mole/stoichiometry the awesome team of alyssa h, lauren f, and dylan r
TRANSCRIPT
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Mole/StoichiometryThe awesome team of Alyssa H, Lauren F,
and Dylan R
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Stoichiometry:
• A balanced equation can be in terms of particles, mass, and moles
• Study relationships or ratios between two or more substances going under a physical or chemical change
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Mole:
• The SI based unit used to measure the amount of a substance whose number of particles is the same as the number of atoms of Carbon in exactly 12 grams of Carbon 12
• When you convert from moles to moles use the molar ratio
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Mole to Mole Ratio
• The coefficient in front of the balanced equation is the # of moles
• A mole ratio is required. A mole ratio is the ratio between moles of one substance to moles of another
• ex.) __H2 +__ O2 ---> __ H2O
How many moles of H2O are produced when
5.00 moles of oxygen are used?
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1.) Balance the equation
2H2 + O2 ---> 2H2O
2.) Set up the equation with mole ratio
5 mole O2 2 H2O
1 O2
3.) Cancel out the O2 because they are across from each other.(Cross Multiply)
4.) This leaves you with 10 moles H2O
Mole Ratio
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Mole to Mass Walkthrough
What is the mass of 2.4 moles of Lithium hydroxide (LiOH)
1. find the formula mass for LiOH- 23.95g
2. set up the equation so moles will cancel
2.4 mole LiOH X 23.95g LiOH = 57 grams LiOH
1 mole LiOH
3. multiply across
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Mole to mass practice
1.) 3.79 moles of NaCl, what is the mass
3.79moles NaCl X 58.44g. NaCl=221g. NaCl
1 mole NaCl
2.) 1.63 moles of Hg2Cl, what is the mass
1.63moles Hg2Cl X 436.64g.Hg2Cl = 712g. Hg2Cl
1 mole Hg2Cl
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Mole to Particles Walkthrough
There is 2.4 moles of LiOH, how particles are there
1. use avogadro's number- 6.02 X 10^23
2. set up equation2.4 mole LiOH X 6.02 X 1023 LiOH = 1.4 X 10^24
LiOH
1 mole LiOH
3. multiply across
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Mole to particle practice
1.) 3.79 moles of NaCl, how many particles
3.79moles NaCl X 6.02 X 1023 NaCl=2.28X1024NaCl
1 mole NaCl
2.) 1.63 moles of Hg2Cl, how many particles
1.63moles Hg2Cl X 6.02 X 1023Hg2Cl =2.28X1024Hg2Cl
1 mole Hg2Cl
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Moles to volume Walkthrough
What is the volume of 2.4 moles of Lithium hydroxide (LiOH)
1. use 22.4 liters
2. set up the equation so moles will cancel
2.4 mole LiOH X 22.4 L LiOH = 53.76 L LiOH
1 mole LiOH
3. multiply across
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Mole to volume practice
1.) 3.79 moles of NaCl, how many liter
3.79moles NaCl X 22.4 L NaCl =84.9 L NaCl
1 mole NaCl
2.) 1.63 moles of Hg2Cl, how many liters
1.63moles Hg2Cl X 22.4 L Hg2Cl = 36.5 L Hg2Cl
1 mole Hg2Cl
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Mass to Moles Walkthrough
15g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
0.19molesNH4NO3
If you have 15g NH4NO3 how many moles of NH4NO3 do you have?
1.) You multiply grams of what you are given( 15g NH4NO3) by the mole ratio of the compound.(The mole ratio is 1 mole of the compound over the formula mass of the compound)2.) Simply multiply and BAM you found your answer. 3.) Now you know how to go from grams to moles
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Mass to Moles Practice
25g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
0.31molesNH4NO3
If you have 25g NH4NO3 how many moles of NH4NO3 do you have?
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Mass to Moles Practice
583g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
7.28molesNH4NO3
If you have 583g NH4NO3 how many moles of NH4NO3 do you have?
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Particle:
• To go from moles to particles or particles to moles use Avagadros number
o 6.02 10^23 particles/mole
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Mass to Particles Walkthrough
15g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
1.13 X 1023
formula unitsNH4NO3
If you have 15g NH4NO3 how many particles of NH4NO3
do you have?
1.) You multiply grams of what you are given( 15g NH4NO3) by the mole ratio of the compound.(The mole ratio is 1 mole of the compound over the formula mass of the compound)2.) Next multiply the third block which is 6.02 X 1023 formula units over 1 mole of the compound.3.) You can plug this into your wiz bang and BAM you have found formula units from moles
6.02 X 1023 formula units 1 mol NH4NOX
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Mass to Particles Practice
73g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
5.49 X 1023
formula unitsNH4NO3
If you have 73g NH4NO3 how many particles of NH4NO3
do you have?
6.02 X 1023 formula units 1 mol NH4NO
X
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Mass to Particles Practice
68g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
5.11 X 1023
formula unitsNH4NO3
If you have 68g NH4NO3 how many particles of NH4NO3
do you have?
6.02 X 1023 formula units 1 mol NH4NO
X
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Mass to Mass Walkthrough
30g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
If you have 30g NH4NO3 how many grams of H2O do you have?NH4NO3 N2O + H2O
1.) Balance the equation. NH4NO3 N2O + 2H2O2.) Multiply the grams of what you're given (30g) by 1 mole of the compound you're given over the formula mass of that compound3.) Next multiply by the mole ratio using the balanced formula4.) Finally multiply by the formula mass of what you're finding of 1 mole of what you're finding5.) Shazaam you've just converted from mass to mass
2 mol H2O1 mol NH4NO3
X18.02g H2O1 mol H2O
X13.5g H2O
Formula Mass of NH4NO3
Mole RatioFormula Massof H2O
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Mass to Mass Practice:
60g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
If you have 60g NH4NO3 how many grams of H2O do you have?NH4NO3 N2O + H2O
2 mol H2O1 mol NH4NO3
X18.02g H2O1 mol H2O X
27.02g H2O
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Mass to Mass Practice:
78g NH4NO3 X 1 mol NH4NO
80.04g NH4NO3
If you have 78g NH4NO3 how many grams of H2O do you have?NH4NO3 N2O + H2O
2 mol H2O1 mol NH4NO3
X18.02g H2O1 mol H2O X
35.12g H2O
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Particle to Mole Walkthrough
If you have 4X1024 particles of NH3 how many moles of NH3 are there?
1.)Check to make sure the equation is balanced
2.)Multiply 4X1024 by Avogadro's Number
3.) Make sure to place Avogadro's Number on the numerator or denominator in order to cancel out units and leave moles
2NH3+H2SO4 (NH4)2SO4
4X1024 particlesNH31moleNH3
6.02X1023particl
esNH3
6.6molsNH3
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Particle to Mole Practice
1.)There is 8.76X1022 particles of H2SO4 convert to moles.
2NH3+H2SO4 (NH4)2SO4
8.76X1022 particles H2SO4
1moleH2SO4
6.02X1023particlesH2SO4
.146molsH2SO4
2.49X1017particles (NH4)2SO4
1mole(NH4)2SO4
6.02X1023particles(NH4)2SO4
4.13X10-7mols(NH4)2SO4
2.)How many moles is 2.49X1017 particles of (NH4)2SO4?
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Particle to Mass Walkthrough
If you have 6.82X1020 particles of O2 how many grams of O2 are there?
1.)Check to make sure the equation is balanced
2.)Multiply 6.82X1020 by Avogadro's Number and 1mole and make particle units cancel
3.)Multiply again by formula mass of O2 over 1mole to cancel out mole units leaving gramsO2
O2+2H2 2H2O
6.82X1020
particlesO2
1moleO2
6.02X1023parti
clesO2
.0363gO232gO2
1moleO2
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Particle to Mass Practice
1.)1.67X1018particlesH2 is how many grams?O2+2H2 2H2O
1.67X1018
particlesH2
1moleH2
6.02X1023parti
clesH2
5.59X10-6gH22.016gH2
1moleH2
2.)8.43X1022particlesH2O is how many grams?
8.43X1022
particlesH2O1moleH2O
6.02X1023particl
esH2O
2.52gH2O18.016gH2O
1moleH2O
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Particle to Particle Walkthrough
If you have 6X1015 particles of Fe how many particles of FeCl3 are there?
1.)Check to make sure the equation is balanced
2.)Multiply by Avogadro's Number
3.)Multiply by the mole to mole ratio
4.)Go back to particles by multiplying by Avogadro again
5.)cancel out units and leave particlesFeCl3
2Fe+3Cl2 2FeCl3
6X1015 part.Fe 1molFe6.02X1023particlesFe
6X1015particlesFeCl3
2molFeCl3
2molFe
6.02X1023particlesFeCl31molFeCl3
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Particle to Particle Practice
1.)8X1020particles Cl2 is___ particles of Fe?2Fe+3Cl2 2FeCl3
8X1020 part.Cl21molCl26.02X1023particlesCl2
5.3X1020particlesFe
2molFe
3molC2
6.02X1023particlesFe1molFe
2.)1.7X1019particlesFe is ___ particles of Cl2?
1.7X1019 part.Fe 1molFe6.02X1023particlesFe
2.55X1019particlesCl2
3molCl2
2molFe
6.02X1023particlesCl21molCl2
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Volume to Mole Walkthrough
If you have 8L of Carbon how many moles are there?
1.)Check to make sure the equation is balanced
2.)Multiply 8L by 22.4L/moles
3.) Make sure to place the correct unit on the numerator or denominator in order to cancel out units and leave moles
2As2O3+3C 3CO3+4As
8LC 1moleC22.4LC
.4molsC
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Volume to Mole Practice
1.) If you have 2.5L of As2O3 how many moles is it?
2As2O3+3C 3CO3+4As
2.5LAs2O31moleAs2O3
22.4LAs2O3
.11molesAs2O3
2.) There is 11L of CO2 what is that in moles?
11LCO21moleCO2
22.4LCO2
.49molesCO2