operations management chapter 12 – inventory management © 2006 prentice hall, inc. powerpoint...

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Operations Management Chapter 12 – Inventory Management 2006 Prentice Hall, Inc. PowerPoint presentation to accompany PowerPoint presentation to accompany Heizer/Render Heizer/Render Principles of Operations Management, 6e Principles of Operations Management, 6e Operations Management, 8e Operations Management, 8e

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Operations ManagementOperations ManagementChapter 12 – Inventory ManagementChapter 12 – Inventory Management

© 2006 Prentice Hall, Inc.

PowerPoint presentation to accompanyPowerPoint presentation to accompany Heizer/Render Heizer/Render Principles of Operations Management, 6ePrinciples of Operations Management, 6eOperations Management, 8e Operations Management, 8e

Safety stock 16.5 units

ROP ROP

Place Place orderorder

Probabilistic DemandIn

ven

tory

lev

elIn

ven

tory

lev

el

TimeTime00

Minimum demand during lead timeMinimum demand during lead time

Maximum demand during lead timeMaximum demand during lead time

Mean demand during lead timeMean demand during lead time

Normal distribution probability of Normal distribution probability of demand during lead timedemand during lead time

Expected demand during lead time Expected demand during lead time (350(350 kits kits))

ROP ROP = 350 += 350 + safety stock of safety stock of 16.5 = 366.516.5 = 366.5

Receive Receive orderorder

Lead Lead timetime

Figure 12.8Figure 12.8

Probabilistic Demand

Safety Safety stockstock

Probability ofProbability ofno stockoutno stockout

95% of the time95% of the time

Mean Mean demand demand

350350

ROP = ? kitsROP = ? kits QuantityQuantity

Number of Number of standard deviationsstandard deviations

00 zz

Risk of a stockout Risk of a stockout (5% of area of (5% of area of normal curve)normal curve)

Probabilistic Demand

Use prescribed service levels to set safety stock when the cost of stockouts cannot be determined

ROP = demand during lead time + ZROP = demand during lead time + Zdltdlt

wherewhere Z Z ==number of standard number of standard deviationsdeviations

dltdlt = =standard deviation of standard deviation of demand during lead timedemand during lead time

Probabilistic Example

Average demand Average demand = = = 350 = 350 kits kitsStandard deviation of demand during lead time Standard deviation of demand during lead time = = dltdlt = 10 = 10 kits kits5%5% stockout policy stockout policy ((service level service level = 95%)= 95%)

Using Appendix I, for an area under the curve Using Appendix I, for an area under the curve of of 95%,95%, the Z the Z = 1.65= 1.65

Safety stock Safety stock == Z Zdltdlt = 1.65(10) = 16.5= 1.65(10) = 16.5 kits kits

Reorder pointReorder point ==expected demand during lead expected demand during lead time + safety stocktime + safety stock

==350350 kits kits + 16.5+ 16.5 kits of safety kits of safety stockstock

==366.5366.5 or or 367367 kits kits

Other Probabilistic Models

1. When demand is variable and lead time is constant

2. When lead time is variable and demand is constant

3. When both demand and lead time are variable

When data on demand during lead time is not available, there are other models available

Other Probabilistic Models

Demand is variable and lead time is constantDemand is variable and lead time is constant

ROP ROP == ((average daily demand average daily demand x lead time in daysx lead time in days) +) + Z Zdltdlt

wherewhere dd == standard deviation of demand per day standard deviation of demand per day

dltdlt = = dd lead timelead time

Probabilistic Example

Average daily demand Average daily demand ((normally distributednormally distributed) = 15) = 15Standard deviation Standard deviation = 5= 5Lead time is constant at Lead time is constant at 22 days days90%90% service level desired service level desired

Z for Z for 90%90% = 1.28= 1.28From Appendix IFrom Appendix I

ROPROP = (15 = (15 units x units x 22 days days) +) + Z Zdltdlt

= 30 + 1.28(5)( 2)= 30 + 1.28(5)( 2)

= 30 + 8.96 = 38.96 ≈ 39= 30 + 8.96 = 38.96 ≈ 39

Safety stock is about Safety stock is about 99 units units

Other Probabilistic Models

Lead time is variable and demand is constantLead time is variable and demand is constant

ROP ROP ==((daily demand x daily demand x average lead time in daysaverage lead time in days))

==Z xZ x ( (daily demanddaily demand) ) xx ltlt

wherewhere ltlt == standard deviation of lead time in days standard deviation of lead time in days

Probabilistic Example

Daily demand Daily demand ((constantconstant) = 10) = 10Average lead time Average lead time = 6= 6 days daysStandard deviation of lead time Standard deviation of lead time = = ltlt = 3 = 398%98% service level desired service level desired

Z for Z for 98%98% = 2.055= 2.055From Appendix IFrom Appendix I

ROPROP = (10 = (10 units x units x 66 days days) + 2.055(10) + 2.055(10 units units)(3))(3)

= 60 + 61.55 = 121.65= 60 + 61.55 = 121.65

Reorder point is about Reorder point is about 122 122 unitsunits

Other Probabilistic Models

Both demand and lead time are variableBoth demand and lead time are variable

ROP ROP == ((average daily demand average daily demand x average lead timex average lead time) +) + Z Zdltdlt

wherewhere dd == standard deviation of demand per daystandard deviation of demand per day

ltlt == standard deviation of lead time in daysstandard deviation of lead time in days

dltdlt == ((average lead time x average lead time x dd22) )

+ (+ (average daily demandaverage daily demand)) 2 2ltlt22

Probabilistic Example

Average daily demand Average daily demand ((normally distributednormally distributed) = 150) = 150Standard deviation Standard deviation = = dd = 16 = 16Average lead time Average lead time 55 days days ((normally distributednormally distributed))Standard deviationStandard deviation = = ltlt = 1 = 1 dayday95%95% service level desired service level desired Z for Z for 95%95% = 1.65= 1.65

From Appendix IFrom Appendix I

ROPROP = (150 = (150 packs x 5 dayspacks x 5 days) + 1.65) + 1.65dltdlt

= (150 x 5) + 1.65 (5 days x 16= (150 x 5) + 1.65 (5 days x 1622) + (150) + (15022 x 1 x 122))

= 750 + 1.65(154) = 1,004 = 750 + 1.65(154) = 1,004 packspacks

Fixed-Period (P) Systems

Orders placed at the end of a fixed period

Inventory counted only at end of period

Order brings inventory up to target level

Only relevant costs are ordering and holding

Lead times are known and constant

Items are independent from one another

Fixed-Period (P) SystemsO

n-h

and

in

ven

tory

On

-han

d i

nve

nto

ry

TimeTime

QQ11

QQ22

Target maximum Target maximum ((TT))

PP

QQ33

QQ44

PP

PP

Figure 12.9Figure 12.9

Fixed-Period (P) Example

Order amount Order amount ((QQ)) = Target = Target ((TT)) - On- - On-hand inventory - Earlier orders not yet hand inventory - Earlier orders not yet

received + Back ordersreceived + Back orders

Q Q = 50 - 0 - 0 + 3 = 53= 50 - 0 - 0 + 3 = 53 jackets jackets

3 3 jackets are back orderedjackets are back ordered No jackets are in stockNo jackets are in stockIt is time to place an orderIt is time to place an order Target value Target value = 50= 50

Fixed-Period Systems

Inventory is only counted at each review period

May be scheduled at convenient times

Appropriate in routine situations

May result in stockouts between periods

May require increased safety stock