number theory
DESCRIPTION
TRANSCRIPT
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Number Theory And Number Theory And SystemsSystems
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Introduction to Number TheoryIntroduction to Number Theory
Number theory is about Number theory is about integersintegers and their and their properties.properties.
We will start with the basic principles ofWe will start with the basic principles of • greatest common divisors,greatest common divisors,• least common multiples, andleast common multiples, and• modular arithmeticmodular arithmetic
and look at some relevant algorithms. and look at some relevant algorithms.
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PrimesPrimes
A positive integer p greater than 1 is called A positive integer p greater than 1 is called prime if the only positive factors of p are 1 and prime if the only positive factors of p are 1 and p.p.
A positive integer that is greater than 1 and is A positive integer that is greater than 1 and is not prime is called composite.not prime is called composite.
The fundamental theorem of arithmetic:The fundamental theorem of arithmetic:
Every positive integer can be written Every positive integer can be written uniquelyuniquely as the as the product of primesproduct of primes, where the prime , where the prime factors are written in order of increasing size.factors are written in order of increasing size.
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PrimesPrimes
Examples:Examples:
3·53·5
48 =48 =
17 =17 =
100 100 ==512 512 ==515 515 ==28 =28 =
15 =15 =
2·2·2·2·3 = 22·2·2·2·3 = 244·3·3
1717
2·2·5·5 = 22·2·5·5 = 222·5·522
2·2·2·2·2·2·2·2·2 = 22·2·2·2·2·2·2·2·2 = 299
5·1035·103
2·2·72·2·7
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Least Common MultiplesLeast Common MultiplesDefinition:Definition:
The The least common multipleleast common multiple of the positive of the positive integers a and b is the smallest positive integers a and b is the smallest positive integer that is divisible by both a and b.integer that is divisible by both a and b.
We denote the least common multiple of a and We denote the least common multiple of a and b by lcm(a, b).b by lcm(a, b).
Examples:Examples:
lcm(3, 7) lcm(3, 7) ==
2121
lcm(4, 6) lcm(4, 6) ==
1212
lcm(5, 10) lcm(5, 10) ==
1010
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Least Common MultiplesLeast Common Multiples
Using prime factorizations:Using prime factorizations:
a = pa = p11aa1 1 p p22
aa2 2 … p… pnnaan n , b = p, b = p11
bb1 1 p p22bb2 2 … p… pnn
bbn n ,,
where pwhere p11 < p < p22 < … < p < … < pnn and a and aii, b, bii NN for 1 for 1 i i n n
lcm(a, b) = plcm(a, b) = p11max(amax(a11, b, b1 1 )) p p22
max(amax(a22, b, b2 2 )) … p… pnnmax(amax(ann, b, bn n ))
Example:Example:
a = 60 a = 60 = =
2222 3 311 5 511
b = 54 b = 54 = =
2211 3 333 5 500
lcm(a, b) lcm(a, b) = =
2222 3 333 5 51 1 = 4 = 427275 = 5405 = 540
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Greatest Common DivisorsGreatest Common DivisorsLet a and b be integers, not both zero.Let a and b be integers, not both zero.The largest integer d such that d | a and d | b is The largest integer d such that d | a and d | b is called the called the greatest common divisorgreatest common divisor of a and b. of a and b.The greatest common divisor of a and b is denoted The greatest common divisor of a and b is denoted by gcd(a, b).by gcd(a, b).
Example 1:Example 1: What is gcd(48, 72) ? What is gcd(48, 72) ?The positive common divisors of 48 and 72 are The positive common divisors of 48 and 72 are 1, 2, 3, 4, 6, 8, 12, 16, and 24, so gcd(48, 72) = 24. 1, 2, 3, 4, 6, 8, 12, 16, and 24, so gcd(48, 72) = 24.
Example 2:Example 2: What is gcd(19, 72) ? What is gcd(19, 72) ?The only positive common divisor of 19 and 72 isThe only positive common divisor of 19 and 72 is1, so gcd(19, 72) = 1. 1, so gcd(19, 72) = 1.
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Greatest Greatest CommonCommon Divisors Divisors
Using prime factorizations:Using prime factorizations:
a = pa = p11aa1 1 p p22
aa2 2 … p… pnnaan n , b = p, b = p11
bb1 1 p p22bb2 2 … p… pnn
bbn n ,,
where pwhere p11 < p < p22 < … < p < … < pnn and a and aii, b, bii NN for 1 for 1 i i n n
gcd(a, b) = pgcd(a, b) = p11min(amin(a11, b, b1 1 )) p p22
min(amin(a22, b, b2 2 )) … p… pnnmin(amin(ann, b, bn n ))
Example:Example:
a = 60 a = 60 = =
2222 3 311 5 511
b = 54 b = 54 = =
2211 3 333 5 500
gcd(a, b) gcd(a, b) = =
2211 3 311 5 50 0 = 6 = 6
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GCD and LCMGCD and LCM
a = 60 a = 60 = =
2222 3 311 5 511
b = 54 b = 54 = =
2211 3 333 5 500
lcm(a, b) lcm(a, b) = =
2222 3 333 5 51 1 = 540 = 540
gcd(a, b) gcd(a, b) = =
2211 3 311 5 50 0 = 6 = 6
Theorem: aTheorem: ab b ==
gcd(a,b)gcd(a,b)lcm(a,lcm(a,b)b)
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Relatively Prime IntegersRelatively Prime IntegersDefinition:Definition:
Two integers a and b are Two integers a and b are relatively primerelatively prime if if gcd(a, b) = 1.gcd(a, b) = 1.
Examples:Examples:
Are 15 and 28 relatively prime?Are 15 and 28 relatively prime?Yes, gcd(15, 28) = 1.Yes, gcd(15, 28) = 1.Are 55 and 28 relatively prime?Are 55 and 28 relatively prime?Yes, gcd(55, 28) = 1.Yes, gcd(55, 28) = 1.Are 35 and 28 relatively prime?Are 35 and 28 relatively prime?No, gcd(35, 28) = 7.No, gcd(35, 28) = 7.
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Modular ArithmeticModular Arithmetic
Let a be an integer and m be a positive integer.Let a be an integer and m be a positive integer.We denote by We denote by a mod ma mod m the remainder when a the remainder when a is divided by m.is divided by m.
Examples:Examples:
9 mod 4 9 mod 4 ==
11
9 mod 3 9 mod 3 ==
00
9 mod 10 9 mod 10 ==
99
-13 mod 4 -13 mod 4 ==
33
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Common Number Systems
System Base Symbols
Used by humans?
Used in computers?
Decimal 10 0, 1, … 9 Yes No
Binary 2 0, 1 No Yes
Octal 8 0, 1, … 7 No No
Hexa-decimal
16 0, 1, … 9,A, B, … F
No No
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Quantities/Counting (1 of 3)
Decimal Binary Octal
Hexa-decimal
0 0 0 0
1 1 1 1
2 10 2 2
3 11 3 3
4 100 4 4
5 101 5 5
6 110 6 6
7 111 7 7
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Quantities/Counting (2 of 3)
Decimal Binary Octal
Hexa-decimal
8 1000 10 8
9 1001 11 9
10 1010 12 A
11 1011 13 B
12 1100 14 C
13 1101 15 D
14 1110 16 E
15 1111 17 F
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Quantities/Counting (3 of 3)
Decimal Binary Octal
Hexa-decimal
16 10000 20 10
17 10001 21 11
18 10010 22 12
19 10011 23 13
20 10100 24 14
21 10101 25 15
22 10110 26 16
23 10111 27 17
Etc.
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Conversion Among Bases
• The possibilities:
Hexadecimal
Decimal Octal
Binary
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Quick Example
2510 = 110012 = 318 = 1916
Base
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Decimal to Decimal (just for fun)
Hexadecimal
Decimal Octal
Binary
Next slide…
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12510 => 5 x 100 = 52 x 101 = 201 x 102 =
100
125Base
Weight
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Binary to Decimal
Hexadecimal
Decimal Octal
Binary
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Binary to Decimal
• Technique– Multiply each bit by 2n, where n is the “weight”
of the bit– The weight is the position of the bit, starting
from 0 on the right– Add the results
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Example
1010112 => 1 x 20 = 11 x 21 = 20 x 22 = 01 x 23 = 80 x 24 = 01 x 25 = 32
4310
Bit “0”
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Octal to Decimal
Hexadecimal
Decimal Octal
Binary
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Octal to Decimal
• Technique– Multiply each bit by 8n, where n is the “weight”
of the bit– The weight is the position of the bit, starting
from 0 on the right– Add the results
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Example
7248 => 4 x 80 = 42 x 81 = 167 x 82 = 448
46810
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Hexadecimal to Decimal
Hexadecimal
Decimal Octal
Binary
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Hexadecimal to Decimal
• Technique– Multiply each bit by 16n, where n is the
“weight” of the bit– The weight is the position of the bit, starting
from 0 on the right– Add the results
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Example
ABC16 => C x 160 = 12 x 1 = 12 B x 161 = 11 x 16 = 176 A x 162 = 10 x 256 = 2560
274810
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Decimal to Binary
Hexadecimal
Decimal Octal
Binary
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Decimal to Binary
• Technique– Divide by two, keep track of the remainder– First remainder is bit 0 (LSB, least-significant
bit)– Second remainder is bit 1– Etc.
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Example
12510 = ?22 125 62 12 31 02 15 12 7 12 3 12 1 12 0 1
12510 = 11111012
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Octal to Binary
Hexadecimal
Decimal Octal
Binary
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Octal to Binary
• Technique– Convert each octal digit to a 3-bit equivalent
binary representation
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Example
7058 = ?2
7 0 5
111 000 101
7058 = 1110001012
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Hexadecimal to Binary
Hexadecimal
Decimal Octal
Binary
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Hexadecimal to Binary
• Technique– Convert each hexadecimal digit to a 4-bit
equivalent binary representation
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Example
10AF16 = ?2
1 0 A F
0001 0000 1010 1111
10AF16 = 00010000101011112
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Decimal to Octal
Hexadecimal
Decimal Octal
Binary
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Decimal to Octal
• Technique– Divide by 8– Keep track of the remainder
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Example
123410 = ?8
8 1234 154 28 19 28 2 38 0 2
123410 = 23228
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Decimal to Hexadecimal
Hexadecimal
Decimal Octal
Binary
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Decimal to Hexadecimal
• Technique– Divide by 16– Keep track of the remainder
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Example
123410 = ?16
123410 = 4D216
16 1234 77 216 4 13 = D16 0 4
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Binary to Octal
Hexadecimal
Decimal Octal
Binary
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Binary to Octal
• Technique– Group bits in threes, starting on right– Convert to octal digits
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Example
10110101112 = ?8
1 011 010 111
1 3 2 7
10110101112 = 13278
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Binary to Hexadecimal
Hexadecimal
Decimal Octal
Binary
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Binary to Hexadecimal
• Technique– Group bits in fours, starting on right– Convert to hexadecimal digits
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Example
10101110112 = ?16
10 1011 1011
1 B B
10101110112 = 2BB16
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Octal to Hexadecimal
Hexadecimal
Decimal Octal
Binary
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Octal to Hexadecimal
• Technique– Use binary as an intermediary
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Example
10768 = ?16
1 0 7 6
001 000 111 110
2 3 E
10768 = 23E16
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Hexadecimal to Octal
Hexadecimal
Decimal Octal
Binary
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Hexadecimal to Octal
• Technique– Use binary as an intermediary
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Example
1F0C16 = ?8
1 F 0 C
0001 1111 0000 1100
1 7 4 1 4
1F0C16 = 174148
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Exercise – Convert ...
Don’t use a calculator!
Decimal Binary Octal
Hexa-decimal
33
1110101
703
1AF
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Exercise – Convert …
Decimal Binary Octal
Hexa-decimal
33 100001 41 21
117 1110101 165 75
451 111000011 703 1C3
431 110101111 657 1AF
Answer
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Thank you