = 1.68s

1) Data/diagram?

2) Type Motion?


A ball starts from rest and rolls down a 4.870 ramp, what velocity does it attain at the bottom?...what is its acceleration?

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September 19, 2017

0.0998 m

1.175 m

t = 1.68 s

1) Data?

2) Type Motion?

3) Formulas that apply?dll = 1.175 mdh = 0.0998 mt = 1.68 sv1 = 0

v

v

v

a

ad

v = v1 + v22 v = dt

a = vt

.dll means parallel to motion

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September 19, 2017

0..0998 m

1.175 m

t = 1.68 s

1) Data? 2) Type Motion?


dll = 1.175 m

v = dt

1.175 m1.68 s= = 0.699 m/s

v = v1 + v22

v2 = 2v v1 v2 = 2(.699 m/s) 0

v2 = 1.40 m/s

a = vt

v = v1 + v22

v = dt

a = v2 v1 t

a = 1.40 m/s 01.68 s

a = 0.833 m/s2

dll = 1.175 mdh = 0.0998 mt = 1.68 sv1 = 0

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September 19, 2017

. Little Andy throws a rock. It leaves his hand at 12 m/s and travels for 3.0 seconds. How far does it go?

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September 19, 2017

.Little Andy throws a rock. It leaves his hand at 12 m/s and travels for 3.0 seconds. How far does it go?

. . . .

.v v v

d

a

v = 12 m/s

t = 3.0 s

d = ?

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September 19, 2017


. . . .

.v v v

d

a

v = 12 m/s

t = 3.0 s

d = ?

TM? v constant

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September 19, 2017


. . . .

.v v v

d

a

v = 12 m/s

t = 3.0 s

d = ?TM? v constant... v = d/t

d = vt

d = 12 m/s(3.0 s)

d = 36 m

m = m/s (s)

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September 19, 2017

A 955 kg car slows from 55 mph to 35 mph in1.3 s. What is the deceleration? How fardid he travel during the decelerating?

data?

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September 19, 2017

v1 = 55 mph

v2 = 35 mph

t = 1.3 s

a = ?

d = ?

A 955 kg car slows from 55 mph to 35 mph in1.3 s. What is the deceleration? How fardid he travel during the decelerating?

particle diagram/vectors?

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September 19, 2017

v1 = 55 mph

v2 = 35 mph

t = 1.3 s

a = ?

d = ?

d

v v v

a

. . . . .

a

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September 19, 2017

convertv1 = 55 mphv2 = 35 mpht = 1.3 sa = ?d = ?

55 miles/hr(1 hr/3600s)(1610 m/1mile) = 25 m/s

35 miles/hr(1 hr/3600s)(1610 m/1mile) = 16 m/s

25 m/s

16 m/s

a = Δv/t = (v2 v1)/ta = (16 m/s 25 m/s)/1.3 sa = 6.9 m/s/s = 6.9 m/s2

v = dt/tt dt = v t =

v1 + v2 2

(( t

dt = 25 m/s + 16 m/s 2( (

1.3 s

dt = 27 m

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September 19, 2017

t = 0.46 s

v1 = 0

v2 = ?

A little girl drops a rock from rest and it hits the ground 0.46 s later. What velocity does it hit the ground at?

vectors?

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September 19, 2017

t = 0.46 s

v1 = 0

v2 = ?

d

v

v

v

a

a

.

anything else known?

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September 19, 2017

t = 0.46 s

v1 = 0

v2 = ?

a = 9.8 m/s2

TM?

a, vv

... v =

a = Δv/t

v1 + v22

_

v = Δdt/t_

a = Δv/t

v2 = v1 + at v2 = 0 + 9.8 m/s2 (.46 s)v2 = 4.5 m/s2

you have "a" and "t" and want v2...

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September 19, 2017

What distance did it fall?from last page

t = 0.46 s

v1 = 0

v2 = ?

What's known?

(4.5 m/s)

a = 9.8 m/s2

d?equation???

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September 19, 2017

What distance did it fall?from last page

v = (v1 + v2)/2

v = [0 +(4.5 m/s)]/2

v = 2.3 m/s _

_

_

v = dt/tt d = vtd = v (.46s)

_

_

_

d = vtd = 2.3 m/s (.46s) = 1.1 m

_

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September 19, 2017

d

v

v

v

a

a

d2 = 1.5 m

t2 = 0.55 s

v1 = 0

v2 = ?

a = ?This time a little girl drops a rock from rest from a height of 1.5 m. a) What velocity does it hit the ground at?b) What acceleration did it experience?

a)

b)

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September 19, 2017

d2 = 1.5 m

t2 = 0.55 s

v1 = 0

v2 = ?

a = ?

a = vt

v = v1 + v22

v = dt

v = Δdt/t = 1.5 m/.55 s = 2.7 m/sv1 + v22

_v = v2 = 2v v1

v2 = 2(2.7 m/s) 0v2 = 5.4 m/s

a = Δv/t = v2 v1/ta = 5.4 m/s 0/.55 sa = 9.8 m/s2

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September 19, 2017

v =

a = Δv/t

v1 + v22

_

v = Δdt/t_

v2 = 2v v1

Δdt = v t

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September 19, 2017

d

v

v

v

a

a

A ball is dropped from a cliff and it takes 3.0 s to hit the ground. What velocity does it hit at?

v1 = 0

t = 3.0 s

v2 = ?

.

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September 19, 2017

vector directions gravity is down so youlist the value as ""

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September 19, 2017

d

v

v

v

a

a

. v

Bad Billy throws a rock upward at 16 m/s. How long does it take to get to the top of it path?v1 = 16 m/s

v2 = 0

t = ?

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September 19, 2017

ball thrown upward at 16 m/s

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September 19, 2017

d

v

v

v

a

a

This time bad Billy throws the rock downward at 15 m/s (from a new cliff) and it takes 3.0 s to hit the ground. a) What velocity does it hit the ground at? b) How high was the cliff?

v1 = 15 m/s

a = 9.8 m/s2

t = 3.0 s

v2 = ?

dy = ?

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September 19, 2017

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September 19, 2017

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September 19, 2017

You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s as it leaves the bow wow! How long did it take?

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September 19, 2017

You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s as it leaves the bow wow! How long did it take?

dp = .37 mv1p = 0v2p = 120 m/st = ?

TM? ... accel,

Δdt = v tt = Δd/vt = .37 m/60 m/st = .0062 s

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September 19, 2017

You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s wow! How long did it take? How far does it go in 0.55 s?

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September 19, 2017

You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s wow! How long did it take? How far does it go (after it leaves the bow) in 0.55 s?

d = ?

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September 19, 2017

You pull back a bow 37 cm and let it go. The arrow reaches a speed of 120 m/s wow! How long did it take? How far does it go in 0.55 s? The arrow stops in 4.0 cm?

phy 3.1.notebook

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September 19, 2017

duck in air: v1 = 345 ft/sv2 = 0t = ?da = ?

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September 19, 2017

1200 ft

v2 = ?

t = 3.06 s

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September 19, 2017

1200 ft

v1 = 345 ft/s

d = 1200 ft

366 m

105 m/s

g = 9.81 m/s2

v2 = ?

t = 3.06 s

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September 19, 2017

1200 ft

v1 = 345 ft/s

d = 1200 ft

366 m

105 m/s

g = 9.81 m/s2

v2 = ?

a = ∆v/tv2 = v1 + atv2 = (105 m/s) + [(9.81 m/s2)3.06 s]

v2 = 135 m/s

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September 19, 2017

duck

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phy 3.1.notebook - wisconsin lutheran high schoolgreschner.wiscoscience.com/worksheets/physics/chpt...

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