module 1 lesson 1-11 review.notebook · module 1 lesson 111 review.notebook 13 september 26, 2016...
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Module 1 Lesson 111 Review.notebook
1
September 26, 2016
Sep 229:04 AM
Review for Module 1 Lesson 1-11 Test
HWStudy for Module 1 Lesson 1-11
Test Tomorrow
Do Now:Write the converse of the conditional statement:
If parallel lines are cut by a transversal then alternate interior angles are equal
Sep 242:48 PM
Do Now:Write the converse of the conditional statement:
Conditional: If parallel lines are cut by a transversal then alternate interior angles are equal
Converse: If alternate interior angles are equal then there are parallel lines cut by a transversal
Module 1 Lesson 111 Review.notebook
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1. Construct circle A, center A radius AB
2. Construct circle B, center B, radius AB
3. Label one point of intersection as C
4. Draw segments AC and BC
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1. Create a circle with the center at the stake, and the radius of Bailey's leash
2. Create a circle with the center at the stake, and the radius of Daisy's leash
3. Put X's at point of intersection
0°
122
Module 1 Lesson 111 Review.notebook
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Tina is correct because the cirlces at centers D
and G with radius DG do not intersect at point O.
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1. Create circle B, any radius
2. Label points of intersection as E and D
3. Create circles with center E and center D, radius DE
4. Label the point of intersection as F
5. Draw ray BF
1. Create circle A, any radius
2. Label points of intersection as C and B
3. Draw ray FE
4. Draw circle F radius BC
5. Label points of intersection as H and G
6. Draw circle G radius BC
Module 1 Lesson 111 Review.notebook
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1. Construct circle A, center A radius AB
2. Construct circle B, center B, radius AB
3. Label one point of intersection as C and D
4. Draw segment CD
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1. Construct circle P any radius such that it intersects line ST twice.2. Construct circle A, center A radius AB
3. Construct circle B, center B, radius AB
4. Label one point of intersection as C and D
5. Draw segment CD that passes through point P
Module 1 Lesson 111 Review.notebook
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Altitudes
Angle Bisectors
Medians
Perpendicular Bisectors
False (only 1 right angle created, perpendicular lines have 4True ( C is the midpoint)True ( C is the midpoint)True (Both are right angles)
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x and y are supplementary anglesy + x = 180y + 103 = 180 -103 -103
y = 77
x = 103 because Vertical angles are
equal to one another
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3,4 4,5 5,6 3,6 1,2
3,4 4,5 5,6 3,6 1,2
6,4 3,5
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x and <ABC are supplementary anglesx + 110 = 180 -110 -110
x = 70
<ABD = 70 because <ABD and <x equal one another <ABD + x + <DBC = 180
70 + 70 + <DBC = 180 140 + <DBC = 180 -140 -140 <DBC = 40
y and 115 are supplementary anglesy + 115 = 180 -115 -115
y = 65
65 + 2x + 65 - 10 = 180 120 + 2x =180 -120 -120 2x = 60 2 2 x = 30
Module 1 Lesson 111 Review.notebook
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<1 and <2 are Same side interior supplementary angles <1 + <2 =180 7x - 36 + 5x + 12 = 180 12x - 24 = 180 + 24 +24 12x = 204 12 12
x = 17
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y = 30 because of alternate interior angles
z = 80 because of vertical angles
x + y + z = 180
x + 30 + 80 = 180
x + 110 = 180
-110 -110
x = 70
Module 1 Lesson 111 Review.notebook
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<RTQ = 63 because of alternate interior angles
<2 + 90 + 63 = 180
<2 + 153 = 180
-153 -153
<2 = 27
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opposite interior angle + opposite interior angle = exterior angle
x + 40 + 4x - 5 = 6x + 20 5x + 35 = 6x + 20 -5x -5x 35 = x + 20 -20 - 20
15 = x
<QPT = 6x + 20 <QPT= 6(15) + 20<QPT = 90 + 20
<QPT = 110
Module 1 Lesson 111 Review.notebook
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Consecutive Angles on a straight line sum to 180 x + 40 + 90 = 180 x + 130 = 180 - 130 -130 x = 50
Supplementary angles sum to 180 y + 40 = 180 -40 -40 y = 140
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<a = 48 because of alternate interior angles
Supplementary angles sum to 180180 - 118 = 62
<b = 62 because of alternate interior angles
Module 1 Lesson 111 Review.notebook
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<1 = 70, corresponding angles<2 = 55, alternate interior angles
<x = <1 + <2 = 70 + 55 = 125
<x = 125 degrees
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43Alternate interior angles are equal
94 + 43 + e =180 137 + e = 180 -137 -137 e = 43
43Angles in a triangle sum to 180
43 + 43 + k =180 86 + k = 180 -86 -86 k = 94
94Consecutive Angles on a straight line sum to 180
Module 1 Lesson 111 Review.notebook
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<1 + 98 = 180 same side supplementary
- 98 -98
<1 = 82 <2 = 46, alternate interior angles
<x = <1 + <2 vertical angles<x = 82 + 46<x = 128
128
Vertical angles are equal to one another
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a
a + 110 = 180 -110 -110 a = 70
70
Linear Pairs form supplementary angles
Module 1 Lesson 111 Review.notebook
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70b + 70 + 90 = 180
b + 160 = 180
-160 -160
b = 20
20
Angles in a triangle sum to 180 degrees
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Linear pairs form supplementary angles
Linear pairs form supplementary angles
Angles in a triangle sum to 180 degrees
Substitution Property of Equality
Module 1 Lesson 111 Review.notebook
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1. Given1. AB ll CD
2. AB ll L, L ll CD 2. Auxillary line L drawn in through G
3. <x = <13. If parallel lines are cut by a transversal then corresponding angles are equal
4. <w = <24. If parallel lines are cut by a transversal then corresponding angles are equal
6. <x + <w = <15. <1 + <2 = <y
6. Substitution Property of Equality
5. Angle Addition Postulate
Sep 229:09 AM
1. <a = <1 1. Vertical Angles are equal to one another
2. <1 + <b + <c = 180
3. <a + <b + <c = 180
2. Consecutive angles on a straight line sum to 180 degrees
3. Substitution Property of Equality