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Orbits • Read Your Textbook: Foundations of Astronomy – Chapter 5 • Homework Problems – Review Questions: 3, 4, 5, 9, 10 – Review Problems: 1, 3, 4 – Web Inquiries:

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Orbits. Read Your Textbook: Foundations of Astronomy Chapter 5 Homework Problems Review Questions: 3, 4, 5, 9, 10 Review Problems: 1, 3, 4 Web Inquiries:. Kepler’s Laws. I. Planets orbit the sun in ellipses with the sun located at one focus point. Ellipses. - PowerPoint PPT Presentation

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Page 1: Orbits

Orbits• Read Your Textbook: Foundations of Astronomy

– Chapter 5

• Homework Problems– Review Questions: 3, 4, 5, 9, 10– Review Problems: 1, 3, 4– Web Inquiries:

Page 2: Orbits

Kepler’s Laws• I. Planets orbit the sun in ellipses with the sun located at one

focus point.

Page 3: Orbits

Ellipsesa (1-e) = closest approach e = eccentricity

Page 4: Orbits

Ellipsesa (1- e) = closest approach (perihelion)

a (1+ e) = farthest away (aphelion)

Circle e = 0

radius = a

Ellipse e > 0

Page 5: Orbits

Kepler’s II LawA Planet’s Orbital Vector Sweeps Out Equal Area

in Equal Intervals of Time

Page 6: Orbits

Equal Area in Equal TimeThe time required to travel from point A’ to B’ is

equal to the time required to travel from A to B.

Page 7: Orbits

Angular MomentumAngular Momentum L,

is the product of a planet's mass (m),

orbital velocity (v)

and distance from the Sun (R).

The formula is simple: L = m v R,

where R is a function of e, the eccentricity.

Page 8: Orbits

Kepler’s III LawPeriod2/Distance3 = constant for any system

If the orbital period (P) is measured in years,

and the average distance (a) is measured in A.U.,

the constant for the solar system is 1.000.

P2 = a3

Page 9: Orbits

Closest ApproachFor orbits around the Sun,

critical points are perihelion and aphelion.

The corresponding points for orbits around

the Earth are perigee and apogee.

The planetary orbital ellipses are very nearly circular.

(i.e. the eccentricity is nearly zero, Earth e = 0.03)

Circular orbits are a good approximation.

Page 10: Orbits

Circular Orbit ApproximationThe Circular Velocity is the rate at which an

object would move in a circular orbit around

a given massive body.

Examples might be a satellite around the Earth

or a planet around the Sun.

The equation for circular velocity is:

Vcir= (GM/R)1/2

Page 11: Orbits

Centripetal Accelerationa = v2 r

Centripetal Force = m a

= m v2 r

Since velocity is a vector, even an object with constant

speed that does not travel in a straight line, must

experience an acceleration since acceleration is a

change in velocity. Velocity is a vector which

includes speed AND direction.

Page 12: Orbits

Two Types of Energy

Potential Energy Kinetic Energy

Page 13: Orbits

Potential Energy• The energy associated with an objects position• The object has the potential to do WORK• Work was done to give it this potential

Examples:

Ohh #$%*@!

Chop, Chop

Page 14: Orbits

Potential Energy• The motor pulls the cart up against gravity

WORK = Force x distance

mg x height

Page 15: Orbits

Potential Energy• The motor pulls the cart up against gravity

WORK = Force x distance

mg x height

• Muscles do work against the tension in the bow string

Page 16: Orbits

Potential Energy• The motor pulls the cart up against gravity

WORK = Force x distance

mg x height

• Muscles do work against the tension in the bow string

• Muscles do work against gravity to lift the

axe above the ground

Page 17: Orbits

Potential Energy• The roller coaster cart, the bow and the axe were all

given potential energy. The change in the potential energy

is identical to the work done.

• These objects now have the potential to do work and

convert that stored energy.

Page 18: Orbits

Kinetic Energy• The energy associated with an objects motion.

KE = 1/2 m v2

m = mass

v = velocity

Without velocity, there is no KE

Chop, Chop

Page 19: Orbits

Energy• When work is done, there is a change in energy.

• Energy is a conserved quantity, and remains unchanged in a physical system.

• TOTAL ENERGY, not Kinetic Energy or Potential Energy by themselves.

Page 20: Orbits

The Simple Pendulum• The pendulum swings to and fro,

where it stops, conservation of energy knows.

TOTAL ENERGY = Potential Energy + Kinetic Energy

Page 21: Orbits

The Simple Pendulum The total energy of this system is zero.

Page 22: Orbits

The Simple Pendulum The total energy of this system is zero.

This simple pendulum could be the

sway in a grandfather clock,

a child on a swing,

a hypnotists watch, etc.

Page 23: Orbits

The Simple Pendulum Suppose someone does work against

gravity to give it some potential energy?

Page 24: Orbits

The Simple Pendulum Suppose someone does work against

gravity to give it some potential energy?

The work done = Force x Distance

Force = m g

Distance = h

The work done = potential energy gained

= m g h

h

Page 25: Orbits

The Simple Pendulum The total energy of the system is

now (m g h), reflecting the work done

to the system.

What happens when we let go of the pendulum?

h

Page 26: Orbits

To and Fro

Page 27: Orbits

To and Fro

Page 28: Orbits

To and Fro

Page 29: Orbits

To and Fro

Page 30: Orbits

To and Fro

Page 31: Orbits

To and Fro

Page 32: Orbits

To and Fro

h

The pendulum swingsuntil it has reached thesame height on the otherside, before pausing tooscillate back.

Page 33: Orbits

Total EnergyA projectile has an amount of kinetic energy given by

K.E. = 1/2 m V2

It has a potential energy relative to earth's surface of P.E. = - mGM/R

The total energy is conserved so that

Total Energy = K.E. + P.E.

Total Energy = 1/2 m V2 - mGM/R

In order to escape earth's gravity you have to have

Total Energy > 0, so the critical point is when the energy = 0.

Page 34: Orbits

Escape VelocityThe Escape Velocity is the velocity

an object (of ANY mass) must have in order to leave

the gravitational field of a massive body.

It depends on the total amount of energy an object has.

There is an escape velocity from the Earth's surface,

from the Sun's surface, even from the solar system,

and it depends on how massive that body is and

how far you are away from the body.

Page 35: Orbits

Escape Velocity0 = 1/2 m V2 - mGM/R

V2/2 = GM/R

Vesc = (2GM/R)1/2

The escape velocity at the earth's

surface is = 11.2 km/sec.

Page 36: Orbits

OrbitsObject must have

kinetic energy

greater than the

gravitational

potential energy

needed to escape

the earth. The

velocity associated

with this kinetic

energy is the

escape velocity.

Page 37: Orbits

Escape Velocity and Orbits

Conic Section Velocity Total Energy Orbit Hyperbola V > Vesc > 0 Unbound Parabola V = Vesc = 0 1 pass Ellipse V < Vesc < 0 a(1-e), a(1+e) Circle V = Vcirc Minimum a = radius

e = 0

e > 0

e >> 0