mendelelian genetics
DESCRIPTION
Mendelelian Genetics. Gregor Mendel (1822-1884). Responsible for the Laws governing Inheritance of Traits. Gregor Johann Mendel. Austrian monk Studied the inheritance of traits in pea plants He found that the plants' offspring retained traits of the parents - PowerPoint PPT PresentationTRANSCRIPT
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Mendelelian Genetics
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Gregor Mendel
(1822-1884)
Responsible for the Laws governing
Inheritance of Traits
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Gregor Johann MendelAustrian monkStudied the inheritance of traits in pea plantsHe found that the plants' offspring retained traits of the parentsCalled the “Father of Genetics"
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Mendel stated that physical traits are inherited as “particles”Mendel did not know that the “particles” were actually Chromosomes & DNA
Particulate Inheritance
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Genetic Terminology
Trait - any characteristic that can be passed from parent to offspring Heredity - passing of traits from parent to offspring Genetics - study of heredity
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Types of Genetic CrossesMonohybrid cross - cross
involving a single traite.g. flower color Dihybrid cross - cross involving two traits e.g. flower color & plant height
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Punnett Square
Used to help solve genetics problems
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Designer “Genes”Alleles - two forms of a gene
(dominant & recessive) Dominant - stronger of two genes expressed in the hybrid; represented by a capital letter (R) Recessive - gene that shows up less often in a cross; represented by a lowercase letter (r)
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More Terminology
Genotype - gene combination for a trait (e.g. RR, Rr, rr) Phenotype - the physical feature resulting from a genotype (e.g. red, white) (e.g. red, white)
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Genes and Environment Determine Characteristics
pH of soil can change the color of hydrangea plants
Temperature and season can change fur color of animals
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Generation “Gap”
Parental P1 Generation = the parental generation in a breeding experiment.
F1 generation = the first-generation offspring in a breeding experiment. (1st filial generation)From breeding individuals from the P1 generation
F2 generation = the second-generation offspring in a breeding experiment. (2nd filial generation) From breeding individuals from the F1 generation
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Following the Generations
Cross 2 Pure
PlantsTT x tt
Results in all
HybridsTt
Cross 2 Hybridsget
3 Tall & 1 ShortTT, Tt, tt
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Monohybrid Crosses
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Trait: Seed ShapeAlleles: R – Round r – WrinkledCross: Round seeds x Wrinkled seeds
RR x rr
P1 Monohybrid Cross
R
R
rr
Rr
RrRr
Rr
Genotype: Rr
Phenotype: Round
GenotypicRatio: All alike
PhenotypicRatio: All alike
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P1 Monohybrid Cross ReviewHomozygous dominant x
Homozygous recessiveOffspring all Heterozygous (hybrids)Offspring called F1 generation
Genotypic & Phenotypic ratio is ALL ALIKE
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Trait: Seed ShapeAlleles: R – Round r – WrinkledCross: Round seeds x Round seeds
Rr x Rr
F1 Monohybrid Cross
R
r
rR
RR
rrRr
Rr
Genotype: RR, Rr, rr
Phenotype: Round & wrinkled
G.Ratio: 1:2:1
P.Ratio: 3:1
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F1 Monohybrid Cross ReviewHeterozygous x heterozygousOffspring:
25% Homozygous dominant RR50% Heterozygous Rr25% Homozygous Recessive rrOffspring called F2 generationGenotypic ratio is 1:2:1Phenotypic Ratio is 3:1
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What Do the Peas Look Like?
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…And Now the Test Cross
Mendel then crossed a pure & a hybrid from his F2 generation
This is known as an F2 or test cross
There are two possible testcrosses:Homozygous dominant x HybridHomozygous recessive x Hybrid
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Trait: Seed ShapeAlleles: R – Round r – WrinkledCross: Round seeds x Round seeds
RR x Rr
F2 Monohybrid Cross (1st)
R
R
rR
RR
RrRR
Rr
Genotype: RR, Rr
Phenotype: Round
GenotypicRatio: 1:1
PhenotypicRatio: All alike
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Trait: Seed ShapeAlleles: R – Round r – WrinkledCross: Wrinkled seeds x Round seeds
rr x Rr
F2 Monohybrid Cross (2nd)
r
r
rR
Rr
rrRr
rr
Genotype: Rr, rr
Phenotype: Round & Wrinkled
G. Ratio: 1:1
P.Ratio: 1:1
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F2 Monohybrid Cross ReviewHomozygous x heterozygous
(hybrid)Offspring:50% Homozygous RR or rr50% Heterozygous RrPhenotypic Ratio is 1:1Called Test Cross because the offspring have SAME genotype as parents
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Results of Monohybrid Crosses
Inheritable factors or genes are responsible for all heritable characteristics
Phenotype is based on Genotype Each trait is based on two genes,
one from the mother and the other from the father
True-breeding individuals are homozygous ( both alleles) are the same
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Mendel’s Laws
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Law of Dominance
In a cross of parents that are pure for contrasting traits, only one form of the trait will appear in the next generation.
All the offspring will be heterozygous and express only the dominant trait.
RR x rr yields all Rr (round seeds)
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Law of Dominance
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Law of Segregation
During the formation of gametes (eggs or sperm), the two alleles responsible for a trait separate from each other.
Alleles for a trait are then "recombined" at fertilization, producing the genotype for the traits of the offspring.
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Applying the Law of Segregation
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Law of Independent Assortment
Alleles for different traits are distributed to sex cells (& offspring) independently of one another.
This law can be illustrated using dihybrid crosses.
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Test CrossA mating between an individual of unknown
genotype and a homozygous recessive individual.
Example: bbC__ x x bbcc
BB = brown eyesBb = brown eyesbb = blue eyes
CC = curly hairCc = curly haircc = straight hair
bC b___
bc
bc
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Test Cross
Possible results:
bCbC b___
bcbc bbCc bbCc
CC bC b___
bc bbCc bbccor
c
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Incomplete Dominanceand
Codominance
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Incomplete Dominance
F1 hybrids have an appearance somewhat in between the phenotypes of the two parental varieties.
Example: snapdragons (flower)red (RR) x white (rr)
RR = red flowerrr = white flower
R
R
r r
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Incomplete Dominance
RrRr
RrRr
RrRr
RrRr
R
R
r
All Rr = pink(heterozygous pink)
produces theF1 generation
r
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Incomplete Dominance
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CodominanceTwo alleles are expressed (multiple
alleles) in heterozygous individuals.Example: blood type
1. type A = IAIA or IAi2. type B = IBIB or IBi3. type AB= IAIB
4. type O = ii
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Codominance Problem
Example: homozygous male Type B (IBIB)
x heterozygous female Type A (IAi)
IAIB IBi
IAIB IBi
1/2 = IAIB
1/2 = IBi
IB
IA i
IB
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Another Codominance Problem
• Example:Example: male Type O (ii) x female type AB (IAIB)
IAi IBi
IAi IBi
1/2 = IAi1/2 = IBi
i
IA IB
i
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Codominance
Question:If a boy has a blood type O and his sister has blood type AB, what are the genotypes and phenotypes of their parents?
boy - type O (ii) X girl - type AB (IAIB)
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Codominance
Answer:
IAIB
ii
Parents:genotypes = IAi and IBiphenotypes = A and B
IB
IA i
i
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Sex-linked Traits
Traits (genes) located on the sex chromosomes, X and Y
XX genotype for femalesXY genotype for malesMany sex-linked traits carried
on X chromosome
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Sex-linked Traits
Sex Chromosomes
XX chromosome - female Xy chromosome - male
fruit flyeye color
Example: Eye color in fruit flies
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Sex-linked Trait Problem
Example: Eye color in fruit flies (red-eyed male) x (white-eyed female)
XRY x XrXr
Remember: the Y chromosome in males does not carry traits.
RR = red eyedRr = red eyedrr = white eyedXY = maleXX = female XR
Xr Xr
Y
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Sex-linked Trait Solution:
XR Xr
Xr Y
XR Xr
Xr Y
50% red eyed female50% white eyed
male
XR
Xr Xr
Y
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Female Carriers
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Dihybrid CrossA breeding experiment that tracks
the inheritance of two traits.
Mendel’s “Law of Independent Assortment”
a. Each pair of alleles segregates independently during gamete formation
b. Formula: 2n (n = # of heterozygotes)
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Question:How many gametes will be
produced for the following allele arrangements?
Remember: 2n (n = # of heterozygotes)
1. RrYy
2. AaBbCCDd
3. MmNnOoPPQQRrssTtQq
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Answer:1. RrYy: 2n = 22 = 4 gametes
RY Ry rY ry
2. AaBbCCDd: 2n = 23 = 8 gametesABCD ABCd AbCD AbCdaBCD aBCd abCD abCD
3. MmNnOoPPQQRrssTtQq: 2n = 26 = 64 gametes
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Dihybrid CrossTraits: Seed shape & Seed colorAlleles: R round
r wrinkled Y yellow y green
RrYy x RrYy
RY Ry rY ry RY Ry rY ry
All possible gamete combinations
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Dihybrid Cross
RY Ry rY ry
RY
Ry
rY
ry
9:3:3:1 phenotypic ratio
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Dihybrid CrossRound/Yellow: 9Round/green: 3wrinkled/Yellow: 3wrinkled/green: 1
9:3:3:1
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Next up, Pedigrees!