ph36010 numerical methods
DESCRIPTION
PH36010 Numerical Methods. Solving Differential Equations using MATHCAD. Solving ODEs numerically. Produce numeric solution to system of ODEs. Must have initial conditions Use one of several different solvers Produces matrix of solutions. Steps to solving ODEs. - PowerPoint PPT PresentationTRANSCRIPT
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PH36010 PH36010 Numerical MethodsNumerical Methods
Solving Differential Equations using Solving Differential Equations using MATHCADMATHCAD
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Solving ODEs numericallySolving ODEs numerically
• Produce Produce numericnumeric solution to system solution to system of ODEs.of ODEs.
• Must have initial conditionsMust have initial conditions• Use one of several different solversUse one of several different solvers• Produces matrix of solutionsProduces matrix of solutions
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Steps to solving ODEsSteps to solving ODEs
• Scale equations, parameters & Scale equations, parameters & initial conditions to remove unitsinitial conditions to remove units
• Manipulate equations to give Manipulate equations to give vector of derivativesvector of derivatives
• Give vector of initial conditionsGive vector of initial conditions• Call solverCall solver• Plot resultsPlot results
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• Radioactive decay, Newton’s law of Radioactive decay, Newton’s law of cooling etccooling etc
• A is amount of material, A is amount of material, temperature difference, etctemperature difference, etc
• k is rate constantk is rate constant
Solution of First Order ODESolution of First Order ODE
tAd
dk A
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Forming the derivative Forming the derivative vectorvector
• ““The derivative The derivative of A with of A with respect to t is –k respect to t is –k times A”times A”
tAd
dk A
k 0.1
D t A( ) k A
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Initial ConditionsInitial Conditions
• First order ODEFirst order ODE– 1 member of D(t,A) vector1 member of D(t,A) vector– 1 member of ic vector1 member of ic vector
ic0 1Although onlyAlthough only 1 member, still 1 member, still needs to be a vector needs to be a vector
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Solution parametersSolution parameters
• TStart and TFinish timesTStart and TFinish times• Number of points, NNumber of points, N
TStart 0 TFinish 5 N 1000
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Create Solution MatrixCreate Solution Matrix
• Use rkfixed() functionUse rkfixed() function• Return matrix with 1 column per DE + 1 Return matrix with 1 column per DE + 1
for independent variablefor independent variable• Use column operator to strip off columnsUse column operator to strip off columns
Soln rkfixed ic TStart TFinish N D( )
Time Soln0
Quantity Soln1
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Plot ResultsPlot Results
0 1 2 3 4 50
0.5
11
4.54105
Quantity
50 Time
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What can go wrongWhat can go wrong
• Found number greater than Found number greater than 10^30710^307– Use more pointsUse more points– Reduce TFinishReduce TFinish
• Can’t have anything with Can’t have anything with dimensions heredimensions here– Strip units from system before Strip units from system before
solutionsolution
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More complex first order More complex first order systemsystem
• Double decayDouble decay• A => B => CA => B => C
K1 K2K1 K2
tA t( )
d
dK1 A t( )
tB t( )
d
dK1 A t( ) K2 B t( )
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Forming the derivative Forming the derivative vectorvector
tA t( )
d
dK1 A t( )
tB t( )
d
dK1 A t( ) K2 B t( )
tF0 t( )
d
dK1 F0
t( )tF t( )1
d
dK1 F0
t( ) K2 F1 t( )
D t F( )K1 F0
K1 F0 K2 F1
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Initial ConditionsInitial Conditions
• System of 2 DEsSystem of 2 DEs– 2 members in D(t,F) vector2 members in D(t,F) vector– 2 members in ic vector2 members in ic vector
• FF00 refers to A => ic refers to A => ic00
• FF11 refers to B => ic refers to B => ic11
ic1
0Initially 100% of A, Initially 100% of A, 0% of B0% of B
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Form Solution of Double Form Solution of Double Decay systemDecay system
• Solution parameters as beforeSolution parameters as before• Call rkfixed() as before to create Call rkfixed() as before to create
matrixmatrix
TStart 0 TFinish 2 N 1000
Soln rkfixed ic TStart TFinish N D( )
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Plot results of double Plot results of double decaydecay
Time Soln0
A Soln1
B Soln2
0 0.5 1 1.5 20
0.2
0.4
0.6
0.8
1
A
B
Time
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Second Order SystemSecond Order SystemDamped SHMDamped SHM
• Rewrite as system of first order Rewrite as system of first order equationsequations
• Solve as beforeSolve as before
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Second Order systemSecond Order systemLCR CircuitLCR Circuit
L coilti
d
d i R res
q
C cap0
Kirchoff’s Kirchoff’s Voltage Law =>Voltage Law =>
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Second order SystemSecond order SystemForming the equationsForming the equations
L coilti
d
d i R res
q
C cap0
2tq
tq
R res
L coil
d
d
q
L coil C cap
0d
d
2
Use dq/dt=i and divide by LUse dq/dt=i and divide by Lcoilcoil
To get homogeneous equation in qTo get homogeneous equation in q
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Second Order SystemSecond Order SystemWriting standard form #1Writing standard form #1
2tq
tq
R res
L coil
d
d
q
L coil C cap
0d
d
2
q2 q1R res
L coil
q0
L coil C cap
0
Rewrite again, getting rid of d/dtRewrite again, getting rid of d/dt
2tq q2
d
d
2
tq
d
dq1 q q0
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Second Order SystemSecond Order SystemWriting standard form #2Writing standard form #2
q2 q1R res
L coil
q0
L coil C cap
0
q2 q1R res
L coil
q0
L coil C cap
0 solve q2q1 R res
C cap q0
L coil C cap
Use symbolic solver to get q2Use symbolic solver to get q2
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Second Order SystemSecond Order SystemFill in D vectorFill in D vector
• Have expressions for q1 & q2Have expressions for q1 & q2• Now fill in D(t,q) vectorNow fill in D(t,q) vector• Replace Replace
– q0 q0 q q00 ,q1 ,q1 q q1 1 ,q2 ,q2 q q22
D t q( )
q1
q1 R res C cap
q0
L coil C cap
tq
d
dq1
2tq q2
d
d
2 q1 R res C cap
q0
L coil C cap
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Second Order SystemSecond Order SystemDefine Initial ConditionsDefine Initial Conditions
• Start with 1V across capacitor & no Start with 1V across capacitor & no current flowingcurrent flowing
V0 1
ic0 holds charge at t=0ic
V0 C cap
0 ic1 holds current at t=0
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Second Order SystemSecond Order SystemCreate SolutionCreate Solution
• Examine over 0.1sExamine over 0.1s• Use 1000 pointsUse 1000 points
TStart 0 TFinish 0.1 N 1000
Soln rkfixed ic TStart TFinish N D( )
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Second Order SystemSecond Order SystemPlot Solution Plot Solution
Time Soln0
Charge Soln1
Current Soln2
Voltage capCharge
C cap
0 0.02 0.04 0.06 0.08 0.10.01
0.005
0
0.005
0.01
Current
Time
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Driven SystemsDriven Systems
• So far all systems have been So far all systems have been ‘Relaxation to steady state’‘Relaxation to steady state’
• Can also model systems driven by Can also model systems driven by ‘Forcing Function’‘Forcing Function’
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Forcing Function for LCR Forcing Function for LCR circuitcircuit
• Enables us to see resonanceEnables us to see resonance• Put voltage source in loopPut voltage source in loop
L coilti
d
d i R res
q
C capf t( ) 0
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Solution for Forced Solution for Forced OscillationOscillation
• Use symbolic solver to solve for q2 as beforeUse symbolic solver to solve for q2 as before
• Compare with undriven case…Compare with undriven case…
q2 q1R res
L coil
q0
L coil C cap
f t( ) 0 solve q2q1 R res
C cap q0 f t( ) L coil
C cap
L coil C cap
q2 q1R res
L coil
q0
L coil C cap
0 solve q2q1 R res
C cap q0
L coil C cap
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Forcing functionForcing function
• Drive with sinusoidal waveformDrive with sinusoidal waveform
• Substitute to give…Substitute to give…
q2q1 R res
C cap q0 A 0 sin t( ) L coil
C cap
L coil C cap
A 0 1 300 f t( ) A 0 sin t( )
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Derivative Vector for Derivative Vector for Forced SHMForced SHM
• No initial charge or currentNo initial charge or current
D t q( )
q1
q1 R res C cap
q0 A 0 sin t( ) L coil C cap
L coil C cap
ic0
0
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Form solutionForm solution
• Use rkfixed as before…Use rkfixed as before…
TStart 0 TFinish 0.1 N 1000
Soln rkfixed ic TStart TFinish N D( )
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Extract values & plotExtract values & plot
Time Soln0
Charge Soln1
Current Soln2
Voltage capCharge
C cap
0 0.02 0.04 0.06 0.08 0.15 10 4
0
5 10 4
Current
Time
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Phase PlotPhase Plot
• Plot Current (q1) vs Charge (q0)Plot Current (q1) vs Charge (q0)
0.15 0.1 0.05 0 0.05 0.1 0.156 10 4
4 10 4
2 10 4
0
2 10 4
4 10 4
6 10 4
4.547104
4.928104
Current
0.1180.135 Voltage cap