options - examples

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OPTIONS - EXAMPLES MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

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OPTIONS - EXAMPLES. SOME STRATEGIES. COVERED STRATEGIES : Take a position in the option and the underlying stock. SPREAD STRATEGIES : Take a position in 2 or more options of the same type (A spread ). COMBINATION STRATEGIES : Take a position in a mixture of calls and puts. - PowerPoint PPT Presentation

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Page 1: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

OPTIONS - EXAMPLES

Page 2: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

COVERED STRATEGIES: Take a position in the option and the underlying stock.

SPREAD STRATEGIES: Take a position in 2 or more options of the same type (A spread).

COMBINATION STRATEGIES: Take a position in a mixture of calls and puts.

SOME STRATEGIES

Page 3: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

STANDARD SYMBOLS:◦ C = current call price, P = current put price◦ S0 = current stock price, ST = stock price at

time T◦ T = time to maturity◦ X = exercise price (or K in some books)◦P = profit from strategy

STAKES:◦ NC = number of calls◦ NP = number of puts◦ NS = number of shares of stock

TYPES OF STRATEGIES

Page 4: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

These symbols imply the following:◦ NC or NP or NS > 0 implies buying (going long)◦ NC or NP or NS < 0 implies selling (going short)

Recall the PROFIT EQUATIONS◦ Profit equation for calls held to expiration P = NC[Max(0,ST - X) – Cexp(rT)]

For buyer of one call (NC = 1) this implies P = Max(0,ST - X) - Cexp(rT) For seller of one call (NC = -1) this implies P = -Max(0,ST - X) + Cexp(rT)

Types of Strategies

Page 5: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

The Profit Equations (continued) Profit equation for puts held to expiration P = NP[Max(0,X - ST) - Pexp(rT)] For buyer of one put (NP = 1) this implies

P = Max(0,X - ST) - Pexp(rT) For seller of one put (NP = -1) this implies P = -Max(0,X - ST) + Pexp(rT)

Types of Strategies

Page 6: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

The Profit Equations (continued)◦Profit equation for stock P = NS[ST - S0] For buyer of one share (NS = 1) this

implies P = ST - S0

For short seller of one share (NS = -1) this implies

P = -ST + S0

Types of Strategies

Page 7: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Positions in an Option & the Underlying

Profit

STK

Profit

ST

K

Profit

ST

K

Profit

STK

(a) (b)

(c)

(d)

Page 8: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Bull Spread Using Calls

Bull Spread Using Calls: Buying a call option on a stock with a particular strike price and selling a call option on the same stock with a higher strike price.

Payoff from a Bull Spread:

Stock price Range

Payoff from Long Call Option

Payoff from Short Call Option

Total Payoff

ST ≥ K2

K1 < ST < K2

ST ≤ K1

ST - K1

ST - K1

0

K2 - ST 00

K2 - K1

ST ≥ K2

0

Page 9: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Bull Spread Using Calls

Ex: An investor buys $3 a call with a strike price of $30 and sells for $1 a call with a strike price of $35.

Payoff from a Bull Spread:

Stock price Range

Payoff from Long Call Option

Payoff from Short Call Option

Total Payoff

ST ≥ $35$30 < ST < $35ST ≤ $30

ST - $30 - $3ST - $30 -$30 - $3

$35 - ST +$10+$10+$1

$3ST - $32-$2

Page 10: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Bull Spread Using Calls

K1 K2

Profit

ST

Page 11: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Bull Spread Using Puts

K1 K2

Profit

ST

Page 12: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Bear Spread Using Puts-buying one put with a strike price of K2 and selling one put with a strike price of K1

K1 K2

Profit

ST

Page 13: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Bear Spread Using Calls

Stock price Range

Payoff from Long Call Option

Payoff from Short Call Option

Total Payoff

ST ≥ K2

K1 < ST < K2

ST ≤ K1

ST - K2

00

K1 - ST K1 - ST

0

-(K2 - K1) -(ST ≥ K1)0

Bear Spread: Buying a call option on a stock with a particular strike price and selling a call option on the same stock with a lower strike price.

Page 14: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Bear Spread Using Calls

Stock price Range

Payoff from Long Call Option

Payoff from Short Call Option

Total Payoff

ST ≥ $35$30 < ST < $35ST ≤ $30

ST - $3500

$30 - ST $30 - ST

0

-($35 - $30) -(ST ≥ $30)0

Example: An investor buys a call for $1 with a strike price of $35 and sells for $3 a call with a strike price of $30.

Page 15: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Bear Spread Using Calls

K1 K2

Profit

ST

Page 16: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A combination of a bull call spread and a bear put spread

If all options are European a box spread is worth the present value of the difference between the strike prices

If they are American this is not necessarily so.

Box Spread

Page 17: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Butterfly Spread Using Calls Butterfly Spread: buying a call option with a relative

low strike price, K1,, buying a call option with a relative high strike price. K3, and selling two call options with a strike price halfway in between, K2.Stock price Range

Payoff from First Long Call Option

Payoff from Second Long Call Option

Payoff from Short Calls

Total Payoff

ST ≥ K3

K2 < ST < K3

K2 < ST < K3

ST ≤ K1

ST - K1 ST - K1

ST - K1

0

ST - K3 000

-2(ST - K2) -2(ST - K2) 00

0K3 - ST ST - K1

0

Page 18: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Butterfly Spread Using Calls Example: Call option prices on a $61 stock are: $10 for a $55 strike, $7

for a $60 strike, and $5 for a $65 strike. The investor could create a butterfly spread by buying one call with $55 strike price, buying a call with a $65 strike price, and selling two calls with a $60 strike price.

Stock price Range

Payoff from First Long Call Option

Payoff from Second Long Call Option

Payoff from Short Calls

Total Payoff

ST ≥ $65$60 < ST <$65$55 < ST <$60ST ≤ $55

ST - $55ST - $55ST - $550

ST - $65000

-2(ST - $60) -2(ST - $60)00

0$65 - ST ST -$550

Page 19: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Butterfly Spread Using Calls

K1 K3

Profit

STK2

Page 20: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Butterfly Spread Using Puts

K1 K3

Profit

STK2

Page 21: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Calendar Spread Using Calls

Profit

ST

K

Page 22: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Calendar Spread Using Puts

Profit

ST

K

Page 23: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A Straddle Combination

Stock price Range

Payoff from Call Payoff from Put Total Payoff

ST ≥ KST < K

ST – K 0

0K - ST

ST - K K - ST

Straddle: Buying a call and a put with the same strike price and expirationDate.

Page 24: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A Straddle Combination

Stock price Range

Payoff from Call Payoff from Put Total Payoff

ST ≥ $70ST < $70

ST – $70 -$40 - $4

0 -$3$70 - ST - $3

ST - $77$63 - ST

Example: An investor buying a call and a put with a strike price of $70 and an expiration date in 3 months. Suppose the call costs $4 and the put $3.

Page 25: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A Straddle Combination

Profit

STK

Page 26: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Strip & StrapStrip: combining one long call with two long putsStrap: combining two long calls with one long put

Profit

K ST

Profit

K ST

Strip Strap

Page 27: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A Strangle Combinationbuying one call with a strike price of K2 and buying one put with a strike price of K1

K1 K2

Profit

ST

Page 28: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

BINOMIAL MODELS - EXAMPLES

A stock price is currently $20 In three months it will be either $22 or $18

Stock Price = $22

Stock Price = $18

Stock price = $20

Page 29: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Stock Price = $22Option Price = $1

Stock Price = $18Option Price = $0

Stock price = $20Option Price=?

A Call Option

A 3-month call option on the stock has a strike price of 21.

Page 30: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Consider the Portfolio: long D shares short 1 call option

Portfolio is riskless when 22D – 1 = 18D or D = 0.25

22D – 1

18D

Setting Up a Riskless Portfolio

Page 31: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Valuing the Portfolio(Risk-Free Rate is 12%)

The riskless portfolio is: long 0.25 sharesshort 1 call option

The value of the portfolio in 3 months is 22 ´ 0.25 – 1 = 4.50

The value of the portfolio today is 4.5e – 0.12´0.25 = 4.3670

Page 32: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Valuing the Option The portfolio that is

long 0.25 sharesshort 1 option

is worth 4.367 The value of the shares is

5.000 (= 0.25 ´ 20 ) The value of the option is therefore

0.633 (= 5.000 – 4.367 )

Page 33: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Generalization

A derivative lasts for time T and is dependent on a stock

S(1+a)=Su

ƒu

S(1-a)=Sd

ƒd

Page 34: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Generalization(continued) Consider the portfolio that is long D shares and

short 1 derivative

The portfolio is riskless when SuD – ƒu = Sd D – ƒd or

du

du

SSfƒ

D

SuD – ƒu

SdD – ƒd

Page 35: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Generalization(continued)

Value of the portfolio at time T is Su D – ƒu

Value of the portfolio today is (Su D – ƒu )e–rT

Another expression for the portfolio value today is S D – f

Hence ƒ = S D – (Su D – ƒu )e–rT

Page 36: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Generalization(continued)

Substituting for D we obtain ƒ = [ p ƒu + (1 – p )ƒd ]e–rT

where

aaep

rT

21

Page 37: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Risk-Neutral Valuation

ƒ = [ p ƒu + (1 – p )ƒd ]e-rT

The variables p and (1 – p ) can be interpreted as the risk-neutral probabilities of up and down movements

The value of a derivative is its expected payoff in a risk-neutral world discounted at the risk-free rate Su

ƒu

Sd

ƒd

p

(1 – p )

Page 38: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Original Example Revisited

Since p is a risk-neutral probability 20e0.12 ´0.25 = 22p + 18(1 – p ); p = 0.6523

Su = 22 ƒu = 1

Sd = 18 ƒd = 0

S ƒ

p

(1 – p )

Page 39: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Valuing the Option

The value of the option is e–0.12´0.25 [0.6523´1 + 0.3477´0] = 0.633

Su = 22 ƒu = 1

Sd = 18 ƒd = 0

0.6523

0.3477

Page 40: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Estimating pOne way of matching the volatility is to set

where s is the volatility and Dt is the length of

the time step. This is the approach used by Cox, Ross, and Rubinstein

12

1

Dt

rT

eaa

aep

s

Page 41: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A Two-Step Example

Each time step is 3 months K=21, r=12%

20

22

18

24.2

19.8

16.2

Page 42: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Valuing a Call Option

Value at node B = e–0.12´0.25(0.6523´3.2 + 0.3477´0) = 2.0257

Value at node A = e–0.12´0.25(0.6523´2.0257 + 0.3477´0)

= 1.2823

201.2823

22

18

24.23.2

19.80.0

16.20.0

2.0257

0.0

A

B

C

D

E

F

Page 43: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A Put Option Example; K=52

K = 52, Dt = 1yrr = 5%

504.1923

60

40

720

484

3220

1.4147

9.4636

A

B

C

D

E

F

Page 44: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Behaviorof Stock Prices

Page 45: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Discrete time; discrete variable Discrete time; continuous variable Continuous time; discrete variable Continuous time; continuous variable

Categorization of Stochastic Processes

Page 46: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

We can use any of the four types of stochastic processes to model stock prices

The continuous time, continuous variable process proves to be the most useful for the purposes of valuing derivative securities

Modeling Stock Prices

Page 47: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

In a Markov process future movements in a variable depend only on where we are, not the history of how we got where we are

We will assume that stock prices follow Markov processes

Markov Processes

Page 48: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

The assertion is that it is impossible to produce consistently superior returns with a trading rule based on the past history of stock prices. In other words technical analysis does not work.

A Markov process for stock prices is clearly consistent with weak-form market efficiency

Weak-Form Market Efficiency

Page 49: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A stock price is currently at $40 At the end of 1 year it is considered

that it will have a probability distribution of (40,10) where f(m,s) is a normal distribution with mean m and standard deviation s.

Example of a Discrete Time Continuous Variable Model

Page 50: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

What is the probability distribution of the stock price at the end of 2 years?

½ years? ¼ years? Dt years? Taking limits we have defined a

continuous variable, continuous time process

Questions

Page 51: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

In Markov processes changes in successive periods of time are independent

This means that variances are additive Standard deviations are not additive

Variances & Standard Deviations

Page 52: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

In our example it is correct to say that the variance is 100 per year.

It is strictly speaking not correct to say that the standard deviation is 10 per year.

Variances & Standard Deviations (continued)

Page 53: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

We consider a variable z whose value changes continuously

The change in a small interval of time Dt is Dz

The variable follows a Wiener process if: 1.

2. The values of Dz for any 2 different (non-overlapping) periods of time are independent

A Wiener Process

(0,1) N from drawing random a is where tz DD

Page 54: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Mean of [z (T ) – z (0)] is 0 Variance of [z (T ) – z (0)] is T Standard deviation of [z (T ) – z (0)] is

Properties of a Wiener Process

T

Page 55: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

What does an expression involving dz and dt mean?

It should be interpreted as meaning that the corresponding expression involving Dz and Dt is true in the limit as Dt tends to zero

In this respect, stochastic calculus is analogous to ordinary calculus

Taking Limits . . .

Page 56: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A Wiener process has a drift rate (ie average change per unit time) of 0 and a variance rate of 1

In a generalized Wiener process the drift rate & the variance rate can be set equal to any chosen constants

Generalized Wiener Processes

Page 57: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

The variable x follows a generalized Wiener process with a drift rate of a & a variance rate of b2 if

dx=adt+bdz

Generalized Wiener Processes(continued)

Page 58: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Mean change in x in time T is aT Variance of change in x in time T is b2T Standard deviation of change in x in

time T is

Generalized Wiener Processes(continued)

D D Dx a t b t

b T

Page 59: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A stock price starts at 40 & has a probability distribution of (40,10) at the end of the year

If we assume the stochastic process is Markov with no drift then the process is

dS = 10dz If the stock price were expected to grow by

$8 on average during the year, so that the year-end distribution is (48,10), the process is

dS = 8dt + 10dz

The Example Revisited

Page 60: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

In an Ito process the drift rate and the variance rate are functions of time

dx=a(x,t)dt+b(x,t)dz The discrete time equivalent

is only true in the limit as Dt tends to zero

Ito Process

D D Dx a x t t b x t t ( , ) ( , )

Page 61: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

For a stock price we can conjecture that its expected proportional change in a short period of time remains constant not its expected absolute change in a short period of time

We can also conjecture that our uncertainty as to the size of future stock price movements is proportional to the level of the stock price

Why a Generalized Wiener Processis not Appropriate for Stocks

Page 62: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

where m is the expected return s is the volatility.

The discrete time equivalent is

An Ito Process for Stock Prices

dS Sdt Sdz m s

D D DS S t S t m s

Page 63: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

We can sample random paths for the stock price by sampling values for

Suppose m= 0.14, s= 0.20, and Dt = 0.01, then

Monte Carlo Simulation

DS S S 0 0014 0 02. .

Page 64: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Monte Carlo Simulation – One Path

PeriodStock Price atStart of Period

RandomSample for

Change in StockPrice, DS

0 20.000 0.52 0.236

1 20.236 1.44 0.611

2 20.847 -0.86 -0.329

3 20.518 1.46 0.628

4 21.146 -0.69 -0.262

Page 65: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

If we know the stochastic process followed by x, Ito’s lemma tells us the stochastic process followed by some function G (x, t )

Since a derivative security is a function of the price of the underlying & time, Ito’s lemma plays an important part in the analysis of derivative securities

Ito’s Lemma

Page 66: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

A Taylor’s series expansion of G (x , t) gives

Taylor Series Expansion

D D D D

D D D

G Gx

x Gt

t Gx

x

Gx t

x t Gt

t

½

½

2

22

2 2

22

Page 67: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Ignoring Terms of Higher Order Than Dt

In ordinary calculus we get

stic calculus we get

because has a component which is of order

In stocha

½

D D D

D D D D

D D

G Gx

x Gt

t

G Gx

x Gt

t Gx

x

x t

2

22

Page 68: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Substituting for DxSuppose ( , ) ( , )so that

= + Then ignoring terms of higher order than

½

dx a x t dt b x t dz

x a t b tt

G Gx

x Gt

t Gx

b t

D D DD

D D D D

2

22 2

Page 69: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

The 2Dt Term

tbxGt

tGx

xGG

tt

ttE

E

EE

EN

DDDD

DD

DD

22

2

2

2

2

22

21

Hence ignored. be can and toalproportion is of varianceThe

)( that followsIt

1)(

1)]([)(

0)(,)1,0( Since

Page 70: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Taking Limits

Taking limits ½

Substituting

We obtain ½

This is Ito's Lemma

dG Gx

dx Gt

dt Gx

b dt

dx a dt b dz

dG Gx

a Gt

Gx

b dt Gx

b dz

2

22

2

22

Page 71: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Application of Ito’s Lemmato a Stock Price Process

The stock price process is For a function of &

½

d S S dt S d zG S t

dGGS

SGt

GS

S dtGS

S dz

m s

m

s

s2

22 2

Page 72: OPTIONS - EXAMPLES

MILJAN KNEŽEVIĆ, BANJA LUKA - AUGUST 2010

Examples1. The forward price of a stock for a contract maturing at time

e

2.

T

G SdG r G dt G dz

G S

dG dt dz

r T t

( )

( )

ln

m s

ms

s2

2