monday, 4/30tuesday, 5/1wednesday, 5/2thursday, 5/3friday, 5/4 no classes review for tomorrow’s...
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Monday, 4/30 Tuesday, 5/1 Wednesday, 5/2 Thursday, 5/3 Friday, 5/4
No classesReview
for tomorrow’s test
TEST! Quadratic graphs
Quadratic Graphs
Monday, 5/7 Tuesday, 5/8 Wednesday, 5/9 Thursday, 5/10 Friday, 5/11
Quiz on quadratic
graphs
Quadratic Graphs
Transformations of quadratic
graphs
Transformations of quadratic
graphs
Quadratic Formula
Monday, 5/14 Tuesday, 5/15 Wednesday, 5/16 Thursday, 5/17 Friday, 5/18
Quadratic Formula
Reviewfor tomorrow’s
test
Test on quadratic graphs!
Review for Exit Exam
Review for Exit Exam
Monday, 5/22 Tuesday, 5/23 Wednesday, 5/24 Thursday, 5/25 Friday, 5/25
Review for Exit Exam
Review for Exit Exam
Review for Exit Exam
EXIT EXAM!!1
(3PM – 5PM)
Celebration!
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Monday, 5/14 Tuesday, 5/15 Wednesday, 5/16 Thursday, 5/17 Friday, 5/18
Review Reviewfor tomorrow’s
test
Factoring & quadratic
equations TEST
Quadratic graphs
Quadratic Graphs
Monday, 5/21 Tuesday, 5/22 Wednesday, 5/23 Thursday, 5/24 Friday, 5/25
Quadratic graphs
Transformations of quadratic
graphs
Transformations of quadratic
graphs
Quadratic Formula
½ Day: Junior Achievement
Monday, 5/28 Tuesday, 5/29 Wednesday, 5/30 Thursday, 5/31 Friday, 6/1
No classes: Memorial Day
Quadratic Formula
Reviewfor tomorrow’s
test
EXPLORE testing
Test on quadratic functions!
Monday, 6/4 Tuesday, 6/5 Wednesday, 6/6 Thursday, 6/7 Friday, 6/8
Review for final Review for final Review for finalFINAL EXAM Part I
FINAL EXAMPart II
Monday, 6/11 Tuesday, 6/12 Wednesday, 6/13 Thursday, 6/14 Friday, 6/15
Assembly/talent show/
Locker clean out
Reflection No Classes Last Day of School!!!
VACATION!ELLADA!
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Graphs of Quadratics
Let’s start by graphing the parent quadratic function
y = x2
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Graphs of Quadratics
To graph a quadratic, set up a table and plot points
Example: y = x2 x y
-2 4
-1 1
0 0
1 1
2 4
. .
..
.x
y
y = x2
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Standard form of a quadratic y = ax2 + bx + c
a, b, and c are the coefficientsExample:
If y = 2x2 – 3x + 10, find a, b, and c a = 2 b = -3 c = 10
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Characteristics of Quadratic Functions When the power of an equation is 2, then the
function is called a quadratic function The shape of a graph of a quadratic function is
called a parabola. Parabolas are symmetric about a central line
called the axis of symmetry. The axis of symmetry intersects a parabola at
only one point, called the vertex. The lowest point on the graph is the minimum. The highest point on the graph is the maximum.
The maximum or minimum is the vertex
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In general equations have roots,
Functions haves zeros, and
Graphs of functions have x-intercepts
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Axis of symmetry
.x-intercept x-intercept
.
vertexy-intercept
x
y
Characteristics of Quadratic Functions
To find the solutions graphically, look for the x-intercepts of the graph
(Since these are the points where y = 0)
maximum
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Axis of symmetry examples
http://www.mathwarehouse.com/geometry/parabola/axis-of-symmetry.php
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Given the below information, graph the quadratic function.
1. Axis of symmetry: x = 1.52. Vertex: (1.5, -6.25 )3. Solutions: x = -1 or x = 44. y-intercept: (0, -5)
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x
y
..
.(0, -5)
x = 4x = -1
x = 1.5
.(1.5, -6.25)
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Given the below information, graph the quadratic function.
1. Axis of symmetry: x = 12. Vertex: (1, 0)3. Solutions: x = 1 (Double Root)4. y-intercept: (0, 2)
Hint: The axis of symmetry splits the parabola in half
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x
y
.(1, 0)x = 1
x = 1
.(0, 2)
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Graph y = x2 – 41. What is the axis of symmetry?2. What is the vertex?3. What is the y-intercept?4. What are the solutions?5. What is the domain?6. What is the range?
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Ex: Graph y = x2 – 4
x
y
y = x2- 4
2. What is the vertex:
4. What are the solutions:
(x-intercepts)
3. What is the y-intercept:
1. What is the axis of symmetry?
x y
-2 0 -1 -3 0 -4 1 -3 2 0
(0, -4)
x = -2 or x = 2
(0, -4)
x = 0
5. What is the domain? All real numbers
6. What is the range? y ≥ -4
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Finding the y-intercept
Given y = ax2 + bx + c, what letter represents the y-intercept.
Answer: c
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Calculating the Axis of Symmetry Algebraically
Ex: Find the axis of symmetry of y = x2 – 4x + 7
a = 1b = -4c = 7
a
bx
2
2)1(2
4
2
a
bx
2x
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Calculating the Vertex AlgebraicallyEx1: Find the vertex of y = x2 – 4x + 7
a = 1, b = -4, c = 7
y = x2 – 4x + 7 y = (2)2 – 4(2) + 7 = 3
The vertex is at (2, 3)Steps to solve for the vertex:Step 1: Solve for x using x = -b/2aStep 2: Substitute the x-value in the original function to find the
y-valueStep 3: Write the vertex as an ordered pair ( , )
2)1(2
4
2
a
bx
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Ex3: (HW1 Prob #11)
Find the vertex: y = 5x2 + 30x – 4
a = 5, b = 30
x = -b = -30 = -30 = -3 2a 2(5) 10 y = 5x2 + 30x – 4
y = 5(-3)2 + 30(-3) – 4 = -49 The vertex is at (-3, -49)
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Vertex formula: Example: Find the vertex of y = 4x2 + 20x + 5
a = 4, b = 20, c = 5
y = 4x2 + 20x + 5 y = 4(-2.5)2 + 20(-2.5) + 5 = -20
The vertex is at (-2.5,-20)Steps to solve for the vertex:Step 1: Solve for x using x = -b/2aStep 2: Substitute the x-value in the original function to find the
y-valueStep 3: Write the vertex as an ordered pair ( , )
a
bx
2
5.2)4(2
20
2
a
bx
Ex4 (HW1 Prob #9)
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Ex5
Find the vertex: y = x2 + 4x + 7
a = 1, b = 4
x = -b = -4 = -4 = -2
2a 2(1) 2 y = x2 + 4x + 7
y = (-2)2 + 4(-2) + 7 = 3
The vertex is at (-2,3)
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Find the vertex: y = 2(x – 1)2 + 72(x – 1)(x – 1) + 72(x2 – 2x + 1) + 72x2 – 4x + 2 + 72x2 – 4x + 9a = 2, b = -4, c = 9
y = 7 Answer: (1, 7)
1)2(2
4
2
a
bx
(HW1 Prob #12)
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SWBAT… graph quadratic functions. Mon, 5/21
Agenda 1. WU (15 min)2. Graphs of quadratic functions - posters (30 min)
Warm-Up:
1. Take out HW#1: Any questions?
2. Review the weekly agenda
HW#2: Quadratic functions (both sides)
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HW1, Problem #4
Axis of symmetry: x = -2 Vertex: (-2, -1) y-intercept: (0, 3) Solutions: x = -3 or x = -1 Domain: All real numbers Range: y ≥ -1
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Graph y = -x2 + 1 (HW1 Prob #2)
x
y
y = -x2 + 1
2. Vertex: (0,1)
4. Solutions: x = 1 or x = -1
3. y-intercept: (0, 1)
1. Axis of symmetry: x = 0
x y-2 -3 -1 0 0 1 1 0 2 -3
5. What is the domain?
6. What is the range?
All real numbers
y ≤ 1
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Vertex formula: Example: Find the vertex of y = 4x2 + 20x + 5
a = 4, b = 20, c = 5
y = 4x2 + 20x + 5 y = 4(-2.5)2 + 20(-2.5) + 5 = -20
The vertex is at (-2.5,-20)Steps to solve for the vertex:Step 1: Solve for x using x = -b/2aStep 2: Substitute the x-value in the original function to find the
y-valueStep 3: Write the vertex as an ordered pair ( , )
a
bx
2
5.2)4(2
20
2
a
bx
Ex4 (HW1 Prob #9)
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Ex3: (HW1 Prob #11)
Find the vertex: y = 5x2 + 30x – 4
a = 5, b = 30
x = -b = -30 = -30 = -3 2a 2(5) 10 y = 5x2 + 30x – 4
y = 5(-3)2 + 30(-3) – 4 = -49 The vertex is at (-3, -49)
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Find the vertex: y = 2(x – 1)2 + 72(x – 1)(x – 1) + 72(x2 – 2x + 1) + 72x2 – 4x + 2 + 72x2 – 4x + 9a = 2, b = -4, c = 9
y = 7 Answer: (1, 7)
1)2(2
4
2
a
bx
(HW1 Prob #12)
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Graphing Quadratic Functions For your given quadratic find the following
algebraically (show all work on poster!):1. Find the axis of symmetry
2. The vertex (ordered pair)
3. Find the solutions
4. Find the y-intercept (ordered pair)
5. After you find the above, graph the quadratic on graph paper
6. Find the domain
7. Find the range (need the vertex!)
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3 Types of Solutions1. Two real roots
1. Parabolas crosses two different points on the x-axis
2. Double root1. Parabola crosses the same point on the x-axis
3. No real roots1. Parabola does not cross the x-axis
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Exit Slip: Complete on graph paper:
Given y = x2 + 6x + 8 find algebraically:1. The axis of symmetry2. The vertex (as an ordered pair)3. The solutions (x-intercepts)4. The y-intercept (as an ordered pair)5. After you find the above, graph the quadratic 6. Domain7. Range