molecular genetics handout (1)

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    1

    1. The process of DNA synthesis follows this order:

    A.

    B.

    C.

    D.

    winding, pairing, joining

    pairing, joining, pairing

    unwinding, pairing and joining

    joining, pairing, unwinding

    22. Which is NOT a requirement for DNA replication?

    A.

    B.

    C.

    D.

    Deoxynucleoside triphosphates (dNTPs)

    ATP

    Primer

    None of the above

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    3. All of the following DNA Replication enzymes can alsobe utilized in DNA excision repair, EXCEPT:

    A.

    B.

    C.

    D.

    Endonuclease

    DNA ligase

    DNA polymerase

    All can be used

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    Stage Component

    Initiation Promoter

    -TATA box*

    Transcription Factors

    -Sigma Factor*

    RNA Polymerase

    Ribonucleotides

    Elongation RNA Polymerase

    Helicase*

    More Ribonucleotides

    Termination Termination Sequence-Hairpin, Rho factor*

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    4. Eukaryotic mRNA production occurs in the following

    sequence:

    A.

    B.

    C.

    D.

    Transcription from DNA in the cytoplasm followed

    by post-transcriptional processing on the ribosome

    Transcription from DNA in the nucleus followed by

    post-transcriptional processing in the nucleus

    Transcription from DNA in the ribosome followed

    by post-transcriptional processing in the cytoplasm

    Transcription from DNA in the cytoplasm followed

    by post-transcriptional processing in the nucleus

    55. If the base sequence of a strand of DNA is 5'-GATTCAAGTAGTC-3,

    what would be the corresponding base sequence on the newly

    transcribed RNA strand?

    A.

    B.

    C.

    D.

    5'-GAUUCAAGUAGUC-3'

    5'-GACUACUUGAAUC-3

    5'-CUAAGUUCAUCAG-3

    5'-CTAAGTTCATCAG-3

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    6. Which of the following is true concerning the genetic

    code?

    A.

    B.

    C.

    D.

    There are more amino acids than codons.

    Any change in the nucleotide sequence of a codon

    must result in a new amino acid.

    The genetic code varies from species to species.

    There is no codon that can code for more than one

    amino acid.

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    7. Codons that specify the same amino acid can differ only in the

    A.

    B.

    C.

    D.

    First base

    Second base

    Third base

    All of the above

    5

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    8. Which of the following occurs when the eukaryotic

    translational machinery encounters the UAG codon?

    A.

    B.

    C.

    D.

    The bound preinitiation complex stops scanning and positions the Met-tRNA at this site.

    The termination factors recognize this codon and translation ends.

    This codon is recognized by the corresponding anticodon of a tRNA molecule that is linked to glycine.

    This codon is not recognized by any factors.

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    9. A certain cell is exposed to a chemical that inhibits

    ribosome movement. This will:

    A.

    B.

    C.

    D.

    instantly stop all DNA transcription.

    immediately halt DNA replication.

    prevent effective protein synthesis.

    decrease the speed of protein synthesis.

    6

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    10. Several types of noncovalent bonds are involved

    in protein-protein interactions and by extension in

    interactions between portions of a single protein. Whichof the following bonds are apt to be more common in the

    nonaqueous, interior environment of a protein than in the

    aqueous, surface environment of a protein?

    A.

    B.

    C.

    D.

    Ionic bonds.

    Hydrophobic bonds.

    Hydrogen bonds.

    Covalent bonds.

    11

    11. Which of the following statements about protein

    denaturation is correct?

    A.

    B.

    C.

    D.

    Denaturation can be irreversible

    Proteins are pH and temperature resistant

    Denaturation only occurs through enzymatic

    modification of proteins

    Denaturation does not change the tertiary structure

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    13. If Griffith had injected a fifth group of mice with a

    combination of heat-killed rough strain and heat-killed

    smooth strain, would the mice have died?

    A.

    B.

    C.

    D.

    No, because live bacteria must be present to produce the lethal effect.

    No, because the heat-killed smooth strain cannot transform mice cells.

    Yes, because the heat-killed rough strain is transformed into the smooth strain.

    Yes, because the mice do not have acquired immunity to pneumococcus bacteria.