parabola volume 31, issue 2 (1995)...1. by pythagoras' theorem he then triangle has sides 2, a,...

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Parabola Volume 31, Issue 2 (1995) 1

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$Page 1: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

Parabola Volume 31, Issue 2 (1995)

1

$Page 2: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

$Page 3: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

$Page 4: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

$Page 5: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

$Page 6: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

$Page 7: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

$Page 8: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

$Page 9: Parabola Volume 31, Issue 2 (1995)...1. By Pythagoras' Theorem he then triangle has sides 2, a, 25 — Notice that Diophantus allowed fractional solutions obtains a = to his problems,$

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