mechanics of solids power-point presentation
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The Presentation consists of notes for the mechanics of solids. The explanation of the subject contents and for the ease in study.TRANSCRIPT
Subject: Mechanics of Solids-I CE-104
Instructor: Prof. Dr. Akhtar Naeem Lecturer: Engr. Muhammad Nissar
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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N-W.F.P University of Engineering & Technology Peshawar
Lecture # 1: Basic Concepts
Basic Concepts
• What is Civil Engineering ?1) Civil 2) Engg
• What is Strength of Materials or Mechanics of Solids?
1) Strength of Material2) Mechanics of Solids
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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IntroductionIntroduction•Mechanics of materials is a branch of applied mechanics that deals with the behavior of solid bodies subjected to various types of loading.
•This field of study is known by several names, including "Strength of materials" and "mechanics of deformable bodies.".
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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40 ft span
IntroductionIntroduction
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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• Suspension bridges are good example of structures that carry these stresses. The weight of the vehicle is carried by the bridge deck and passes the force to the stringers (vertical cables), which in turn, supported by the main suspension cables. The suspension cables then transferred the force into bridge towers.
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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IntroductionIntroduction
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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IntroductionIntroduction•The solid bodies considered include axially loaded members, shafts in torsion, thin shells, beams, and columns, as well as structures that are assemblies of these components.
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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IntroductionIntroduction Axial Force. Shear Force Transverse Force
• Torsion
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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IntroductionIntroduction
Deflection due to Load
P
• Usually the objectives of our analysis will be the determination of the stresses, strains, and deflections produced by the loads.
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IntroductionIntroduction
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IntroductionIntroduction•Theoretical analyses and experimental results have equally important roles in the study of mechanics of materials.
•These properties are available to us only after suitable experiments have been carried out in the laboratory.
Also, because many practical problems of great importance in engineering cannot be handled efficiently by theoretical means, experimental measurements become a necessity.
• Theoretical Analysis (Equilibrium and Compatibility Equations).
• Experimental Analysis (Constitutive)
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IntroductionIntroduction
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Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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IntroductionIntroduction
500 N 5000 N
Steel Bar
Equilibrium Equation
Simply Supported Beam
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IntroductionIntroduction
Compatibility Problems
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IntroductionIntroductionConstitutive Problems
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IntroductionIntroductionTypes of Failure:
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IntroductionIntroductionFailure Pattern:
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IntroductionIntroduction
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IntroductionIntroduction
Beam with Reinforcement
Reinforcement
Beam
Longitudinal Section
Composite Section
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Normal Stress Formula Normal Stress Formula DerivationDerivation
The fundamental concepts of stress can be illustrated by considering a prismatic bar that is loaded by axial forces P at the ends, as shown in Figure 1 prismatic bar having constant cross section throughout its length. The axial forces produce a uniform stretching of the bar; hence, the bar is said to be in tension.
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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Normal Stress Formula Normal Stress Formula DerivationDerivation
Area 1Area 2
Area 1>Area 2
Non prismatic X-Section
Prismatic and Non Prismatic Bar
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Normal Stress Formula Normal Stress Formula DerivationDerivation
Prismatic X-Section
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Normal Stress Formula Normal Stress Formula DerivationDerivation
• To investigate the internal stresses produced in the bar by the axial forces, we make an imaginary cut at section aa (Figure 1).
• The intensity of force (that is, the force per unit area) is called the stress and is commonly denoted by the Greek letter s (sigma).
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Normal Stress Formula Normal Stress Formula DerivationDerivation
• The intensity of force (that is, the force per unit area) is called the stress and is commonly denoted by the Greek letter s (sigma).
• Assuming that the stress has a uniform distribution over the cross section (see Figure 1), we can readily see that its resultant is equal to the intensity s times the cross-sectional area A of the bar.
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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Normal Stress Formula Normal Stress Formula DerivationDerivation
• Furthermore, from the equilibrium (balancing of forces) of the body shown in Figure 1, it is also evident that this resultant must be equal in magnitude and opposite in direction to the applied load P. Hence, we obtain
A
P
Instructor: Prof: Dr.Akhtar Naeem Lecturer: Engr Muhammad
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Normal Stress Formula Normal Stress Formula DerivationDerivation
• When a sign convention for normal stresses is required, it is customary to define tensile stresses as positive (+) and compressive stresses as negative (-).
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Normal Stress Formula Normal Stress Formula DerivationDerivation
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Normal Stress Formula Normal Stress Formula DerivationDerivation
Tensile Normal StressTensile Normal Force