path integral quantum monte carlo consider a harmonic oscillator potential a classical particle...
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Path Integral QuantumMonte Carlo
• Consider a harmonic oscillator potential
• a classical particle moves back and forth periodically in such a potential
• x(t)= A cos(t) • the quantum wave function can be thought
of as a fluctuation about the classical trajectory
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Feynman Path Integral• The motion of a quantum wave function is
determined by the Schrodinger equation
• we can formulate a Huygen’s wavelet principle for the wave function of a free particle as follows:
• each point on the wavefront emits a spherical wavelet that propagates forward in space and time
( , ) ( , ; , ) ( , )b b a b b a a a ax t dx G x t x t x t
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Feynman Paths• The probability amplitude for the particle to
be at xb is the sum over all paths through spacetime originating at xa at time ta
2( )1( , ; , ) exp
2 ( ) 2( )b a
b b a ab a b a
i x xG x t x t
i t t t t
( , ) ( , ; , ) ( , )b b a b b a a a ax t dx G x t x t x t
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Principal Of Least Action
• Classical mechanics can be formulated using Newton’s equations of motion or in terms of the principal of least action
• given two points in space-time, a classical particle chooses the path that minimizes the action
0
,
,0
x t
x
S Ldt Fermat
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Path Integral
• L is the Lagrangian L=T-V
• similarly, quantum mechanics can be formulated in terms of the Schrodinger equation or in terms of the action
• the real time propagator can be expresssed as
/0( , , ) iS
paths
G x x t A e
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Propagator
• The sum is over all paths between (x0,0) and (x,t) and not just the path that minimizes the classical action
• the presence of the factor i leads to interference effects
• the propagator G(x,x0,t) is interpreted as the probability amplitude for a particle to be at x at time t given it was at x0 at time zero
/0( , , ) iS
paths
G x x t A e
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Path Integral
• We can express G as
0 0 0( , ) ( , , ) ( ,0) 0x t G x x t x dx t
/0 0( , , ) ( ) ( ) niE t
n nn
G x x t x x e
0 0( , , ) ( ) ( ) nEn n
n
G x x x x e
• Using imaginary time =it/
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Path Integrals
• Consider the ground state
• as
0200 0 0( , , ) ( ) EG x x ex
0 0( , , ) ( ) ( ) nEn n
n
G x x x x e
• hence we need to compute G and hence S to obtain properties of the ground state
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Lagrangian• Using imaginary time =it the Lagrangian for a
particle of unit mass is2
1( )
2
dxL V x E
d
21
2
( )1( , ) ( )
2 ( )j j
j j j
x xE x V x
• divide the imaginary time interval into N equal steps of size and write E as
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Action
• Where j = j and xj is the displacement at time j
1
0
211
20
( , )
( )1( )
2 ( )
N
j jj
Nj j
jj
S i E x
x xi V x
21
2
( )1( , ) ( )
2 ( )j j
j j j
x xE x V x
0
,
,0
x t
x
S Ldt
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Propagator• The propagator can be expressed as
211
20
( )1( )
2 ( )
Nj j
jj
x xV x
iSe e
21
12
0
( )1( )
2 ( )
0 1 1( , , ) ...
Nj j
jj
x xV x
NG x x N A dx dx e
/0( , , ) iS
paths
G x x t A e
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Path Integrals
• This is a multidimensional integral
• the sequence x0,x1,…,xN is a possible path
• the integral is a sum over all paths
• for the ground state, we want G(x0,x0,N ) and so we choose xN = x0
• we can relabel the x’s and sum j from 1 to N
211
20
( )1( )
2 ( )
0 1 1( , , ) ...
Nj j
jj
x xV x
NG x x N A dx dx e
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Path Integral
• We have converted a quantum mechanical problem for a single particle into a statistical mechanical problem for N “atoms” on a ring connected by nearest neighbour springs with spring constant 1/( )2
21
21
( )1( )
2 ( )
0 0 1 1( , , ) ...
Nj j
jj
x xV x
NG x x N A dx dx e
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Thermodynamics
• This expression is similar to a partition function Z in statistical mechanics
• the probability factor e- E in statistical mechanics is the analogue of e- E in quantum mechanics
=N plays the role of inverse temperature =1/kT
21
21
( )1( )
2 ( )
0 0 1 1( , , ) ...
Nj j
jj
x xV x
NG x x N A dx dx e
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Simulation• We can use the Metropolis algorithm to simulate the
motion of N “atoms” on a ring
• these are not real particles but are effective particles in our analysis
• possible algorithm:
• 1. Choose N and such that N >>1 ( low T) also choose ( the maximum trial change in the displacement of an atom) and mcs (the number of steps)
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Algorithm• 2. Choose an initial configuration for the
displacements xj which is close to the approximate shape of the ground state probability amplitude
• 3. Choose an atom j at random and a trial displacement xtrial ->xj +(2r-1) where r is a random number on [0,1]
• 4. Compute the change E in the energy
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Algorithm
• If E <0, accept the change
• otherwise compute p=e- E and a random number r in [0,1]
• if r < p then accept the move
• if r > p reject the move
2 2
1 1
2 2
1 1
1 1( )
2 2
1 1( )
2 2
j trial xtrial jtrial
j j j jj
x x x xE V x
x x x xV x
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Algorithm• 4. Update the probability density P(x). This
probability density records how often a particular value of x is visited
Let P(x=xj) => P(x=xj)+1 where x was position chosen in step 3 (either old or new)
• 5. Repeat steps 3 and 4 until a sufficient number of Monte Carlo steps have been performed
qmc1
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Excited States• To get the ground state we took the limit • this corresponds to T=0 in the analogous statistical
mechanics problem
• for finite T, excited states also contribute to the path integrals
• the paths through spacetime fluctuate about the classical trajectory
• this is a consequence of the Metropolis algorithm occasionally going up hill in its search for a new path