me804306-2 fluid mechanics chapter 2 fluid statics dr. kamel mohamed guedri mechanical engineering...

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ME804306-2 Fluid Mechanics Chapter 2 Fluid Statics Dr. Kamel Mohamed Guedri Mechanical Engineering Department, The College of Engineering and Islamic Architecture, Umm Al-Qura University, Room H1091 Website: https://uqu.edu.sa/kmguedri Email: [email protected]

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ME804306-2Fluid Mechanics

Chapter 2

Fluid Statics

Dr. Kamel Mohamed Guedri

Mechanical Engineering Department,The College of Engineering and Islamic Architecture,

Umm Al-Qura University, Room H1091

Website: https://uqu.edu.sa/kmguedriEmail: [email protected]

Objectives

• Determine the variation of pressure in a fluid at rest

• Calculate pressure using various kinds of manometers

• Calculate the forces exerted by a fluid at rest on plane

or curved submerged surfaces.

• Analyze the stability of floating and submerged

bodies.

• Analyze the rigid-body motion of fluids in containers

during linear acceleration or rotation.

OUTLINE

1. Absolute and gauge pressure2. Basic Equation of Fluid Statics3. Pressure - Depth Relationships

a) Constant density fluidsb) Ideal gases

4. Pressure measurement devicesa) The barometreb) The manometersb) Other pressure measurement devices

5. Hydrostatic forces on submerged plane surfaces6. Hydrostatic forces on submerged curved surfaces7. Buoyancy and stability8. Fluid in rigid-body in motion

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2.1 Absolute and Gauge Pressure• Pressure measurements are generally indicated as

being either absolute or gauge pressure.

• Gauge pressure

• is the pressure measured above or below the atmospheric pressure (i.e. taking the atmospheric as datum).

• can be positive or negative. • A negative gauge pressure is also known as vacuum

pressure.

• Absolute pressure

• uses absolute zero, which is the lowest possible pressure.

• Therefore, an absolute pressure will always be positive.

• A simple equation relating the two pressure measuring system can be written as:

• Pabs = Pgauge + Patm (2.2)

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•Atmospheric pressure• refers to the prevailing pressure in the air around

us.

• It varies somewhat with changing weather conditions, and it decreases with increasing altitude.

• At sea level, average atmospheric pressure is 101.3 kPa (abs), 14.7 psi (abs), or 1 atmosphere (1 bar = 1x105 Pa).

• This is commonly referred to as ‘standard atmospheric pressure’.

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Example 2.1 Express a pressure of 155 kPa (gauge) as an absolute

pressure. Express a pressure of –31 kPa (gauge) as an absolute

pressure. The local atmospheric pressure is 101 kPa (abs).

• Solution:

Pabs = Pgauge + Patm

Pabs = 155 + 101 = 256 kPa

Pabs = -31 + 101 = 70 kPa

2.2 Basic Equation of Fluid Statics

The pressure at a point in a static fluid is the same in all directions. What this means that the pressure on the small cube in Figure 2.1 is the numerically the same on each face as the cube shrinks to zero volume. At the surface, the pressure is zero gage. Since depth increases in the downward z-direction, the sign on the specific weight in equation 2.1 is negative.

2.3 Pressure - Depth Relationships

2.3.1 Constant Density Fluids

To establish the relationship between pressure and depth for a constant density fluid, the pressure - position relationship must be separated and integrated

Equation 2.3 is one of the most important and useful equations in fluid statics.

Figure below shows a tank

with one side open to the

atmosphere and the other

side sealed with air above

the oil (SG=0.90).

Calculate the gauge

pressure at points

A,B,C,D,E.

Example 2.2

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Solution:

• At point A, the oil is exposed to the atmosphereThus PA=Patm = 0 (gauge)

• Point B is 3 m below point A, Thus PB = PA + oilgh

= 0 + 0.9x1000x9.81x3= 26.5 kPa (gauge)

• Point C is 5 m below point A, Thus PC = PA + oilgh

= 0 + 0.9x1000x9.81x5= 44.15 kPa (gauge)

• Point D is at the same level of point B,Thus PD = PB

= 26.5 kPa (gauge)• Point E is higher by 1 m from point A,

Thus PE = PA - oilgh= 0 - 0.9x1000x9.81x1= -8.83 kPa (gauge).

2.3.2 Variable Density Fluids

Most fluids are relatively incompressible, but gases are not. This means that the density increases with depth so we cannot use the specific weight as a constant in determining the pressure. If we assume an ideal gas, then the density is given by

where M is the molecular weight, T is the absolute temperature, and R is the gas constant in appropriate units.Replacing in the differential equation (2.1) we get

2.4. Pressure measurement devices

Example 2.3

Example 2.4

Example 2.5

2.5. Hydrostatic forces on submerged plane surfaces

Example 2.6

2.6. Hydrostatic forces on submerged curved surfaces

Example 2.7

below.

2.7

2.7. Buoyancy and stability

Example 2.8

2.8. Fluid in rigid-body motion

Example 2.9