mechanics of materials - university of pittsburghqiw4/academic/mems1082/chapter3-1 diode.pdf ·...
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MEMS1082
MechatronicsChapter 3-1 Semiconductor devices
Diode
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Semiconductor: Si
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Semiconductor
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N-type and P-type SemiconductorsThere are two types of impurities: N-type - In N-type doping, phosphorus or arsenic is added to the silicon in small quantities. Phosphorus and arsenic each have five outer electrons, so they're out of place when they get into the silicon lattice. The fifth electron has nothing to bond to, so it's free to move around. It takes only a very small quantity of the impurity to create enough free electrons to allow an electric current to flow through the silicon. N-type silicon is a good conductor. Electrons have a negative charge, hence the name N-type. P-type - In P-type doping, boron or gallium is the dopant. Boron and gallium each have only three outer electrons. When mixed into the silicon lattice, they form "holes" in the lattice where a silicon electron has nothing to bond to. The absence of an electron creates the effect of a positive charge, hence the name P-type. Holes can conduct current. A hole happily accepts an electron from a neighbor, moving the hole over a space. P-type silicon is a good conductor.
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N-type and P-type Semiconductors
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Semiconductor device-diodeA diode is the simplest possible semiconductor device. A diode allows current to flow in one direction but not the other. You may have seen turnstiles at a stadium or a subway station that let people go through in only one direction. A diode is a one-way turnstile for electrons.
When you put N-type and P-type silicon together as shown in this diagram, you get a very interesting phenomenon that gives a diode its unique properties.
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Diodes
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Diode
Electron flow direction
Current direction
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Diode depletion region
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pn junction
PN Junction
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Diode depletion region
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Diode forward and reverse bias
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Shockley diode equation
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Diode current and voltage
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Diode Characteristic
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Diode Characteristic
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Diode Characteristic at different scale
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Diode Characteristic at different scale
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Diode measurementMeter with a
“Diode check” function displays the forward voltage drop of 0.548 volts instead of a low resistance
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Measurement of a diodeMeasuring forward voltage of a diode without “diode check” meter function: (a) Schematic diagram. (b) Pictorial diagram
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Load line of diode A circuit with a diode
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Example For circuit, determine the current i
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Example Circuit
reduction to Théveninequivalent circuit
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Example Thévenin equivalent circuit
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Example Draw load line
to determine the diode voltage and current
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Example Determine current i
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Example Determine the current and voltage of the diode in the
circuit. The diode characteristic is given in the right figure.
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Example
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Piecewise-linear approximation and small signal analysis Diode is nonlinear resistor
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Piecewise-linear approximation and small signal analysis Diode piecewise-linear approximation
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Piecewise-linear approximation and small signal analysis
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Piecewise-linear approximation and small signal analysis
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Piecewise-linear approximation and small signal analysis
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Piecewise-linear approximation and small signal analysis Small signal analysis
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Piecewise-linear approximation and small signal analysis Small signal analysis
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Piecewise-linear approximation and small signal analysis If we are only interested in the portion due to vs(t), we may
set Es=0, and Ef =0, then
Often, for practical purpose, we can assume Ef =0 in small signal equivalent circuit of a diode. For typical diodes, the value of Rf is quite small, between 1Ω and 100Ω. Thus Rfcan be neglected.
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Piecewise-linear approximation and small signal analysis
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The ideal diodes
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The piecewise- linear model of a diode, using an ideal diode
Ideal diode
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Example Nonlinear resistors with a wide range of characteristics can be
obtained, approximately, with circuit containing diodes, for example, a square-law device is two-terminal nonlinear resistor whose terminal voltage-current characteristic obeywhere k is normalization constant. The ideal characteristic is shown
2kvi =
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Example This device may be used in modulator, e.g., to attain a voice
signal to high-frequency carrier wave, as is done in amplitude modulation (AM) radio transmission. Design a square-law device to approximate the ideal characteristics for
with a normalization constant k=0.001Vv 50 ≤≤
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Example A circuit using ideal diodes D1 and D2
and voltage sources E1 and E2
Use V=5V; E1 < E2
Initially 0≤v≤ E1,the diodes are reverse biased and open, the curve will have slope 1/R3
For E1 ≤v≤ E2,D1 closes, and D2 open, the input resistance will be R3llR1
For E2 ≤v≤ 5V,D1 and D2 close, the input resistance will be R3llR1llR2
Suppose E1 =2.0V and E2=3.5V
mAkEI 4211 ==
mAkEI 25.12222 ==
mAkVI 252 ==
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Example Noting the slope of each portion, we obtain
Ω== 5001
13 I
ER Ω=−−
= 18212
1221 II
EERR Ω= 2861R
Ω=−−
= 1182
2321 II
EVRRR Ω= 3332R
Replacing the actual diode with their piecewise-linear approximation using
VER ff 5.0,10 =Ω=
Ω= 5003RΩ= 2761R Ω= 3232R
E1 =1.5V and E2=3.0V
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Ideal transformer
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Rectifiers
Half-Wave Rectifier The transformer isolates the load from the source
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Rectifiers
Half-Wave Rectifier
πωππωω20
0sin≤≤=≤≤=tv
ttVv
L
sL
( )
π
ωωπ
π
s
sL
V
tdtVV
=
= ∫0 sin21
The average dc value of vL
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Rectifiers Representing the Half-Wave Rectifier voltage by Fourier series
.........2coscos......2sinsin 2121 ++++++= tbtbtataVv LL ωωωω
The Fourier coefficients can be determined as
( ) ( ) dttntvT
bdttntvT
aT
Ln
T
Ln ωω cos2;sin200 ∫∫ ==
( ) ( )2
sinsin1sin2001
ss
T
LVtdttVdtttv
Ta === ∫∫ ωωω
πω
π
For the Half-Wave Rectified voltage
( ) ( ) 0sinsin1sin200
=== ∫∫ tdtntVdttntvT
a s
T
Ln ωωωπ
ωπ
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Rectifiers
0;152;0,
32;0 54321 =−==−== bVbbVbb ss
ππ
Thus the Fourier series for the Half-Wave Rectified signal
( ) .....4cos1522cos
32sin
2+−−+= tVtVtVVtv ssss
L ωπ
ωπ
ωπ
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Rectifiers Filtering the Half-Wave Rectifier
Capacitor has lower impedance to higher frequencies
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Rectifiers Filtering the Half-Wave Rectifier
Larger C can be used to increase the time constant RC
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Rectifiers Effects of actual diodes
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Rectifiers Effects of actual diodes
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The Full-Wave Rectifiers The full-wave rectifier
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The Full-Wave Rectifiers The full-wave rectifier
( )
π
ωωπ
π
s
sL
V
tdtVV
2
sin10
=
= ∫
The average dc value of vL
Thus the Fourier series for the Full-Wave Rectified signal
( ) .....4cos1542cos
342
+−−= tVtVVtv sssL ω
πω
ππ
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The Full-Wave Rectifiers Effect of actual diodes
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The Full-Wave Bridge Rectifier A bridge rectifier makes use of four diodes in a bridge
arrangement to achieve full-wave rectification. This is a widely used configuration, both with individual diodes wired as shown and with single component bridges where the diode bridge is wired internally.
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Bridge Rectifiers
Various types of Bridge RectifiersNote that some have a hole through
their centre for attaching to a heat sink
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The Full-Wave Bridge Rectifier Bridge Rectifier
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The Full-Wave Bridge Rectifier Bridge Rectifier with RC Filter and LC filter
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The Voltage Limiter Limiter using ideal diodes and batteries
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The Voltage Limiter Limiter using ideal diodes and batteries
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The Voltage Limiter Limiter using ideal diode and batteries
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The Voltage Limiter Limiter using ideal diode and batteries
( ) 12 VR
RRtvVR
RR
L
sLs
L
sL +<<
+−
Load voltage is limited for source voltage
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The Voltage Limiter Limiter using ideal diode and batteries
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Example For a limiter shown below, assume identical piecewise-
linear diodes with Rf=100Ω, Ef=0.5V, V1=V2=10V, RL=100Ω, Rs=100Ω, and vs(t)=50sinωt V, sketch vL(t)
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Zener Diodes A Zener diode is a type of
diode that permits current not only in the forward direction like a normal diode, but also in the reverse direction if the voltage is larger than the breakdown voltage known as "Zener knee voltage" or "Zener voltage". The device was named after Clarence Zener, who discovered this electrical property.
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Zener Diodes Piecewise-linear
characteristic Device characteristic
of Zener diode
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Zener Diodes Piecewise-linear model
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Zener Diode Regulator In this circuit, a typical voltage
reference or regulator, an input voltage, UIN, is regulated down to a stable output voltage UOUT. The intrinsic voltage drop of diode D is stable over a wide current range and holds UOUTrelatively constant even though the input voltage may fluctuate over a fairly wide range. Because of the low impedance of the diode when operated like this, Resistor R is used to limit current through the circuit.
IDiode = (UIN - UOUT) / R
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Zener Diode Regulator R must be small enough that the current through D keeps D in reverse breakdown. The value of this current is given in the data sheet for D. For example, the common BZX79C5V6 device, a 5.6 V 0.5 W Zener diode, has a recommended reverse current of 5 mA. If insufficient current exists through D, then UOUT will be unregulated, and less than the nominal breakdown voltage. When calculating R, allowance must be made for any current through the external load, not shown in this diagram, connected across UOUT.
R must be large enough that the current through D does not destroy the device. If the current through D is ID, its breakdown voltage VB and its maximum power dissipation PMAX, then IDVB < PMAX.
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Zener Diode regulator
L
z
zs
zs
RV
VP
RRVV
I +=+−
= max
min
max,max
L
z
s
zs
RV
RRVV
I =+−
=max
min,min
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Example
ARV
RVV
VPI
L
zzs
z
18.0max,maxmax =−
−==
Ω=−
= 250min
min,max I
VVR zs
A source voltage varies between 120V and 75V. The source resistance is zero, and the load resistance is 1kΩ. It is desired to maintain the load voltage at 60V. Determine the value of a regulator resistor R that will accomplish this and the required power rating of the zener.
1. A zener having a zener voltage of 60V is selected2. The maximum value of regulator resistance
mARVI
L
z 601000
60min ===
3. The power rating is determined when Vs=Vs,max. And zener draw the maximum current
WP 8.10max =
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Light Emitting Diode
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Light Emitting DiodeAn LED will begin to emit light when the on-voltage is exceeded. Typical on voltages are 2–3 volts
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Connect Light Emitting Diode in Series
Connecting LEDs in seriesIf you wish to have several LEDs on at the same time it may be possible to connect them in series. This prolongs battery life by lighting several LEDs with the same current as just one LED. All the LEDs connected in series pass the same current so it is best if they are all the same type. The power supply must have sufficient voltage to provide about 2V for each LED (4V for blue and white) plus at least another 2V for the resistor. To work out a value for the resistor you must add up all the LED voltages and use this for VL.
Example calculations: A red, a yellow and a green LED in series need a supply voltage of at least 3 × 2V + 2V = 8V, so a 9V battery would be ideal. VL = 2V + 2V + 2V = 6V (the three LED voltages added up). If the supply voltage VS is 9V and the current I must be 15mA = 0.015A, Resistor R = (VS - VL) / I = (9 - 6) / 0.015 = 3 / 0.015 = 200, so choose R = 220 (the nearest standard value which is greater).