No NaCllmlmpTf percobaan V Spuit (mL)

13%1,0179101,79 g

98,79 g

1,570

26%1,0460104,60 g

98,60 g

8,670

39%1,0618106,18 g

97,18 g

6,670,5

412%1,0862108,62 g

96,62 g

5,170

515%1,1075110,75 g

95,75 g

5,50,3

618%1,1318113,18 g

95,18 g

17,570

a. Penentuan volume piknometerV pikno = = b. Penetuan massa jenis larutan

NaCl 3 % = = = 1,0179 g NaCl 6 % = = = 1,0460 g NaCl 9 % = = = 1,0618 g NaCl 12 % = = = 1,0862 g NaCl 15 % = = = 1,1075 g NaCl 18 % = = = 1,1318 g Isotonik = = = 1,1318 g

c. Menentukan massa larutan tiap konsentrasiM Larutan = Larutan x V Larutana) M Larutan 3% = 1,0179 g/mLx100 mL = 101,79 gb) M Larutan 6% = 1,0460 g/mLx100 mL = 104,60 gc) M Larutan 9% = 1,0618 g/mLx100 mL = 106,18 gd) M Larutan 12% = 1,0862 g/mLx100 mL = 108,62 ge) M Larutan 15% = 1,1075 g/mLx100 mL = 110,75 gf) M Larutan 18% = 1,1318 g/mLx100 mL = 113,18 gd. Menentukan massa pelarut tiap konsentrasiM pelarut = m L m Ta) Mp 3% = 101,79 g 3 g = 98,79 gb) Mp 6% = 101,79 g 6 g = 98,60 gc) Mp 9% = 101,79 g 9 g = 97,18 gd) Mp 12% = 101,79 g 12 g = 96,62 ge) Mp 15% = 101,79 g 15 g = 95,75 gf) Mp 18% = 101,79 g 18 g = 95,18 ge. Menentukan MolalitasM = xa) M 3% = x = 0,5191 Mb) M 6% = x = 1,0402Mc) M 9% = x = 1,5831 Md) M 12% = x = 2,1230 Me) M 15% = x = 2,6779 Mf) M 18% = x = 3,2327 Mf. Menentukan Tf toritisTf toritis =Kf x M x Ia) Tf toritis NaCl 3% =1,86 x 0,5191 M x 2 = 1,9311b) Tf toritis NaCl 6% =1,86 x 1,0402 M x 2 = 3,8695c) Tf toritis NaCl 9% =1,86 x 1,5831 M x 2 = 5,8891d) Tf toritis NaCl 12% =1,86 x 2,1230 M x 2 = 7,8976e) Tf toritis NaCl 15% =1,86 x 2,6779 M x 2 = 9,9618f) Tf toritis NaCl 18% =1,86 x 3,2327 M x 2 = 12,0256g. Menentukan Tf Percobaana) Tf Percobaan NaCl 3% = 0 (-1,57) = 1,57 oCb) Tf Percobaan NaCl 6% = 0 (-8,67) = 8,67oCc) Tf Percobaan NaCl 9% = 0 (-6,67) = 6,67 oCd) Tf Percobaan NaCl 12% = 0 (-5,17) = 5,17 oCe) Tf Percobaan NaCl 15% = 0 (-5,5) = 5,5 oCf) Tf Percobaan NaCl 18% = 0 (-17,57) = 17,57 oCh. x x Tf Percobaana) NaCl 3%= x x 1,57 = 1,5564b) NaCl 6%= x x 8,67 = 8,5785c) NaCl 9%= x x 6,67 = 6,5042d) NaCl 12%= x x 5,17 = 5,0126e) NaCl 15%= x x 5,5 = 5,2850f) NaCl 18%= x x 17,57 = 16,7830i. Menghitung ln V Percobaan x x x Tf Percobaana) ln V 3% = x x x 1,57 = 2087,0822 Jb) ln V 6% = x x x 8,67 = 11503,4914 Jc) ln V 9% = x x x 6,67 = 8721,9221 Jd) ln V 12% = x x x 5,17 = 6721,7347 Je) ln V 15% = x x x 5,5 = 7087,0143 Jf) ln V 18% = x x x 17,57 = 22505,4609 Jln Vsoln-w solv x Tf percobaan solv-w soln

2087,08221,5564

11503,49148,5785

8721,92216,5042

6721,73475,0126

7087,01435,285

22505,460916,783

j. Menghitung ln V percobaan + C x x x Tf Percobaan + Ca) ln V 3% = x x x 1,57 + 0,00004 = 2087,08224 Jb) ln V 6% = x x x 8,67 + 0,00004= 11503,49144 Jc) ln V 9% = x x x 6,67 + 0,00004= 8721,92214 Jd) ln V 12% = x x x 5,17 + 0,00004= 6721,73474 Je) ln V 15% = x x x 5,5 + 0,00004 = 7087,01434 Jf) ln V 18% = x x x 17,57 + 0,00004= 22505,46094 J

k. x x Tf Teoritisa) NaCl 3%= x x 1,9311 = 1,9144b) NaCl 6%= x x 3,8287 = 3,8287c) NaCl 9%= x x 5,8891 = 5,7427d) NaCl 12%= x x 7,8976 = 7,6572e) NaCl 15%= x x 9,9618 = 9,5725f) NaCl 18%= x x 12,0256 = 11,4869l. Menghitung ln V Teoritis x x x Tf Teoritisa) ln V 3% = x x x 1,9311 = 2567,1486 Jb) ln V 6% = x x x 3,8287 = 5134,1630 Jc) ln V 9% = x x x 5,8891 = 7700,7752 Jd) ln V 12% = x x x 7,8976 = 10268,0579 Je) ln V 15% = x x x 9,9618 = 12836,4133 Jf) ln V 18% = x x x 12,0256 = 15403,5619 Jln Vsoln-w solv x Tf percobaan solv-w soln

2567,14861,9144

5134,1633,8287

7700,77525,7427

10268,05797,6572

12836,41339,5725

15403,561911,4869

m. Menghitung ln V Teoritis + C x x x Tf Teoritis + Ca) ln V 3% = x x x 1,9311 + 0,0000009 = 2567,1486 J b) ln V 6% = x x x 3,8287 + 0,0000009 = 5134,1630 Jc) ln V 9% = x x x 5,8891 + 0,0000009 = 7700,7752 Jd) ln V 12% = x x x 7,8976 + 0,0000009 = 10268,0579 Je) ln V 15% = x x x 9,9618 + 0,0000009 = 12836,4133 Jf) ln V 18% = x x x 12,0256 + 0,0000009 = 15403,5619 J

n. Menentukan h percobaan x x x Tf Percobaan a) ln V 3% = x x x 1,57 = 2087,0822 Jb) ln V 6% = x x x 8,67 = 11503,4914 Jc) ln V 9% = x x x 6,67 = 8721,9221 Jd) ln V 12% = x x x 5,17 = 6721,7347 Je) ln V 15% = x x x 5,5 = 7087,0143 Jf) ln V 18% = x x x 17,57 = 22505,4609 J h w soln - w solv xTf percobaan w soln

2087,08221,5564

11503,49148,5785

8721,92216,5042

6721,73475,0126

7087,01435,285

22505,460916,783

o. Menghitung ln h percobaan + C x x x Tf Percobaan + Ca) h 3% = x x x 1,57 + 0,00004 = 2087,08224 Jb) h 6% = x x x 8,67 + 0,00004= 11503,49144 Jc) h 9% = x x x 6,67 + 0,00004= 8721,92214 Jd) h 12% = x x x 5,17 + 0,00004= 6721,73474 Je) h 15% = x x x 5,5 + 0,00004 = 7087,01434 Jf) h 18% = x x x 17,57 + 0,00004= 22505,46094 J

p. Menghitung ln h Teoritis x x x Tf Teoritisa) h 3% = x x x 1,9311 = 2567,1486 Jb) h 6% = x x x 3,8287 = 5134,1630 Jc) h 9% = x x x 5,8891 = 7700,7752 Jd) h 12% = x x x 7,8976 = 10268,0579 Je) h 15% = x x x 9,9618 = 12836,4133 Jf) h 18% = x x x 12,0256 = 15403,5619 J h w soln - w solv xTf toritis w soln

2567,14861,9144

5134,1633,8287

7700,77525,7427

10268,05797,6572

12836,41339,5725

15403,561911,4869

q. Menghitung ln h Teoritis + C x x x Tf Teoritis + Cg) h 3% = x x x 1,9311 + 0,0000009 = 2567,1486 Jh) h 6% = x x x 3,8287 + 0,0000009 = 5134,1630 Ji) h 9% = x x x 5,8891 + 0,0000009 = 7700,7752 Jj) h 12% = x x x 7,8976 + 0,0000009 = 10268,0579 Jk) h 15% = x x x 9,9618 + 0,0000009 = 12836,4133 Jl) h 18% = x x x 12,0256 + 0,0000009 = 15403,5619 J

r. Tekanan OsmosisLarutan IsotonikKomposisi Na+ = 21 meq/LK+ = 5 meq/LCa2+ = 1 meq/LMg2+= 0,5 meq/LCl-= 16 meq/LSitrat 3-= 10 meq/LLaktat-= 1 meq/LPenentuan H Na+ =21 meq/L = 21meq/1000 mL1000 meq = 23 gram = X (g) = = 0,483 gM = x = 0,084 M= M R T i= 0,084x 0,082x298x 1 = 2,0526 atm K+ =5 meq/L = 5 meq/1000 mL1000 meq = 39,1 gram = X (g) = = 0,1955 gM = x = 0,02 M= M R T i=0,02x 0,082x298x 1 = 0,488872 atm Ca2+ =1 meq/L = 1meq/1000 mL1000 meq = 40,08 g = X (g) = = 0,04008 gM = x = 0,004008M= M R T i= 0,004008 x 0,082x298x 1 = 0,19588 atm Mg2+ =0,5 meq/L = 0,5meq/1000 mL1000 meq = 24,31 gram = X (g) = = 0,012155 gM = x = 0,002 M= M R T i= 0,002 x 0,082x298x 1 = 2,0526 atm Na+ =21 meq/L = 21meq/1000 mL1000 meq = 23 gram = X (g) = = 0,483 gM = x = 0,084 M= M R T i= 0,084 x 0,082x298x 1 = 2,0526 atm Cl- = 16 meq/L = 16 meq/1000 mL1000 meq = 35,5 gram = X (g) = = 0,568 gM = x = 0,064 M= M R T i= 0,064 x 0,082x298x 1 = 1,363 atm Sitrat 3- =10 meq/L = 10meq/1000 mL1000 meq = 189,08 gram = X (g) = = 1,89 gM = x = 0,04 M= M R T i= 0,04 x 0,082x298x 3 = 2,9323 atm Laktat- =1meq/L = 1meq/1000 mL1000 meq = 89,09 gram = X (g) = = 0,08909 gM = x = 0,004 M= M R T i= 0,004 x 0,082x298x 1 = 0,09744 atm

total= = 7,394494.