notes 6-7

44
SECTION 6-7 LINEARIZING DATA TO FIND MODELS

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Linearizing Data to Find Models

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Page 1: Notes 6-7

SECTION 6-7 LINEARIZING DATA TO FIND MODELS

Page 2: Notes 6-7

WARM-UP

SKETCH A GRAPH IN THE FIRST QUADRANT FOR EACH OF THE FOLLOWING.

a. y = 3x

b. y = log x

Page 3: Notes 6-7

WARM-UP

SKETCH A GRAPH IN THE FIRST QUADRANT FOR EACH OF THE FOLLOWING.

a. y = 3x

b. y = log x

Page 4: Notes 6-7

WARM-UP

SKETCH A GRAPH IN THE FIRST QUADRANT FOR EACH OF THE FOLLOWING.

a. y = 3x

b. y = log x

Page 5: Notes 6-7

BLOG QUESTION

Page 6: Notes 6-7

BLOG QUESTION

WHAT DOES IT MEAN TO LINEARIZE DATA? DISCUSS THIS IDEA WITH A PARTNER, THEN RECORD YOUR

THOUGHTS IN YOUR BLOG. CHECK BACK TOMORROW TO SEE WHAT YOUR CLASSMATES

SAID.

Page 7: Notes 6-7

EXAMPLE 1

REWRITE AS A LINEAR MODEL OF log G IN TERMS OF X.

Page 8: Notes 6-7

EXAMPLE 1

REWRITE AS A LINEAR MODEL OF log G IN TERMS OF X.

G = 36(7)x

Page 9: Notes 6-7

EXAMPLE 1

REWRITE AS A LINEAR MODEL OF log G IN TERMS OF X.

G = 36(7)x

logG = log(36i7 x )

Page 10: Notes 6-7

EXAMPLE 1

REWRITE AS A LINEAR MODEL OF log G IN TERMS OF X.

G = 36(7)x

logG = log(36i7 x )

logG = log36 + log 7 x

Page 11: Notes 6-7

EXAMPLE 1

REWRITE AS A LINEAR MODEL OF log G IN TERMS OF X.

G = 36(7)x

logG = log(36i7 x )

logG = log36 + log 7 x

logG = log36 + x log 7

Page 12: Notes 6-7

EXAMPLE 2

SOLVE FOR R.

lnR = 9x − 5.52

Page 13: Notes 6-7

EXAMPLE 2

SOLVE FOR R.

lnR = 9x − 5.52

R = e 9 x−5.52

Page 14: Notes 6-7

EXAMPLE 2

SOLVE FOR R.

lnR = 9x − 5.52

R = e 9 x−5.52

R = e 9 xie−5.52

Page 15: Notes 6-7

EXAMPLE 2

SOLVE FOR R.

lnR = 9x − 5.52

R = e 9 x−5.52

R = e 9 x

e5.52

R = e 9 xie−5.52

Page 16: Notes 6-7

EXAMPLE 2

SOLVE FOR R.

lnR = 9x − 5.52

R = e 9 x−5.52

R = e 9 x

e5.52

R ≈ .004e 9 x

R = e 9 xie−5.52

Page 17: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

Page 18: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

Page 19: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

98 ≈ 15.7 lnt + 30.1

Page 20: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

98 ≈ 15.7 lnt + 30.1-30.1-30.1

Page 21: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

98 ≈ 15.7 lnt + 30.1-30.1-30.1

67.9 ≈ 15.7 lnt

Page 22: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

98 ≈ 15.7 lnt + 30.1-30.1-30.1

67.9 ≈ 15.7 lnt15.715.7

Page 23: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

98 ≈ 15.7 lnt + 30.1-30.1-30.1

67.9 ≈ 15.7 lnt15.715.7

67.9

15.7≈ lnt

Page 24: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

98 ≈ 15.7 lnt + 30.1-30.1-30.1

67.9 ≈ 15.7 lnt15.715.7

67.9

15.7≈ lnt

t ≈ e67.9

15.7

Page 25: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

98 ≈ 15.7 lnt + 30.1-30.1-30.1

67.9 ≈ 15.7 lnt15.715.7

67.9

15.7≈ lnt

t ≈ e67.9

15.7

≈ 75.55

Page 26: Notes 6-7

EXAMPLE 3

REFER BACK TO EXAMPLE 2 IN THE BOOK. ESTIMATE THE AMOUNT OF PRACTICE TIME NEEDED

TO EXCEED 98%.

P ≈ 15.7 lnt + 30.1

98 ≈ 15.7 lnt + 30.1-30.1-30.1

67.9 ≈ 15.7 lnt15.715.7

67.9

15.7≈ lnt

t ≈ e67.9

15.7

≈ 75.55 SECONDS

Page 27: Notes 6-7

EXAMPLE 4

THE MANAGER OF A TOY COMPANY ANALYZES THE PRODUCTION COSTS FOR THE COMPANY’S NEWEST

STUFFED ANIMAL. IN THE TABLE BELOW ARE COSTS C OF PRODUCING A GIVEN NUMBER OF UNITS U OF

THE TOY.

Units u 250 500 750 1000 1250

Production Cost C $68 $103 $150 $212 $314

Page 28: Notes 6-7

USING YOUR GRAPHING CALCULATOR, DETERMINE WHETHER THIS DATA PRESENTED IS A LINEAR,

EXPONENTIAL, POWER, OR LOGARITHM REGRESSION. RECORD YOUR EQUATION. THEN,

ESTIMATE TO THE NEAREST DOLLAR HOW MUCH IT SHOULD COST TO PRODUCE 1100 UNITS OF THE TOY.

Page 29: Notes 6-7

USING YOUR GRAPHING CALCULATOR, DETERMINE WHETHER THIS DATA PRESENTED IS A LINEAR,

EXPONENTIAL, POWER, OR LOGARITHM REGRESSION. RECORD YOUR EQUATION. THEN,

ESTIMATE TO THE NEAREST DOLLAR HOW MUCH IT SHOULD COST TO PRODUCE 1100 UNITS OF THE TOY.

Page 30: Notes 6-7

USING YOUR GRAPHING CALCULATOR, DETERMINE WHETHER THIS DATA PRESENTED IS A LINEAR,

EXPONENTIAL, POWER, OR LOGARITHM REGRESSION. RECORD YOUR EQUATION. THEN,

ESTIMATE TO THE NEAREST DOLLAR HOW MUCH IT SHOULD COST TO PRODUCE 1100 UNITS OF THE TOY.

Page 31: Notes 6-7

USING YOUR GRAPHING CALCULATOR, DETERMINE WHETHER THIS DATA PRESENTED IS A LINEAR,

EXPONENTIAL, POWER, OR LOGARITHM REGRESSION. RECORD YOUR EQUATION. THEN,

ESTIMATE TO THE NEAREST DOLLAR HOW MUCH IT SHOULD COST TO PRODUCE 1100 UNITS OF THE TOY.

Page 32: Notes 6-7

USING YOUR GRAPHING CALCULATOR, DETERMINE WHETHER THIS DATA PRESENTED IS A LINEAR,

EXPONENTIAL, POWER, OR LOGARITHM REGRESSION. RECORD YOUR EQUATION. THEN,

ESTIMATE TO THE NEAREST DOLLAR HOW MUCH IT SHOULD COST TO PRODUCE 1100 UNITS OF THE TOY.

Page 33: Notes 6-7

USING YOUR GRAPHING CALCULATOR, DETERMINE WHETHER THIS DATA PRESENTED IS A LINEAR,

EXPONENTIAL, POWER, OR LOGARITHM REGRESSION. RECORD YOUR EQUATION. THEN,

ESTIMATE TO THE NEAREST DOLLAR HOW MUCH IT SHOULD COST TO PRODUCE 1100 UNITS OF THE TOY.

Page 34: Notes 6-7

USING YOUR GRAPHING CALCULATOR, DETERMINE WHETHER THIS DATA PRESENTED IS A LINEAR,

EXPONENTIAL, POWER, OR LOGARITHM REGRESSION. RECORD YOUR EQUATION. THEN,

ESTIMATE TO THE NEAREST DOLLAR HOW MUCH IT SHOULD COST TO PRODUCE 1100 UNITS OF THE TOY.

Page 35: Notes 6-7
Page 36: Notes 6-7
Page 37: Notes 6-7
Page 38: Notes 6-7
Page 39: Notes 6-7

C ≈ 47.45025482(1.001513796)u

Page 40: Notes 6-7

C ≈ 47.45025482(1.001513796)u

C ≈ 47.45025482(1.001513796)1100

Page 41: Notes 6-7

C ≈ 47.45025482(1.001513796)u

C ≈ 47.45025482(1.001513796)1100

Page 42: Notes 6-7

C ≈ 47.45025482(1.001513796)u

C ≈ 47.45025482(1.001513796)1100

C ≈ $251

Page 43: Notes 6-7

HOMEWORK

Page 44: Notes 6-7

HOMEWORK

P. 413 #1-16