nicl ao preparation - quantitative aptitude (day 8)

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NICL AO Preparation Dear Friends, Try to solve the following problems in Quantitative Aptitude in less than 20 minutes. Kindly use the discussion section efficiently and don’t post any irrelevant comments. NICL AO Preparation – Quantitative Aptitude (Day 8) Mar 28, 2015 Current Affairs NICL AO Preparation Daily Aptitude

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NICL AO Preparation

Dear Friends,

Try to solve the following problems in Quantitative Aptitude in less than 20 minutes. Kindly use the discussionsection efficiently and don’t post any irrelevant comments.

NICL AO Preparation – Quantitative Aptitude (Day 8)Mar 28, 2015Current Affairs NICL AO Preparation Daily Aptitude

1. Radhika invested an amount that is 10% of Rs.10,000 at SI. After three years, the amount becomes Rs 2500.Find out the 4 times of actual interest rate.

a) 100% b) 200% c) 250% d) 300%

Answer – b) 200%

2. Sindhuja takes loan from Sonia at the rate of 5% per annum. After 2 years Sindhuja gave back Rs. 8800 toSonia and this way paid her whole loan. Find the interest paid by Sindhuja.

a) 500 b) 600 c) 700 d) 800

Answer- d) 800

3. Avinnash invested an amount of Rs.21250 for 6 years. At what rate of SI, he will obtain Rs 26350 at the endof 6 years?

a) 2% b) 3% c) 4% d) 5%

Answer – c) 4%

4. A bag has 100 blue pencils. 50 red pencils and 50 black pencils. 25% of blue pencils and 50% of red pencilsare taken away. Then the percentage of black pencils at present is

a) 20(2/3)% b) 44(2/3)% c) 33(1/3)% d) 41(1/3)%

Answer – c) 33(1/3)%

5. A bus travles a distance from City P to City Q at the speed of 42kmph and city Q to City P at 48kmph. What isthe average speed of the bus?

a) 43.6 b) 44.8 c) 46 d) 52

Answer – b) 44.8

6. Find the maximum number of Rose Plants, which can be planted 20 m apart on the two sides of a straightroad 1760 m long.

a) 178 b) 176 c) 174 d) 180

Answer – a) 178

7. In how many ways, a hockey team of 11 players can be made from 15 players, if a particular player is alwayschosen?

a) 991 b) 1001 c) 1010 d) 1100

Answer – B) 1001

8. In a high level meeting between India and Pakistan, a total of 12 delegates attended from each country. Allthe 12 delegates of India shake hands with the 12 delegates of Pakistan. The possible number of handshakesare

a) 288 b) 144 c) 156 d) 168

Answer – b) 144

9. P, Q and R run 1 Km in 5, 8, and 10 mins respectively. R starts running from a point at a certain time, Q startsfrom the same point 1 min later and P starts from the same point 2 min later than R. Then, P meets Q and R attimes

a) 3 min; 3/5 min b) 2 min; 5/3 min c) 2 min; 4/7 min; d) 3 min; 5/9 min

Answer – b) 2 min; 5/3 min

10. A container contains 60 L – the ratio of milk and water is 2:1. If the ratio of milk and water is to be 1:2,then the amount of water to be added is

a) 58 L b) 60 L c) 62 L d) 64 L

Answer – b) 60 L

Related Posts:

1. NICL AO Preparation – Quantitative Aptitude (Day 7)2. NICL AO Preparation – Quantitative Aptitude (Day 6)3. NICL AO Preparation – Quantitative Aptitude (Day 2)4. NICL AO Preparation – Quantitative Aptitude (Day 3)5. NICL AO Preparation – Quantitative Aptitude (Day 5)

Arunsathyan

41 Comments AffairsCloud satish kumar R

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• Reply •

Prateek G • 12 days ago

3](26350­21250)=2150*6*x/100:5100=425*3*x;x=5100/(425*3)=4%

1

• Reply •

Arun • 15 days ago

exp 9th one 1

• Reply •

Deepika deep • 14 days ago> Arun

speed of P is 200 m/min, Q­125m/min, R­100m/sec. now according to question at 1st minposition of P, Q, R from initial point is 0, 0, 100. at 2nd min 0, 125, 200. at 3rd min 200, 250,300. at 4th min 400, 375, 400. it shows P met R at his 2nd min and P crossed Q before his2nd min and this condition in only in option B

2

• Reply •

Renuga Santhanakumar • 2 days ago> Deepika deep

could u explain pls how did u taken speed as 200,125,100?

• Reply •

Deepika deep • 2 days ago> Renuga Santhanakumar

CONVERT IT..LIKE FOR, IN 5 MIN = 1KM (1000M)SO IN 1 MIN = 1000/5 = 200M

• Reply •

Renuga Santhanakumar • 2 days ago> Deepika deep

ok thanks 1

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Hey Friends. I am Arunsathyan, Alumini of SASTRA & SRM University. I worked in a MNCand quit my job in 2013 to focus on UPSC exams. During my preparation, the idea to starta website raised in my mind and we landed here. AffairsCloud.com is a website "by anaspirant; to the aspirants; for the aspirants". :-)

• Reply •

Arun • 14 days ago> Deepika deep

Thank u deepika :)

• Reply •

Prashant • 14 days ago> Deepika deep

Thanks

• Reply •

Abinaya • 15 days ago

2.total amount sonia get after 2 years 8800. (p + SI)consider SI = xconsider principal = 8800­xx = (8800 ­ x)* 2 * 5/100therefore x =800

1

• Reply •

Abinaya • 15 days ago

1.10% of 10000=1000(principal) total amount after 3 years 2500..interest=2500­1000­­­­>1500rate of interest = SI * 100/ P * N = 50% 4times of rate of interest is 200 %

1

• Reply •

Nitin Aggarwal • 15 days ago> Abinaya

explain 9th

• Reply •

SP Ever • 2 days ago

please provide solution procedure also......

• Reply •

Deepika deep • 14 days ago

9th. speed of P is 200 m/min, Q­125m/min, R­100m/sec. now according to question at 1st minposition of P, Q, R from initial point is 0, 0, 100. at 2nd min 0, 125, 200. at 3rd min 200, 250, 300. at4th min 400, 375, 400. it shows P met R at his 2nd min and P crossed Q before his 2nd min and thiscondition in only in option B

• Reply •

srikanth 26 • 15 days ago

it could b better if u provide easy solutions , like BA does

• Reply •

flick 'the ant' • 15 days ago

SIR ,WHEN WE ARE STARTING THE PREPARATION OF BOB(MANIPAL) AND NICLASSISTANT YET I HAD NOT FILL THE FORM OF NICL AO?

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• Reply •

Aspire • 15 days ago

Kindly explain Q6, 8 & 9.....

• Reply •

Nidhi CK Singh • 14 days ago> Aspire

6.total distance is 1760 and distance between two plants is 20 m right,now simply divide1760/20=88 +1( 1st plant will be at zero distance)=89 this is for one side for two side89x2=178

2

• Reply •

Aspire • 14 days ago> Nidhi CK Singh

thnkuu

• Reply •

Deepika deep • 14 days ago> Aspire

speed of P is 200 m/min, Q­125m/min, R­100m/sec. now according to question at 1st minposition of P, Q, R from initial point is 0, 0, 100. at 2nd min 0, 125, 200. at 3rd min 200, 250,300. at 4th min 400, 375, 400. it shows P met R at his 2nd min and P crossed Q before his2nd min and this condition in only in option B

1

• Reply •

Aspire • 14 days ago> Deepika deep

thnkss

• Reply •

Nidhi CK Singh • 14 days ago> Aspire

8. it is 12x12=144 1

• Reply •

rajeshwari • 15 days ago

can anybdy explain me 9th and 7th question?

• Reply •

Sandeep Saladi • 15 days ago

guys 14c10 means =101 then how did you get 1001?

• Reply •

Abinaya • 15 days ago> Sandeep Saladi

14 * 13 * 12* ......................................*5/10 * 9 * 8 *.......................*1so u get 14*13*12*11/4*3*2*1=1001

• Reply •

Nitin Aggarwal • 15 days ago

EXPLAIN 9TH

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• Reply •

• Reply •

Deepika deep • 14 days ago> Nitin Aggarwal

speed of P is 200 m/min, Q­125m/min, R­100m/sec. now according to question at 1st minposition of P, Q, R from initial point is 0, 0, 100. at 2nd min 0, 125, 200. at 3rd min 200, 250,300. at 4th min 400, 375, 400. it shows P met R at his 2nd min and P crossed Q before his2nd min and this condition in only in option b

• Reply •

Abinaya • 15 days ago

7. particular player always chosen so...14C10=1001

• Reply •

Abinaya • 15 days ago

5.average speed= 2 * 42* 48 /(42+48)=44.8

• Reply •

Abinaya • 15 days ago

3.simple interest =26350­21250­­­­­­­>5100use formula pnr/100 = SI r=SI * 100/p*n

• Reply •

Parmar Vijaykumar • 15 days ago

Anybody can explain 4th one???

• Reply •

Nidhi CK Singh • 14 days ago> Parmar Vijaykumar

total given is 100 blue ,50 red and 50 black,when 25% blue are taken outside than 100­2575.similerly 50% red than 50­25=25.now add all i.e 75+25+50=150.from 150 find the %ofblack i.e 50/150 x100=33.33%

• Edit • Reply •

satish kumar R • 15 days ago> Parmar Vijaykumar

7 a particular player is selected every timeso 10 players are chosen from 14that is

• Reply •

Parmar Vijaykumar • 15 days ago> satish kumar R

I am asking 4th one

Uma • 15 days ago> Parmar Vijaykumar

after taken 25% in blue­75

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• Reply •

after taken 25% in blue­75aftr tkn 50% in red­25black­5075+25+50=150% of black pencil=150(x/100)=50x=33(1/3)

• Reply •

monika • 15 days ago

sir,plz explain it thoroughly....

• Edit • Reply •

satish kumar R • 15 days ago> monika

10thsum

Quantity of milk =60 x2litres = 40 litres.3

Quantity of water in it = (60­ 40) litres = 20 litres.

New ratio = 1 : 2

Let quantity of water to be added further be x litres.

Then, milk : water =40.20 + x

Now,40=120 + x2

20 + x = 80

x = 60.

Quantity of water to be added = 60 litres. 1

• Reply •

Ritu • 14 days ago> satish kumar R

please explain 9th Qs.

• Reply •

Deepika deep • 14 days ago> Ritu

speed of P is 200 m/min, Q­125m/min, R­100m/sec. now according to questionat 1st min position of P, Q, R from initial point is 0, 0, 100. at 2nd min 0, 125,200. at 3rd min 200, 250, 300. at 4th min 400, 375, 400. it shows P met R at his2nd min and P crossed Q before his 2nd min and this condition in only in optionb.

• Reply •

Ritu • 14 days ago> Deepika deep

Thank u Deepika

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• Reply •

Nitin Aggarwal • 15 days ago> satish kumar R

explain 9

• Reply •

Renuga Santhanakumar • 3 days ago

pls explain first one

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