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    ISE 310L Spring 2010GEZA BOTTLIK

    MIDTERM No. 203/29/10

    DO YOUR WORK ON THIS HANDOUT. THIS WILL EXPEDITE THE GRADING OF THEPAPERS.

    NAME ________________________

    MIDTERM SCORE _________________________

    Read these instructions!!

    Please read the problems carefully and provide the information requested and only theinformation requested in each question. Use the minimum amount of work required toanswer each question. Show all your work. The test is worth 75 points. (About 13% of

    your total grade).

    Do your work on this handout you should not need more space.

    The test papers are to be handed in no later than 3:15 P.M. or one hour and 15 minutesafter we start, whichever is later. It is unfair to your fellow students who hand in theirpapers on time to use more time than they had. Approach the problems with this timelimit in mind!

    The test is open notes and open book. Use your calculator or laptop if needed.

    If you want to ask a question, come up to me and ask me. In general it is better to makeassumptions than to ask questions. If you want to borrow your neighbors calculator, askme to do it for you. No talking to your neighbors.

    Move on to the next problem if you are stuck.

    Good luck, I hope you all do well.

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    ISE 310L Spring 2010GEZA BOTTLIK

    MIDTERM No. 203/29/10

    Section No. 1 (1 or 2 points each)1. A single item, a number of items or bulk material which is arranged so that the load canbe stored, and picked up, and moved between two locations defines a Unit Load (2 points)

    2. An uninterrupted flow path progressing directly from origination to destination is a called

    a Directed Path ( 1 point)

    3. Revenue sharing is a method of Increasing supply chain profits ( 1 point)

    4. Regression and time series are used to Forecast demand (1 point)

    5. Two examples of manufacturing layouts are Process and Product, Fixed point,

    cellular( 2 points)

    6. Flow may be measured two ways qualitatively and quantitatively

    ( 2 points)

    7. Cost and lead time are part of Assessing suppliers ( 1 point)

    8. A collection of interacting or independent entities that form a unified whole is a System

    ( 1 point)

    9. The effectiveness of a layout can be measured by Layout score (2 points)

    10. The term routing refers to Sequence of operations on a product = process plan ( 2

    points)

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    ISE 310L Spring 2010GEZA BOTTLIK

    MIDTERM No. 203/29/10

    Problem No. 2

    We spent some time discussing the product design process. As this is not a principal activitythat industrial engineers engage in, why should an industrial engineer be interested in the

    product design process? (15 points)

    The design process generates the design. Usually designers concentrate on functionality at theexpense of manufacturability. By getting involved in the design process, the IE can ensure thatthe product is manufacturable in the most efficient way and has a good supply chain design.

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    ISE 310L Spring 2010GEZA BOTTLIK

    MIDTERM No. 203/29/10

    Problem No. 3You are working for the manager of the supply chain in a firm making and distributing handtrucks such as shown in Figure 7.19 of Garcia. Your assignment is to find ways to encouragethe retailers (who are not part of your firm) to help increase the profit of your supply chain. How

    would you go about doing this? (15 points)

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    ISE 310L Spring 2010GEZA BOTTLIK

    MIDTERM No. 203/29/10

    Problem No. 4

    A production process consists of an automatic assembly machine, followed by manualassembly, soldering and testing. The yield of good assemblies has been measured and found tobe 95%, 90%, 97% for the processes and the ability of test to detect a faulty product is 99%. We

    need to produce 1000 good assemblies per day. We also attempt to repair failed assemblieswith a success rate of 75% and then retest them once. If they fail again, they are discarded.How many assemblies must we start each day? (15 points)

    Initial process yield = .95*.9*.97 = 0.829

    For sure good = 0.829*.99 = 0.821

    Repaired = (1-0.821)*.75 = 0.134

    Repaired good for sure = 0.134*0.99 = 0.133

    Total good = 0.821 + 0.133 = 0.954Number required to start = 1000/0.954 = 1049

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