multi storey 2k9

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    The Objectives of the Project are:-

    To select a multi storey building that has alreadydesigned.

    Calculate the load due to DL, LL, WL, EL manuallyand analysis and design of the main building membersis done manually.

    Getting familiar with structural software ( STAAD

    PRO.) To compare the results of the software and manual

    calculations.

    1

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    Beam=230mm*500mm

    Column=250mm*500mm

    Slab=120mm thickness Wall thickness=230 mm

    Parapet wall thickness=115 mm Thickness of footing=350 mm

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    DEAD LOAD (DL)

    LIVE LOAD (LL)

    WIND LOAD (WL) EARTHQUAKE LOAD (EL)

    1.5(DL+LL) 1.2(DL+LL+EL or WL)

    1.5(DL+LL)+0.9EL

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    1.Live load : 3.0 KN/m2

    at typical floor2.Floor finish : 1.0 KN/m23.Location : New Delhi4.Wind load : As per IS: 8755.Earthquake load : As per IS-1893 (Part 1) -

    2002

    6.Depth of foundationbelow ground : 1.5 m7.Type of soil : Type II, Medium as per

    IS:18938.Allowable bearing

    pressure : 200 KN/m2

    9.Average thickness offooting : 0.9 m, assume isolated footings10.Floors : G.F. + 4 upper floors.11.Walls : 230 mm thick brick masonry

    walls

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    Reinforcement

    Beam= max. 4% of cross section areaColumn=min. .8% and max. 6% of cross sectionarea

    Slab=.12% for Hysd steel.15 % for mild seel

    Effective cover:

    For beam=25 mmFor column=40 mmFor slab= 20 mm

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    1. Dead load of slab = 0.120x2.5= 0.3 T/m2

    2. Dead load of wall of ground storey=4x0.23x2=1.84 T/m

    3. Dead Load of wall of IstFloor=3.5x0.23x2=1.61 T/m

    Similarly Dead Load of wall of IIndFloor=1.61 T/mDead Load of wall of IIIrdFloor=1.61 T/m

    Dead Load of wall of IVthFloor=1.61 T/m6.

    4.Dead load of parapet wall=.115x2.5x1.21=.347 T/m

    4.Dead load of columns=.25x.5x2.5x36x19.5=219.375 T5.Dead load of beam=190x2.5x.23x.5=54.625 T

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    Calculation of wind load using IS: 875:-

    Height=18 mWidth=11 mLength=28 mDesign wind speed: Vz=Vb.k1.k2.k3 (Vb=basic windspeed=47m/sec)

    k1=risk coefficient=1k2= Height and structure size

    factork3=topography factor=1

    Vz=47.k2Wind pressure: Pz=.6*(Vz)

    2

    Pz=.6*(47*k2)2

    Pz=1.3254*k22KN/m2

    Value of k2vary with height of structure

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    Wind force: F=Cf.Ae.Pz

    Cf=Force coefficient for the building Isdepend upon height/ breadth ratio

    Pz=Design wind pressureFOR Z DIRECTION: WINDFORCE

    Ae=Effective frontal area of the structure

    Columnno.

    Height k1 k2 k3 Pz=1.3254*k22KN/m2

    Cf F=Cf.Ae.Pz

    KN/mC1 18 1 1.054 1 1.472 .5 1.288

    C1 12 1 1.01 1 1.352 .5 1.183

    C2 18 1 1.054 1 1.472 .5 2.576

    C2 12 1 1.01 1 1.352 .5 2.366

    C3 18 1 1.054 1 1.472 .5 2.576

    C3 12 1 1.01 1 1.352 .5 2.366

    C4 18 1 1.054 1 1.472 .5 2.576

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    Columnno.

    Height k1 k2 k3 Pz=1.3254*k22KN/m2

    Cf F=Cf.Ae.PzKN/m

    C5 18 1 1.054 1 1.472 .5 2.576

    C5 12 1 1.01 1 1.352 .5 2.366

    C6 18 1 1.054 1 1.472 .5 2.576

    C6 12 1 1.01 1 1.352 .5 2.366

    C7 18 1 1.054 1 1.472 .5 2.576

    C7 12 1 1.01 1 1.352 .5 2.366

    C8 18 1 1.054 1 1.472 .5 2.576

    C8 12 1 1.01 1 1.352 .5 2.366

    C9 18 1 1.054 1 1.472 .5 1.288

    C9 12 1 1.01 1 1.352 .5 1.183

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    For X direction: wind force

    Columnno.

    Height k1 k2 k3 Pz=1.3254*k22KN/m2

    Cf F=Cf.Ae.PzKN/m

    C36 18 1 1.054 1 1.472 .96 2.826

    C36 12 1 1.01 1 1.352 .96 2.595

    C27 18 1 1.054 1 1.472 .96 4.945

    C27 12 1 1.01 1 1.352 .96 4.542

    C18 18 1 1.054 1 1.472 .96 4.945

    C18 12 1 1.01 1 1.352 .96 4.542

    C9 18 1 1.054 1 1.472 .96 2.826

    C9 12 1 1.01 1 1.352 .96 2.595

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    Seismiczone : IV (Table 2, IS 1893Part 1 : 2002)

    Type of soil : medium soil site

    No. of columns : 36

    Seismic analysis : Equivalent staticmethod (IS 1893Part 1 : 2002)

    Imposed load : 3.0 kN/mSpecific weight of RCC : 25 kN/m

    Specific weight of infill : 20 kN/mResponse spectra : As per IS 1893 :2002

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    Ah = Z I Sa2 R g

    where,

    Zone factor (Z) = 0.24

    Importance factor (I) = 1.5 (as per IS1893:2002)

    Response reduction factor(R)= 5 (as per IS

    1893:2002)

    Ta(x) = 0.09h = 0.09x18 =0.488D 11

    Ta(z) = o.09x18 = 0.306

    28

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    Sa/g = 2.5 (0.10Ta0.55)Ah = .119

    Determine base shear:-Vb= Ah.W

    W = 25% of live load + dead load

    Floor level Seismic wt.

    (Wi) Ton

    Vbi= Wi*Ah

    1 292.23 34.77

    2 280.45 33.37

    3 280.45 33.37

    4 280.45 33.37

    5 197.97 23.55

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    VERTICAL DISTRIBUTION OF BASESHEAR FOR DIFFERENT FLOORS :-

    Floorlevel

    Seismicweight(Wi) Ton

    Height(hi), m

    Wi*hi Wi*hi(Wi*hi)

    Qi= vbi * Wi*hi(Wi*hi) Ton

    1292.23 4 4675.68 0.026

    4.12

    2 280.45 7.5 15775.31 0.088 13.977

    3 280.45 11 33934.45 0.191 30.294

    4 280.45 14.5 58964.61 0.332 52.73

    5 197.97 18 64142.28 0.361 57.33

    Total 177492.33