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    1.0 INTROCDUCTION

    1.1 Slope Failure

    Slope failure, also referred to as mass wasting, is the down slope movement of rock

    debris and soil in response to gravitational stresses. Three major types of mass wasting

    are classified by the type of down slope movement: falls, slides, and flows and also

    represents one of the most active processes in modifying the landscape in areas of

    significant relief. Mass wasting involves material other than weathered debris (notably in

    rock slides) but most mass wasting phenomena occur in a thick mantle of regolith, the

    rock and mineral fragments produced by weathering. The general term landslide is used

    to describe all rapid forms of mass wasting. Some of the Slope failure factors are :

    a) Slope Gradient

    Slope gradient is probably the major cause of mass wasting. Generally speaking,

    the steeper the slope, the less stable it is. Therefore, steep slopes are more likely

    to experience mass wasting than gentle ones. A number of processes can

    oversteepen a slope. One of the most common is undercutting by stream or

    wave action. This removes the slope's base, increases the slope angle, and

    thereby increases the gravitational force acting parallel to the slope. Wave

    action, especially during storms, often result in mass movements along the

    shores of oceans or large lakes. Excavations for road cuts and hillside buildingsites are another major cause of slope failure. Grading the slope too steeply, or

    cutting into its side, increases the stress in rock or soil until it is no longer strong

    enough to remain at the steeper angle and mass wasting ensues. Such action is

    analogous to undercutting by streams or waves and has the same result, thus

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    explaining why so many mountain roads are plagued by frequent mass

    movements.

    b) Water Content

    The amount of water in rock or soil influences slope stability. Large quantities of

    water from melting snow or heavy storms greatly increase the likelihood of slope

    failure. The additional weight that water adds to a slope can be enough to cause

    mass movement. Furthermore, water percolating through a slope's material

    helps to decrease friction between grains, contributing to a loss of cohesion. For

    example, slopes composed of dry clay are usually quite stable, but when wet,

    they can quickly lose cohesiveness and internal friction and become an unstable

    slurry. This occurs because clay, which can hold large quantities of water,

    consists of platy particles that easily slide over each other when wet. For this

    reason, clay beds are frequently the slippery layer along which overlying rock

    units slide down slope.

    c) Overloading

    Overloading is almost always the result of human activity and typically results

    from dumping, filling, or piling up of material. Under natural conditions, a

    material's load is carried by its grain-to-grain contacts, and a slope is thus

    maintained by the friction between grains. The additional weight created by

    overloading increases the water pressure within the material, which in turn

    decreases its shear strength, thereby weakening the slope material. If enough

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    material is added, the slope will eventually fail, sometimes with tragic

    consequences.

    1.2 Slope stability

    Slope stability is the potential of soil covered slopes to withstand and undergo

    movement. Stability is determined by the balance of shear stress and shear strength. A

    previously stable slope may be initially affected by preparatory factors, making

    the slope conditionally unstable. Slope stability is based on the interplay between two

    types of forces which is driving forces and resisting forces. The driving forces promote

    downslope movement of material while the resisting forces deter movement. When

    driving forces overcome resisting forces, the slope is unstable and results in mass

    wasting. The main driving force in most land movements is gravity and the main for

    resisting force is the material's shear strength.

    Safety Factor (SF) = The ratio of resisting forces to driving forces:

    SF =

    If SF > 1 then safe

    If SF < 1 then unsafe

    1.3 Retaining wall

    Retaining structures are built for the purpose of retaining or holding back a soil mass

    (Cheng and Jack, 2005). A simple retaining wall simply depends on its weight to achieve

    stability hence as call as the gravity wall. In case of taller walls, large lateral pressure

    tends to overturn the wall, and for economical reasons, cantilever walls are more

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    preferable. As for a cantilever wall, it has a part of its base extending underneath the

    backfill and the weight of the soil above this part of the base to help prevent overturning

    (Craig, 1993). The material placed behind the retaining wall is highly desirable to be free

    draining and granular material. Clayey soils make extremely objectionable backfill

    material because of the excessive lateral pressure they create.

    Figure 1.3.1 : Simple retaining wall

    Figure 1.3.2 : Cantilever retaining wall

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    2.0 LITERATURE REVIEW

    Slope stability is a way to protect any slope from sliding or side collapse, or against

    weather conditions and erosions. So it is very important for the engineer to analyses the

    slope stability before any construction are being carried out to ensure the slope is safe

    and does not risk any human life.

    According to (Chandler, 1991), during site investigation, which is in the relation to the

    slope stability, the main aims of site investigation are : a) to obtain an understanding of

    the development and nature of natural slopes, and of the processes which have

    contributed to the formation of different natural features; b) to assess the stability of

    various forms of slopes under given conditions; c) to assess the risk of instability in

    natural or artificial slopes, and to quantify the influence of engineering works or other

    modifications to the stability of an existing slope; d) to facilitate the redesign of failed

    slopes, and the planning and design of prevention and remedial measures; and e) to

    analyze slope failures which have occurred and to define the causes of failure.

    Site investigations can be consider under 3 main headings which are: a) desk study; b)

    field study; and c) laboratory work. For desk study, the aim here is to obtain all available

    information with regard to the site and its geological environments. It will involve a

    search through records, maps, (topographical and geological), and any other

    information which is relevant to the geology, history and present condition of the site.

    As for field study, it is to record accurately the topography of the site, to determine the

    precise nature of the geological deposits underlying the site and to determine their

    engineering properties, either by the collection of good quality samples which can be

    tested subsequently in the laboratory, or by performing tests in-situ. And lastly is the

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    laboratory works which is done to obtain information, additional to that obtained

    from in situ tests, on the composition and properties of the materials encountered on

    any site. Laboratory tests can be grouped under three main headings: a) tests

    for classification and identification; and b) tests for engineering properties (Bromhead,

    1992). The first group include tests to determine the particle-size distribution of the

    material, index property tests (Liquid and Plastic Limits), specific gravity tests, and tests

    to determine the bulk density and water content of the soils. While the second group of

    tests includes those to determine the engineering properties of the soils such as

    permeability, compressibility and shear strength.

    According to (Leventhal, 1987) the accurate measurement of the shearing resistance or

    shear strength of a material is essential in attempting to predict future instability or to

    assess the present or past stability condition. As stated previously, shear strength tests

    must be performed on samples of the highest quality if reliable information is to be

    obtained. Even when this condition is satisfied, however, there may still be cases where

    the shear strength measured in the laboratory differs from that mobilised in situ. Shear

    strength properties of soils are defined by two parameters, apparent cohesion c and the

    angle of shearing resistance υ .

    The shear box was probably the first type of apparatus used for the measurement of the

    shearing resistance of soils. The apparatus consists essentially of a square brass box

    split horizontally at the level of the centre of the soil specimen which is held between

    metal grills and porous stones. The horizontal force acting on the upper part of the box

    is gradually increased until the specimen fails in shear. The shear force at failure s f is

    divided by the cross-sectional area A to give the shearing stress t f at failure. The

    vertical stress s n is provided by a vertical load on the sample, normally by dead-weights

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    and a lever system. The horizontal load is applied by pushing the lower part of the box

    by means of an electric motor and gearbox. Volume changes are monitored by a dial

    gauge mounted to show the vertical movement of the top loading platen.

    Figure 2.0.1 : Shear test example

    Figure 2.0.2 : Results of shear box test

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    The factor of safety of a slope in soil possessing cohesion and friction can be written as

    Where the factor safety for retaining wall is if it is more than 2, it is considered unsafe

    and if it is less than 2, it is considered safe.

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    3.0 Problem details

    3.1 Problem Statement

    Prelude:

    Kinabalu Times, 18 Jan 2013

    Kota Kinabalu: Villagers of a small kampong at suburban of Kota Kinabalu city

    have alarmed the authority of a possible slope failure located next to their housing

    area.

    The slope was cut during the construction of a road two years ago but the

    contractor failed to provide adequate measures to ensure the safety of the

    villagers.

    It‟s village chief, Mr. Ali Rahman said they feared the safety of schoolchildren going

    to and back from nearby secondary school. “During rainy seasons, the soil becomes

    wet and soggy, and tragedy can happen in any minute” he added.

    Upon contacted, the Public Work Department (JKR) representative, Ir. Lim

    confirmed of receiving the public complain. Ir. Lim said a geotechnical company

    has been commissioned to assess the slope stability, to determine the soil

    properties in that area and to purpose the retaining wall structure design. “Upon

    receiving their technical report, the department will ensure swift suitable measures

    are taken to solve this problem” he assured.

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    3.2 Objective

    a) To assess the slope stability

    b) To determine the soil properties in that area

    c) To propose the retaining wall structure design

    3.3 Slope details

    Location : Jalan Bantayan Minintod, Kota Kinabalu, Sabah.

    Slope physical properties :

    a) Steep slope

    b) Clayey looks

    c) Place is currently under construction to improve the safety of factor

    14m

    7m

    =63.435

    Figure 3.2 .1 : Slope of location

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    Based from the sketching of the slope;

    15.653sin 90 = 14sin

    x = 63.435 m

    3.4 Work Flow Chart

    Site Visit

    1) Sieve analysis

    Soil Sampling

    3) Atterberg Limit Test2) Compaction Test

    Soil Classification

    4) Direct Shear Test

    Soil Engineering Properties

    Cullman Method GeoStudioSlope Stability Analysis

    Retaining Wall DesignRankine Method QuickRWall 4.0

    Recommendation of Retaining Wall

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    4.0 Methodology, Results & Discussion

    4.1 Experiment 1: Sieve Analysis

    Objective:

    To classify soil sample according to USCS standard based on its grain size distribution.

    Results:

    Mass of oven-dry specimen, = 2500

    Sieve

    Opening

    (mm)

    Sieve

    weight

    before

    sieving (g)

    Sieve weight

    + weight of

    soil retained

    after sieving

    (g)

    Mass

    retained

    (g)

    % Mass

    retained

    Cumulative

    % mass

    retained

    % Finer

    3.35 1017 1563 546

    27.43718

    593

    27.437185

    93

    72.562

    814

    2.36 1039 1253 214

    10.75376

    884

    38.190954

    77

    61.809

    045

    2 1077 1121 44

    2.211055

    276

    40.402010

    05

    59.597

    99

    1.4 979 1114 135

    6.783919

    598

    47.185929

    65

    52.814

    07

    0.6 928 1147 219

    11.00502

    513

    58.190954

    77

    41.809

    045

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    0.425 793 872 79

    3.969849

    246

    62.160804

    02

    37.839

    196

    0.3 827 1192 365

    18.34170

    854

    80.502512

    56

    19.497

    487

    0.15 790 1007 217

    10.90452

    261

    91.407035

    18

    8.5929

    648

    0.075 795 936 141

    7.085427

    136

    98.492462

    31

    1.5075

    377

    Pan 1004 1034 30

    1.507537

    688 100 0

    = –

    = 2500 – 1990

    = 510

    Since the mass loss of soil after sieving is less than 2% of total weight of soil before, the

    data is acceptable.

    Analysis of Data:

    The soil will be classified according to USCS standard step by step.

    Table 4.1.2: Data from Sieve Analysis

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    a) The soil is a „coarse -grained soils‟ because more than 50% of the soils is retaine d

    on No. 200 sieve. (The percentage retained of soils on No. 200 sieve is, 100% −

    1.5075% = 98.4925% )

    b) Thus, in accordance to plasticity chart, the fraction of soil is low plasticity clay.

    (The analysis using the plasticity chart is explained further in the next

    experiment; The Atterberg Limits)

    Conclusions:

    Based on the classification of soils using USCS standard, the type of soils that was

    experimented is low plasticity clay. Thus, the type of soil is coarse with a fraction of low

    plasticity clay. Since t he soil if of coarse type, the experiment to determine the soil‟s

    angle of internal friction and its cohesion is by shear box testing.

    4.2 Experiment 2: Atterberg Limits Test

    Objective

    To determine the liquid limit and plastic limit of sample

    Results

    The equations used to obtain the result are:

    Mass of water = Mass of container + wet soil - (Mass of container + dry soil)

    Mass of dry soil = (Mass of container + dry soil) - (Mass of container)

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    Moisture content (%) =Mass of water

    Mass of dry soil × 100%

    Test Number 1 2 3 4 5

    Penetration (mm)

    28

    .9

    2

    7

    28

    .5

    21

    .6

    20

    .2

    23

    .3

    20

    .1

    21

    .7

    20

    .2

    27

    .7

    25

    .7

    26

    .7

    33

    .8

    32

    .7

    34

    .9

    Average

    Penetration (mm) 28.13 21.7 20.667 26.7 33.8

    Mass of Container(g) 8.119 7.928 22.501 21.058 19.575

    Mass of container

    + Wet Soil (g) 10.9113 9.735 24.222 26.132 24.410

    Mass of container

    + Dry Soil (g) 10.261 9.348 23.856 24.974 23.216

    Mass of Water (g) 0.649 0.387 0.3663 1.158 1.194

    Mass of Dry Soil

    (g) 2.141 1.419 1.354 3.916 3.640

    Moisture Content

    (%) 30.342 27.265 27.051 29.573 32.797

    Container Number 1 2 3 4

    Mass of Container (g) 8.059 87.7212 7.6516 87.2409

    Mass of Container + Wet Soil 8.8985 89.2477 9.4797 89.6503

    Table 4.2.1: Data for Casagrande Method

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    (g)

    Mass of Container + Dry Soil

    (g) 8.7561 89.0148 9.1579 89.2081

    Mass of water (g) 0.1424 0.2329 0.3218 0.4422

    Mass of Dry Soil (g) 0.6971 1.2936 1.5063 1.9672

    Moisture Content (%) 20.427 18.004 21.364 22.4786

    Analysis

    a) To determine the liquid limit of the sample by using Casagrande method, the

    graph of moisture content against number of blows is plotted on the semi-log

    graph. The value of liquid limit (LL) is the correspondent value of moisture

    content when the number of blows is 25.

    0

    5

    10

    15

    20

    25

    30

    35

    40

    0 5 10 15 20 25 30 35

    P e n e t r a t i o n

    ( m m

    )

    Moisture Content (%)

    Table 4.2.2: Data for Plastic Limit

    Figure 4.2.1: Graph of Moisture Content Vs Number of Blows

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    Therefore, the value of liquid limit for the sample is 26.80%

    b) The average value of plastic limit:

    PL = 20.427+18.004+21.364+22.4794

    = 20.568%

    c) The value of Plastic Index:

    PI = LL - PL

    = 26.80-20.568

    = 6.232%

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    d) Based on the plasticity chart above, the value of Liquid Limit and Plastic Index

    fall at the region of CL or OL. Since the sample does not contain organic matter,

    the sample can be classified as CL which means low plasticity clay or lean clay.

    Conclusion

    Therefore, the sample taken has a liquid limit of 26.80%, plastic limit of 20.0568% and

    plastic index of 6.232%. This sample is classified as low plasticity clay or lean clay.

    4.3 Experiment 3: Shear Box Test

    Objective:

    Figure 4.2.3: Plasticity Chart

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    To determine the cohesion and angle of internal friction of a dry granular soil.

    Results:

    a) Loose States

    Table for Shear Load versus time (Loose States) with corresponding weights

    Times

    (s)

    Shear Load (N)

    5.5kg 15.5kg 25.5kg

    20 0.6 0 0

    40 2.9 0 0

    60 6.7 4.3 0

    80 10.8 12.4 0

    100 5.1

    120 13.9

    Table for Vertical Displacement versus time (Loose States) with corresponding weights

    Times

    (s)

    Shear Load (N)

    5.5kg 15.5kg 25.5kg

    20 7.2 5 2.1

    40 50.8 27.5 6.8

    60 91.1 61.9 8.1

    80 86.2 9.5

    100 35.2

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    120 68.8

    Table for Horizontal Displacement versus time (Loose States) with corresponding

    weights

    Times

    (s)

    Shear Load (N)

    5.5kg 15.5kg 25.5kg

    20 0 1.6 0

    40 0 6.9 29.1

    60 69.2 12.5 24.8

    80 34.1 21.2

    100 19.3

    120 17.1

    140 -28.1

    b) Dense States

    Table for Shear Load versus time (Dense States) with corresponding weights

    Times

    (s)

    Shear Load (N)

    5.5kg 15.5kg 25.5kg

    20 3.2 4 0

    40 4.6 5.8 2.8

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    60 6.8 8.4 5.8

    80 8.8 8.4 9.8

    100 10.2 11.8

    Table for Vertical Displacement versus time (Dense States) with corresponding weights

    Times

    (s)

    Shear Load (N)

    5.5kg 15.5kg 25.5kg

    20 34.2 0 17

    40 84.4 0 20.2

    60 94 8 33.2

    80 94 48.4 70

    100 89.6 110

    120 134.2 17

    Table for Horizontal Displacement versus time (Dense States) with corresponding

    weights

    Times Shear Load (N)

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    (s) 5.5kg 15.5kg 25.5kg

    20 0 0 4.2

    40 10 0 8

    60 24.4 0 9.8

    80 33.4 1 11

    100 1 13.2

    120 1

    Calculation:

    a) Loose States

    • For case no. 1 where the mass of the hanger is 5.5kg:

    The value of Normal stress, σ =

    =

    = 14987.5 Nm -2

    The value of Shear stress, τ = .. .

    = 3000 Nm -2

    • For case no. 2 where the mass of the hanger is 15.5kg:

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    The value of Normal stress, σ =

    =

    = 42237.5 Nm -2

    The value of Shear stress, τ = .. .

    = 3444.444 Nm -2

    • For case no. 3 where the mass of the hanger is 25.5kg:

    The value of Normal stress, σ =

    =

    = 69487.5 Nm -2

    The value of Shear stress, τ = .. .

    = 3861.111Nm -2

    Data for shear stress and normal stress (loose states)

    Shear stress, τ (kN/m 2) Normal stress, σ (kN/m 2)

    3.000 14.9875

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    3.444 42.2375

    3.861 69.4875

    b) Dense States

    • For case no. 1 where the mass of the hanger is 5.5kg:

    The value of Normal stress, σ =

    =

    = 14987.5 Nm -2

    The value of Shear stress, τ = .. .

    = 2444.444 Nm-2

    • For case no. 2 where the mass of the hanger is 15.5kg:

    The value of Normal stress, σ =

    =

    = 42237.5 Nm -2

    The value of Shear stress, τ = .. .

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    25

    = 2833.333 Nm -2

    • For case no. 3 where the mass of the hanger is 25.5kg:

    The value of Normal stress, σ =

    =

    = 69487.5 Nm -2

    The value of Shear stress, τ =.

    . .

    = 3277.780 Nm -2

    Data for shear stress and normal stress (dense states)

    Shear stress, τ (kN/m 2) Normal stress, σ (kN/m 2)

    2.444 14.9875

    2.833 42.2375

    3.278 69.4875

    a) Loose Soil

    τ = c + σ tan ø

    From graph, the apparent cohesion, c = 2000 N/m 2

    tan ø = (τ – c)/ σ

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    = (3861.111 - 2000) Nm -2 / 69487.5 Nm -2

    = 0.0268

    Angle of internal friction, Ø = 1.534 ˚

    b) Dense Soil

    τ = c + σ tan ø

    From graph, the apparent cohesion, c = 1875 N/m 2

    tan ø = (τ – c)/ σ

    = (3277.78 – 1875) Nm -2 / 69487.5 Nm -2

    = 0.020

    Angle of internal friction, Ø = 1.160 ˚

    0

    10000

    20000

    30000

    40000

    50000

    60000

    70000

    80000

    0 10000 20000 30000 40000 50000 60000 70000 80000

    Figure 4.3 .1 : Loose ( Shear stress vs normal stress )

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    Discussion

    a) Based on the result obtained, the angle of internal friction, ø for loose state is

    1.534° and for dense state is 1.160°. Conclusion:

    The cohesion for loose is 2000 N/m 2 and dense state is 1875 N/m 2 while angle of

    internal friction for loose and dense state is 1.534˚and 1.160˚respectively.

    4.4 Experiment 4: PROCTOR COMPACTION TEST

    Objective :

    0

    10000

    20000

    30000

    40000

    50000

    60000

    70000

    0 10000 20000 30000 40000 50000 60000 70000

    Figure 4.3 .1 : Dense ( Shear stress vs normal stress )

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    To determine the maximum dry unit weight of compaction of soils.

    Results :

    Mass of dry soil used : 2.5 kg

    Classification of soil : SW (USCS Classification)

    Measurement of mould :d=100 mm, h=100 mm

    Volume of mould :7.85x10 -4 m3

    Mass of base : 3.242 kg

    Trial No 1 2 3 4 5

    Mass of wet soil + mould +

    base (kg)

    5.22 5.312 5.242 5.192 5.169

    Mass of wet soil (kg) = W 1.378 1.47 1.381 1.342 1.327

    Buld density of soil, ρ (kg/m 3) 1869.74 1994.57 1873.81 1820.9 1800.54

    Container No 1 2 3 4 5

    Mass of container (g) 84 8 8 7 7

    Mass of wet soil + container

    (g)

    104 28 28 26 27

    Mass of dry soil + container (g) 10.62 24.02 23.53 21.52 22.07

    Mass of water (g) 3.38 3.98 4.47 4.48 4.93

    Mass of dry soil (g) 16.62 16.02 15.53 14.52 15.07

    Water content (%), w 0.169 0.199 0.224 0.236 0.247

    Dry density of soil, ρd(kg/m 3) 1599.44 1663.53 1530.89 1473.22 1443.9

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    =ρ/(1+w)

    Table 4.4.1: Results of the Standard Proctor Compaction Test.

    Graph 4.4.1: Graph of Proctor Curve for the soil sample.

    From graph 4.4.1,

    , = 1663.53 3

    , = 0.19 %

    , = × 9.81

    = 1663.53 × 9.81

    = 16.32 / 3

    Conclusion :

    1400

    1450

    1500

    1550

    1600

    1650

    1700

    0 0.05 0.1 0.15 0.2 0.25 0.3

    D r y

    D

    e n s

    i t y o

    f s o

    i l

    Water Content (%)

    Proctor Curve

    1663.53 kg/m^3

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    The maximum dry density is 1663.53 kg / m 3. Therefore, the unit weight is 16.32 kN/m 3

    .

    4.5 Determination of Factor of Safety (FOS) for Slope

    To determine the factor of safety for the slope, the group are using manual calculation

    and software.

    I. Manual Calculation (Culmann Method)

    For the manual calculation, the equation used is;

    =4 sin β cos ∅

    (1 − cos( −∅ )

    cd =c

    F.Sc

    tan ∅ =tan ∅

    . ∅

    From the shear box testing result, ∅= 1.160 °

    From graph, the apparent cohesion, c = 1875 N/m 2

    Safe depth of cut = 14m

    Unit weight of the soil, = 16.32 kN / m 2

    Angle of horizontal to cut surface, β = 63.435

    (The angle of friction, ∅ used is the result from the dense soil because it has lower value

    of ∅ compared to loose sample and this will result in lowest possible value of the factor

    of safety for the slope.)

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    Calculation

    F.S ф фd cd F.Sc

    1 1.16 16.59 0.113

    2 0.58 16.87 0.111

    3 0.38 16.96 0.11

    = 0.111

    0

    1

    2

    3

    4

    0 1 2 3 4F.S ф

    F.Sc

    Figure 4.4.2 : F.Sc vs F.S ф

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    Significance Factor of Safety for Design,

    Safety Factor Significance

    Less than 1.0 Unsafe

    1.0 - 1.2 Questionable safety

    1.3 – 1.4 Satisfactory for cuts, fills; questionable for dams

    1.5 – 1.75 Safe for dams

    From the above table, since the = 0.111 which is less than 1.0,

    therefore the slope is unsafety and a retaining wall is needed to avoid slope failure.

    II. Software Calculation

    For software calculation, the group is using software called Geoslope Design. By

    inputting the necessary parameter such as the slope‟s height, angle, angle of internal

    friction, unit weight and cohesion. The result is as follows.

    Source: Liu C. & Evett J. B., (2005). Soils and Foundations. Singapore: Pearson Prentice Hall

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    The green coloured area is the critical area where the slope failure may occur. The

    factor of safety for the slope is 0.109 which is less than 1.0. Thus, the slope is unsafe.

    There is also other possible slope failure but since the slope failure is the most critical.

    Comparison for manual calculation and software calculation

    Manual Software

    Factor of safety = 0.111 Factor of safety = 0.109

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    5.0 RETAINING WALL DESIGN

    5.1 Proposed Wall Retaining Structure (Manual)

    Kh = 1 – sin υ 1 + sin υ

    Kp = 1+ sin υ 1− sin υ

    = 0.960 = 1.041

    Ph = 1/2 Kh H 2 ɣ Pp = 1/2 Kp H 2 ɣ

    = 1/2 (0.960) (16.5) 2(16.32) = 1/2 (1.041) (12.5) 2(16.32)

    123

    4

    5

    6

    7

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    = 2132.698 kN/m = 1327.275 kN/m

    Component Weight Component (kN/m) Moment arm (m) Righting moment

    kN.m/m

    1 14x15x23.5x0.5 = 822.5 7.83 6440.175

    2 2x14x23.5 = 658 10.5 6909

    3 14x15x23.5x0.5 = 822.5 13.167 10829.583

    4 21x2.5x23.5 = 1233.75 10.5 12954.375

    5 2x10x23.5 = 470 10.5 4935

    6 14x5x16.32x0.5 = 571.2 14.83 8472.8

    7 4.5x16.32x14 = 1028.16 18.75 19278

    Total ΣMv = 5606.11 ΣMr = 69818.928

    Analyse the factor of safety for Sliding.

    F.S sliding = (μ)( ΣV) + Pp = 0.55 5606 .11 +1327.2752132 .698

    = 2.068 > 1.50 Safe against sliding

    Analyse the factor of safety for Overturning.

    Mo = Ph (H/3) = (2132.698) (16.5/ 3)

    = 11729.9367 kN.m/m

    Noted that for the calculation of active and passive pressure, the cohesion isconsidered cohesion less.

    Noted that the passive pressure at toe is not considered in the manualcalculation.

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    F.S overturning = ΣMrΣMo =69818.928

    11729.9367

    = 5.95 > 1.50 Safe against overturning

    Analyse the factor of safety for Bearing Capacity Failure.

    x = ΣMAΣV =ΣMr − ΣMo

    ΣV = 69818.928 − 11729.937

    5606.11

    = 10.362 m

    e = Base2

    – x = 212

    − 10.362 = 0.138< L/6 (i.e. 21/6 = 3.5)

    My = Qe = 5606.11 (0.138) = 775.064 kN.m

    X = Base2

    = 212

    = 10.5 m

    Iy =3

    12=

    1(21) 3

    12= 771.75 m 4

    A = bh = (1)(21) = 21 m 2

    q =

    ± ±

    qL = 5606 .1121

    + 775.064(10.5)771.75

    = 277.503 / ^2

    qR = 5606.1121

    − 775.064(10.5)771.75

    = 256.413 / ^2

    F.S bearing capacity failure 277.503 / ^2 < 620 / ^2 (Assumed allowable

    pressure bearing)

    620277.503

    = 2.234 > 1.5 Safe against bearing capacity

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    5.2 Proposed Wall Retaining Structure (Software)

    For the design of the retaining wall using software, QuickRWall is used. The following

    picture is the recommended retaining walls.

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    5.3 CONLUSION & RECOMMENDATION

    For conclusion, the slope is unsafe since the factor of safety (FOS) is considered

    in manual calculation or from using software is less than 1. The slope is considered fail

    and unsafe. The soil has a liquid limit of 26.80%, plastic limit of 20.0568% and plastic

    index of 6.232%. This sample is classified as low plasticity clay or lean clay known from

    the previous experiment. Thus, a retaining wall is recommended to be built to avoid

    slope failure in the future. Based from all the data obtained, a retaining wall for the

    slope is assumed. It is assumed by using the Rankine method including using the

    software known as QuickRWall 4.0 to get the most suitable retaining wall for the slope.

    Since The allowable pressure bearing for the structure is 620 kPa which for the design

    assumed is only 277.530 kPa thus making the structure safe against failure. The friction

    coefficient assumed in the manual calculation and software is 0.55. As for the calculation

    of active and passive pressure, the cohesion is considered cohesion less soil, thus using

    the equation of a cohesion less soil of Rankine Theory while the software's calculation

    includes the cohesion. Also, the active pressure's height is from top structure to bottom

    of foundation while the passive pressure is from bottom structure to top of foundation.

    Noted that the passive pressure at toe is not considered in the manual calculation as it is

    calculated separately from the manual. That is why the answer for factor of safety of

    overturning is different from software's calculation. The selection criteria is not based on

    the cost, difficulty in building the retaining wall and other factors. Since the most

    important factor in this project is only to avoid slope failure, other factor such as the

    cost of building and the difficulty in building the retaining wall will not be discussed.

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    6.0 REFERENCE

    Bromhead, E.N. 1992. The stability of slopes . Blackie, London.

    Chandler, R.J. 1991. Slope stability engineering . Thomas Telford, London.

    Craig, R. F. Mekanik Tanah . Johor Darul Ta'zim: Universiti Teknologi Malaysia.

    Leventhal, A.R. and Mostyn, G.R. 1987, Slope stabilisation techniques and their

    application in Slope Instability and Stabilisation , ed. by B. Walker and R. Fell,

    Balkema, Rotterdam.

    Liu, C. and Evett, J. B. (2005). Soils and Foundations. Singapore: Pearson Prentice Hall.