p. 610 4, 10, 12, 15, 17, 20, 24, 27, 31, 36, 40, 44, 47, 56, 59, 60, 62, 70, 76
TRANSCRIPT
p. 610 4, 10, 12, 15, 17, 20, 24, 27, 31, 36, 40, 44, 47, 56, 59, 60, 62, 70, 76
Objective: factor polynomials completely including grouping methods
1. GCF: greatest common factor2. Patterns:
▪ Difference of Squares: a2 – b2 = (a – b)(a + b)
▪ Perfect Square Trinomial: a2 + 2ab + b2 = (a + b)2
▪ Perfect Square Trinomial: a2 - 2ab + b2 = (a - b)2
3. “un-FOIL”4. Grouping: What we’re doing today!
4x(x -3) + 5(x-3) We have 4x + 5 of the (x-3)’s. Another way to write it: (4x + 5)(x-3)
2y2(y - 5) – 3(5 – y) Are y – 5 and 5 – y the same thing? No, but –(5 - y) = -5 + y = y - 5 Now 2y2(y - 5) – 3(5 – y) = 2y2(y - 5) +
3(y - 5) (2y2 + 3)(y – 5)
x3 +2x2 + 8x + 16 The first two terms have an x2 in
common; the two last terms have 8 in common.
x2 (x+ 2) + 8(x + 2) (x2 + 8)(x + 2) Can you break this down any further?
r2 +4r + rs + 4s r( r + 4) + s(r + 4) (r + s) (r + 4)
r2 +4r + 4s + rs r(r + 4) + s(4 + r) (r + s)(r + 4)
r2 + rs + 4r + 4s r(r + s) + 4(r + s) (r + 4)(r + s)
Any way you group this one, it comes out the same.
x3 -10 – 5x + 2x2
(x + 2)(x2 – 5)
x2 – 4x -3
Prime!
3x3 – 21x2 – 54x
3x(x + 2)(x – 9)
8d3 + 24d
8d(d2 + 3)
A kitchen drawer has a volume of 768 in3. If the dimensions are as shown, what are the length, width, and height of the drawer?
(w)(w + 4)(16 – w) = 768 -w3 + 12w2 + 64w – 768 = 0 -w2(w - 12) + 64(w – 12) = 0 (-w2 + 64)(w – 12) = 0 Possible Solutions: w = 8 (12, 8) or w = 12 (4,
16)
w w + 4
16- w