modern physics
DESCRIPTION
Modern Physics. By Neil Bronks. Mass Number - Number of protons + Neutrons. Atomic Number - Number of protons. Atoms. C. 12. 6. In a neutral atom the number of electrons and protons are the same. In Carbon it is………. 6. Hydrogen. - PowerPoint PPT PresentationTRANSCRIPT
Modern Physics
By
Neil Bronks
Atoms
C12
6
Mass Number - Number of protons + Neutrons.
Atomic Number - Number of protons
In a neutral atom the number of electrons and protons are the same. In Carbon it is……… 6
Hydrogen
Electron
Proton
The simplest atom has one negative electron orbiting one positive proton.
The electron is very light compared to the proton.
Helium
Neutron
In this atom we see two neutrons and two protons forming the nucleus.
The Neutron has no charge but is the same mass as the proton.
Electron
Proton
4 Forces of Nature (Order of strength)
Gravitational
- Only Positive
- Very long range
Weak Nuclear- Associated with beta
decay
Strong Nuclear –
Holds nucleus together
- Very Short Range
Electromagnetic – Positive and negative
Radiation
Decay of nucleus by the emission of a particle or a ray.
Discovered by Henri Becquerel Units 1 Bq is one decay per secondNatural happens without outside
bombardmentArtificial happens due to bombardment
J’ai fais ça !Dodgy
Beard
Safety
Wear Gloves or Apron of lead
Don’t point at anyone
Don’t eat!!!
Nuclear Equations
Top and bottom must add upTop is mass numberBottom is atomic numberProton H Neutron electronAnd Alpha
H11 n10 e10
HeThU 42
23490
23892
Alpha Particles
Helium NucleiPositive ChargeHeavy so not very penetratingVery Ionizing
147N +4
2He 178O + 1
1H
HeThU 42
23490
23892
Beta Particle ß
Fast electron from the nucleus Negative charge Moderately Penetrating Moderately ionizing
147N 14
8O + 0-1 ß
0123491
23490 PaTh
Gamma Ray
High energy e-m wave (A Photon)No charge - not deflected by fieldVery penetrating – Need lead to stop
most of themNot very ionizingRelease energy after reaction
Penetrating Power
Paper Al foil Concrete
H/W
LC Ord 2007Q11
Particles in Fields
Charged particles move in a circular path as the force is always at right angles to the direction of motion-
Fleming's Left Hand Rule
RadioactiveSource Cloud
Chamber
Click here for internet demo
Ionisation
We can prove that radiation creates ions as we bring a source close to a charge electroscope
Ionising Power
Alpha is heaviest and so does most damage – poison with Polonium
Beta is only moderately ionisingGamma is only slightly ionising but
difficult to stop
Solid State Detector
P N
This a P-N junction in reverse bias.
This creates a huge depletion layer.
+-
A piece of radiation passes through the depletion layer and creates enough carriers to carry one pulse of current.
Geiger Muller Tube
H/W
LC Ord 2004Q10
Experiments
All experiments the same stick a DETECTOR in front of a source and count the decays.
Move it away for distance and plotTime for half life and plotPut things in front for penetration
Penetration
A Gieger Muller Tube and Counter.
Plot the activity against the thickness or the type of barrier
Distance
A Gieger Muller Tube and Counter.
Plot the activity against the distance r.
r
Half Life
A Gieger Muller Tube and Counter.
Plot the activity against the time
Time it takes for half the atoms to decay
Half-Life – time it takes for half the radioactive particles to decay
Atoms Not Decayed
Time1 2 3 4
Half life demo from internet click here
Half Life Calculations
1000 particles time=6s 2 half-life
500 particles time=9s 3 half-life
250 particles time=12s 4 half-life
125 particles time=15s 5 half-life
4000 particles time=0
2000 particles time=3s 1 half-life
Calculations – we use the decay constant λ in our calculations.
=0.693/T½
=0.693/3s
=0.231s-1
Activity Calculations
Rate of Decay = x number you started with
dN/dt = - x N
Start with 4000 particles and =0.231
Activity = 4000 x 0.231=924 Bq
Calculations
1) You start with 100 grams of sulfur-35, which has a half life of 87.51 days. How much time will it take until only 12.5 grams remain?
How many half lives?100>50>25>12.5 so 3 half livesTime = 3 x 87.51 = 262.53 days
Calculations2) You measure the radioactivity of a substance,
then when measuring it 120 days later, you find that it only has 25 % of the radioactivity it had when you first measured it. What is the half life of that substance?
How many half lives100%>50%>25%2 half lives =120 days1 half life = 60 days
Calculations
3) Your professor gives you 64g of phosphorus-32 (half life = 14.263 days).
(a) What is its decay constant ? (b) What is its activity (Rate of Decay)?
(a) Using the formula =0.693/T½
=0.693/(14.263x24x60x60) = 6.62 x 10-7 s-1
Calculations
3) Your professor gives you 64g of phosphorus-32 (half life = 14.263 days).
(a) What is its decay constant ? (b) What is its activity (Rate of Decay)?
= 6.62 x 10-7 s-1 (b) Using Activity =dN/dt = -N N= Moles x 6x1023 = 2 x 6x1023 Activity = 6.62 x 10-7 x 12x1023 == 7.3 x1017 Bq
Isotopes
Same atomic number different mass number
Isotope pp
Uses of Radioactive Isotopes
Medicine – treatment and imagingSmoke detectors Food IrradiationCarbon-14 Dating
Isotopes
Same Atomic number different Mass number
Carbon-14 Dating
At death all animals contain the same ratio of C-14 to C-12
The rate of decay of C-14 is fixedThe C-14 left tells us how long ago it
died
%C-14
time
H/W
LC Ord 2005 Q12(d)LC Higher 2003 Q11LC H 2007 12(d)
Rutherford Scattering
Do I look like Freddie?
Rutherford on internet
Rutherford Scattering – alpha particles fired at gold foil.
Most pass unaffected - So the nucleus is very small
Rutherford Scattering – alpha particles fired at gold foil.
Nucleus
A small number of high energy alphas are Deflected
Some reflected completely back - Nucleus totally positive.
Rutherford Scattering – alpha particles fired at gold foil.
Nucleus
A small number of high energy alphas are DeflectedMore pass unaffected - So the nucleus is very smallSome reflected completely back - Nucleus totally
positive.
Cockcroft and Walton
Alpha Alpha a
LithiumTarget
Alpha Alpha
Hydrogen discharge tube
Accelerated byAn huge electricField (700000v)
Proton
Alpha strikes the screenProducing a flash thatIs seen with the microscope
Internet explanation
Nobel Prize for Physics
Proton + Lithium 2xAlpha + Energy
Proves Einstein’s Law E=mc2
First Transmutation by artificial Bombardment of an element
Ernest Walton
EnergypLi 42
42
11
73
Binding Energy
The total nucleus weighs less than all its parts
Difference is Mass DefectConverted to energy to hold the nucleus
together
E=mc2
As Iron is the most stable as you go towards it you release energy
So Carbon-12 is lighter than 12 protons The difference is the binding energy
Binding Energy of a Deuteron
A deuteron is the nucleus of a deuterium atom, and consists of one proton and one neutron. The masses of the constituents are:
mproton = 1.007276 u (u is Atomic mass unit) mneutron= 1.008665 u mproton + mneutron = 1.007276 + 1.008665 = 2.015941 u
The mass of the deuteron is: Atomic mass 2H = 2.013553 u
The mass difference = 2.015941 - 2.013553
= 0.002388 u
Convert to Kg
Multiply by conversion factor1u = 1.66x10-27 KgMass = m = (0.002388) x 1.66x10-27
Mass = m = 3.96x10-30 Kg
Use Famous Formula
E=mc2
E= 3.96x10-30 Kg x (3x108 m/s) 2
E = 3.56x10-13 Joules
Fusion – The sun and the stars
Fusion is the joining together of 2 light nuclei to make one nucleus with release of energy.
Caused by a super fast collision at high temperature in a magnetic bottle.
21H 2
1H
Fission
The breaking apart of a heavy nucleus to form smaller nucleus with release of energy.
Caused artificially by the bombardment of the right speed of neutron.
In both fusion and fission the products are lighter than the reactants and the MASS DEFECT is turned into Energy E=mc2
1. Subtract mass in a.m.u.
2. Convert to kg
3. Use E=mc2
Also produced 3 fast neutrons that can cause another fission and so a chain reaction
Uranium-235
Nuclear Equation
EnergynBaKrnU 10
13956
9736
10
23892 3
In the isotope U-238 the neutrons must be slowed down by a moderator - Graphite
Fuel rods contain the Uranium-235 (Enriched to ensure chain reaction)
Moderators (Graphite) slow down the neutrons to the right speed
Control Rods (Boron Steel) absorb neutrons to stop the reaction and prevent meltdown
Heat to heat exchanger prevents Radiation escaping steam to turbine
H/W
LC Ord 2006Q 9
Leptons
Fundamental particles
1/1846 of an a.m.u.
Does not feel the strong nuclear force
Matter – Electron , Muon, Tau, ……
Anti-matter – Positron, Anti-Tau
Anti-matter first suggested by Paul Dirac
Annihilation
e+
e-
Matter combining with anti-matter to form energy in the form of e-m radiation
2 photons conserve momentum ?
e+ + e- 2hf (2g)
Annihilation
e+
e-
An electron and a positron collide to make energy.
All the mass of the electrons gets turned into gamma waves
So Energy E=mc2
To find frequency of wave E = 2h.f
Matter turnsInto energy
Matter combining with anti-matter to form energy in the form of e-m radiation
2 photons conserve momentum
Wave made by Anihilation
A proton and a Anti proton. The masses of the constituents are:
mproton = 1.007276 u (u is Atomic mass unit)
mproton + manti = 1.007276 + 1.007276 = 2.014552 u
The mass difference = 2.014552 uTo use this in a calculation we covert to kg
Convert to Kg
Multiply by convertion factor1u = 1.66x10-27
Mass = m = (2.014552) x 1.66x10-27
Mass = m = 3.34x10-27 Kg
Use Famous Formula
E=mc2
E= 3.34x10-27 Kg x (3x108 m/s) 2
E = 3.01x10-10 Joules
Use Planks Equation E=hf
h= planks constant3.01x10-10 Joules = (6.6x10-34 js)x(f)f= 3.01x10-10 Joules / 6.6x10-34 js
= 4.56x1023 Hz
In practice this is low as KE from particles increases this.
Pair Production
e+
e-
An electron and a positron are created from a gamma ray. (We can also get a proton and an anti-proton)
We do the calculation in reverse
To find energy of wave E = h.f
As we get 2 electrons E = 2mc2
A matter and anti-matter pair being created by energy from an e-m wave
Annihilation and Production
p+
p-
New particles are produced from the KE of the colliding protons They must conserve charge
If we carry in 4Gev (1.6x10-19 . 4x109= 6x10-10 J)
As Energy to make 3 Pions is E=mc2 =(3x 2.4842x10-
28xcxc)
=6.7x10-11 J
Subtracting we find the KE after collision.
p+
p-
+
0
-
H/W
LC Higher 2003 10(a)
Quarks - Inside the Hadrons
6 Quarks6 Anti-Quarks – Opposite Signs
UP
+2/3
STRANGE -1/3
TOP
+2/3
DOWN
-1/3
CHARMED +2/3
BOTTOM -1/3
Hadrons
Baryons Mesons
3 quarks Quark+anti-quark
Proton Pion
uud ud
Feels strong nuclear force
Feels strong nuclear force
Baryon
Meson
Hadrons on internet
Subject to all forces
Particle Zoo
HadronsLeptons
Fundamental particles
Do not feel Strong Nuclear
Force
Baryons
3 Quarks
Protonuud
Mesons
Quark +Anti-quark
Pionud
Ghost Particle Mystery
By 1930 most of the particle physics world was understood
However the decay of the neutron to a proton producing a beta particle did not obey Einstein's Law
n0 → p+ + e-
Pauli said there must be a new particle called a neutrino
Beta decay
In β− decay, the weak force converts a neutron into a proton while emitting an electron and an antineutrino
n0 → p+ + e- + νe
This explains loss in energy and momentum. Pauli
proposed it’s existence in 1930 but was not
discovered until 1956 as it is so weakly interacting
with other particles.
Nuclear Formula
00
01
11
10 pn
Particle Accelerators-Linear
Very high Voltage electric fields
Electro-magnetic attraction pulls particles down.
Circular Accelerators
Particles spiral in fields (Flemings Left hand rule)
Cyclotron- We put the field at right angles e more power with oscillating field
CERN
Particles can travel in opposite directions and double the collision energy
Magnets force particles in
circular path so stay in tube
Circular more
compact
High velocity needed to overcome repulsion
Vacuum to avoid collisions increase mean
free path
More velocity more KE so more new
particles made
Detectors
H/W
LC Ord 2002 Q11LC Higher 2004 10(a)
H/W Roundup (Yeh har)
2007 q112004 q102003 q112005 q12(d)2006 q 92003 10(a)