mech 360 final exam study guide (version #2)
DESCRIPTION
Solid Mechanics study guide.TRANSCRIPT
Mechanics of Materials Formula and Data Sheet
Some Engineering Material Properties:
Property Steel Aluminum Brass
Young’s Modulus, E 210 GPa (30 psi x 106) 70 GPa (10 psi x 10
6) 105 GPa (15 psi x 10
6)
Shear Modulus, G 81 GPa (11.6 psi x 106) 26 GPa (3.7 psi x 10
6) 39 GPa (5.6 psi x 10
6)
Poisson’s Ratio, Ȟ 0.30 0.33 0.35
Thermal Expansion, Į 11x10-6
/ºC (6x10-6
º/F) 22x10-6
/ºC (12x10-6
º/F) 20x10-6
/ºC (11x10-6
º/F)
Density, ȡ 7850 kg/m3 (0.28 lb/in
3) 2720 kg/m
3 (0.10 lb/in
3) 8410 kg/m
3 (0.30 lb/in
3)
Moments of Area for Common Shapes:
Shape Cross-section A Ix Iy J = Ix + Iy
solid circle ʌ c2 ʌ c
4 / 4 ʌ c
4 / 4 ʌ c
4 / 2
thin-wall circle 2 ʌ t c ʌ t c3 ʌ t c
32 ʌ t c
3
solid rectangle b h b h3 / 12 h b
3 / 12 b h (b
2 + h
2) / 12
Elastic relationships:
T E
E
E
zyx
x 'D�V
Q�V
Q�V
H G
W
J )2(1
E G
Q�
)2-3(1
E K
Q
Failure Criteria: (for principal stresses ı1 � ı2 � ı3)
Tresca: ı1 – ı3 = ıY Mises: (ı1 – ı2)2 + (ı2 – ı3)
2 + (ı3 – ı1)
2 = 2ıY
2 Mohr: ı1/ıUT – ı3/ıUC = 1
Thin-Walled Pressure Vessels:
0 t2
R p
t
R p :Cylinder ra |V V VT 0
t2
R p :Sphere ra |V V VT
Shaft Torsion: Beam Bending: Parallel Axis Theorem:
L
G
J
T
r
I
W
R
E
I
M
Y
�V
2
0 dA I I(d) �
Power Transmission:
c
J f 2ʌ P
maxW watts (metric units)
c
J rpm 1015.87 P
max-6 Wu
h.p. (lb.in units)
Beam Formulas:
xd
M d V
xd
V d w
EI
M
dx
yd
2
2
³ dAy Q whereI
Q V
I
yVA q
< x – a > = ( x – a ) if x – a > 0, = 0 if x – a � 0
Some Typical I-Beams:
Mohr’s Circle:
ı
IJ ıy, IJyx
ıx, IJxy
ıy
IJxy
ıx
IJyx
Use sign convention “in the kitchen, the clock is above and the counter is below” for the shear stresses.
Then, rotations in the Mohr’s circle have the same direction and double the rotation angle of the physical
stresses. For Mohr’s circle of strain, use İ and Ȗ/2 in place of ı and IJ.
Column Buckling:
2
e
2
2
e
2
CR)r/(L
EA
L
EI P
S
S
where: Le = L (pinned-pinned) Le = 2 L (free-fixed)
Le = 0.7 L (pinned-fixed) Le = 0.5 L (sliding-fixed)
¸¸¹
·¨¨©
§�¸
¸¹
·¨¨©
§ S 1
P
P
2 sec e y :load Eccentric
CR
max
P P
P a y :curvature Initial
CR
max �
For “short” columns:
2
e
2
2
Y
YCR
Y
2
e
r
L
E4
E2
r
L¸¹·
¨©§¸¸¹
·¨¨©
§
SV
�V VVS
�
Strain Energy:
dx 2EA
P U:rod
2
³ dx 2EI
M U:beam
2
³ dx 2GJ
T U:shaft
2
³
Castigliano’s Theorem:
j
jP
U ww
G
j
jM
U ww
T dx P
P
EA
P :rod
j
j ww
G ³ dx P
M
EI
M :beam
j
j ww
G ³
UI
i
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