Nr220106 Surveying II Set1

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  • 8/11/2019 Nr220106 Surveying II Set1

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    Code No: NR220106 NR

    II B.Tech II Semester Supplementary Examinations, Aug/Sep 2006SURVEYING-II

    (Civil Engineering)Time: 3 hours Max Marks: 80

    Answer any FIVE Questions

    All Questions carry equal marks

    1. (a) Two stations at elevations of and are sighted by a theodolite in which theline of collimation is inclined to the trunnion axis at an angel (90 0 - e), wheree is small. [9+7]

    i. Derive an expression for the error in the horizontal angel between the twostations as given by the instrument.

    ii. Show by a diagram the effect of the collimation error on the vertical circlereading of one station.

    iii. What is the effect of measuring the horizontal and vertical angles on bothfaces?

    (b) In a straight line ABC, AB measure 354.384 m, BC measures 282.092 m andAC measures 636.318 m using a particular EDM reflector combination. A linemeasures 533.452 m with this instrument reflector combination. What is thecorrect length of the line?

    2. (a) A man travels from a point A to due to west and reaches the point B. Thedistance between A and B = 139.6 m. Calculate the latitude and departureof the line AB. [8+8]

    (b) For the following traverse, find the length of DE so that A, E and F may bein the same straight line.

    Line Length(m) Reduced BearingAB 200 S 840301 EBC 100 N 750181 ECD 80 N 180451 EDE ? N 290451 EEF 150 N 640101 E

    3. (a) Derive the equation for elevation for a case when the staff is held vertical andline of sight of tacheometer is inclined upwards. [8+8]

    (b) Derive an expression for horizontal distance of vertical staff from a theodolitewith stadia diaphragm, when the line of sight is horizontal. Explain how theusual expression for horizontal distance D and vertical component V can bededuced from the above expression when the line of sight is inclined.

    4. (a) What are the different linear methods for setting out simple circular curves.Explain the procedure to set out the curve by radial offsets from the tangents. [8+8]

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    Code No: NR220106 NR

    (b) Two straight BA and BC are intersected by a line EF. The angles BEF andEFC are 1400and1450, respectively. The radius of the first arc is 600 m andthat of the second is 400 m. Find the chainages of the tangent points, and thepoint of compound curvature, given that the chainage of point A is 3415 m.

    5. (a) What is a transition curve? Why it is used? Define shift of a curve. Drawtwo tangents and show a circular curve and two transition curves connectingthe tangents, marking the shift, on your sketch. [8+8]

    (b) How the transition curve be set out. Explain.

    6. The following reciprocal observations were made from two points: P and Q : [16]Horizontal distance between P and Q = 4860 mAngle of elevation of Q at P = 10 5 21Angle of depression of P at Q = 10 0 50Height of instrument at P = 1.35 mHeight of signal at P = 6.10 m

    Height of instrument at Q = 1.38 mHeight of signal at Q = 6.21 m

    Find the difference in level between P and Q and the co-efficient of refraction. TakeR sin 1 = 30.88 m

    7. (a) Find the sag correction for 30 m steel tape under a pull of 80 N in three equalspans of 10 m each. Mass of one cubic cm at steel = 7.86 g/cm3. Area ofcross-section of the tape = 0.10 sq. cm. [8+8]

    (b) A steel tape is 30 m long at a temperature, of 65F when lying horizontally on

    the ground, Its sectional area is 0.082 sq. cm, its mass 2 kg and coefficient ofexpansion 65 x 107 per 10 F. The tape is stretched over three equal spans.Calculate actual length between the end graduations under the following con-ditions: temp. 850 F, pull 180 N. Take E = 2.07 X 107 N/cm2.

    8. Adjust the angles and , observations of which give [16]= 200 10 10 weight 6= 300 20 30 weight 4+= 500 30 50 weight 2

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