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Tonight’s HW is A2: 541(11b = PANIC and 11d)We will start using the books next Friday!
Chapter 23: Confidence Intervals for a Population Mean In addition to using interval estimates for population proportions (p), we can also use confidence intervals to estimate the true value of a population mean (µ).
The formula for a CI for a population mean is based on the sampling distribution of the sample mean . Recall that:
is approximately normally distributed when n > 30 or when the population is normal.
Thus far, we have been using z-critical values from the normal distribution to make our confidence intervals.
Now, remember that a z-score is calculated as
As long as is normally distributed, the distribution of z will also be normal. Why?
Since , m s, n are all constants, the shape shouldn’t change, only the center and spread.
observed value-expected valuez =
standard deviation
y
n
However, if we don’t know s (the population standard deviation) and we use s (the sample standard deviation) to
estimate s, the distribution of isn’t quite normal, even if is approximately normal.
So, we give this quantity a new name:
t = ysn
If you have your book open it to the back and look at it now.
You will get t-tables on the AP exam and can also find them in the back of your book.
Since t is based on 2 variables (s and ) instead of just (like z),
the t-distributions have more variability than the z (normal) distribution.
However, as the sample size increases, s gets closer to s and the t-distributions get closer to the standard normal distribution (z).
The t-curves are very similar to normal curves, except that they are wider and defined by a number called the DEGREES OF FREEDOM. For this chapter, df = n – 1.
Properties of the t-distributions:The t-curve corresponding to any
fixed number of degrees of freedom (df) is bell-shaped, symetric and centered at 0.
Each t-curve is more spread out than the z-curve (standard normal curve).
As the df increase, the spread of the corresponding t-curve decreases.
As the number of df increases, the t-curves get closer to the z-curve.
T-curves are wider than the z-curve, so we must go further than 1.96 SD to capture 95% of the area.
To find out how far, we use a t-critical value from the t-table.
If df = 20 and you want 95% confidence, what t-critical value should you use?
Thus, to capture the middle 95% of the t-distribution with 20 df, you must go out 2.086 stdev.
2.086
Find the t critical values for the following:a. 95% confidence with n = 10b. 90% confidence with n = 25 c. 99% confidence with n = 100
When using the t-table and the df you want are not provided, round down to the nearest df given.
2.262
1.7112.369
Suppose that a machine is designed to produce bolts that have a diameter of 5 mm. Every hour a random sample of 15 bolts is selected and a 95% confidence interval for the mean diameter is constructed. If there is evidence that m ≠ 5, the machine is adjusted. In one particular sample, the mean diameter was 5.08 mm with a standard deviation of 0.11 mm. Calculate the interval and decide if you need to adjust the machine.
It is asking for a confidence interval, what should we do?
That’s right, PANIC!
P: We want to estimate the true mean bolt diameters that the machine is producing (mD).
A: We have a random sample of 15
bolts.With a SRS, each bolt diameter is
independent of the other. Assuming there are at least 150
bolts produced each hour, our sample is less than 10% of the population.
LEN - …
3 ways to satisfy LEN:1) Data comes from a normal
population2) Graphed data is unimodal and
symmetric3) n > 30
None of these are true but…LEN: It is reasonable to assume that bolt diameters produced by the machine are normally distributed.
N: The conditions for a 95% 1-sample t interval have been met. DF = 14.
I:
=5.08 2.145(.11/√15)
= (5.091, 5.1409)C: I am 95% confident that the interval from 5.091 to 5.1409 captures the true mean diameter of bolts. Does the machine need to be adjusted?
Tonight’s HW: A2: 541(11b , d)
& stay safe…